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Lesson 1

1. Lesson 1

1.5. Discover 2

Mathematics 20-1 Module 4

Module 4: Quadratic Equations and Inequalities

 

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With a classmate, compare your responses to Try This 1. Discuss and resolve any differences in your answers. Then work together on the following questions.

  1. Compare the function h(t) = −1.42t2 + 3.75t + 1.53 to the equation 0 = −1.42t2 + 3.75t + 1.53. How could you use the graph of h(t) = −1.42t2 + 3.75t + 1.53 to determine the solution(s) to the equation?

  2. Consider the equation 3 = −1.42t2 + 3.75t + 1.53. What would be the meaning of this equation in the context of the problem? How could you use the graph to find the solutions to this problem?

course folder Save your work in your course folder. You will revisit these ideas later in the lesson.

In the equation 3 = −1.42t2 + 3.75t + 1.53, h is now equal to 3. What is y in the context of this problem?
In the equation 0 = −1.42t2 + 3.75t + 1.53, h is equal to 0. Think about where on the graph this occurs.