Lesson 2
1. Lesson 2
1.8. Explore 4
Module 3: Quadratic Functions
Example 1: Formulating a Quadratic Equation from a Graph
In Try This 3 you sketched a graph from an equation. Now you will do the opposite—you will formulate a quadratic equation from a graph.
Question
What quadratic function describes the parabola on the grid below?
Solution
Step 1: Find the variables p and q. Since the vertex coordinates are (p, q), you can read the coordinates of the vertex of the parabola from the graph as (−5, −4).
Step 2: Substitute p and q into the quadratic function equation.
Step 3: Find the value of a. The graph opens upward, so you know the value of a is positive. You can pick another point on the graph and substitute its coordinates into the function to solve for a. An easy point is the y-intercept, which is at (0, 1).
Step 4: Substitute in the variables. Put the found values of a, p, and q into the equation for a quadratic function.
y = 0.2(x + 5)2 − 4
Step 5: Verify the equation. Verify the equation by substituting the coordinates of a second point into the equation and see if the equation is true. For example, a second point shown on the parabola is (−1, −0.8). The left side equals the right side, so the equation has been verified.
Left Side | Right Side |
(4)2y (4)2−0.8 (4)2−0.8 (4)2−0.8 −0.8 −0.8 |
0.2(x + 5)2 − 4 0.2((−1) + 5)2 − 4 0.2(4)2 − 4 0.2(16) − 4 3.2 − 4 −0.8 |
Self-Check 3
- What quadratic function describes the parabola on the grid shown?
Answer
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What quadratic function describes a parabola with the following characteristics?
- The parabola opens downward.
- The vertex of the parabola is at (4, 6).
- There are two x-intercepts. One is at (6, 0) and the other is at (2, 0).
- The y-intercept is at (0, −18).