Module 6 Intro

1. Module 6 Intro

1.23. Page 2

Lesson 4

Module 6—Stoichiometry

Explore

 

Read

 

A photograph of different kinds of glassware used in a chemistry laboratory.

© Elemental Imaging/shutterstock

As you learned in Module 5, quantitative aspects of a solution include the concentration of solute and volume of solution. Can you recall a relationship that exists between a solution’s concentration, its volume, and the number of moles of solute it contains? What might be similar about how you would use this relationship and how you have used other relationships, such as and PV = nRT, during your study in this module?

 

Read “7.4 Solution Stoichiometry” on pages 300 to 302 of your textbook. Work through “SAMPLE problem 7.4” and the “COMMUNICATION example.”

 

Discuss

 

Look at the “Stoichiometry Calculations” in the margin on page 302 of your textbook. Construct a flow chart that outlines the steps involved in stoichiometry calculations. The flow chart should summarize the use of the formulas you have used to perform calculations regardless of whether the known or desired substance in a reaction is a solid, gas, or part of a solution.

 

Post your flow chart to the discussion board for your class. Read and comment on the postings from two other students. Revise your flow chart using the comments relayed to you from your classmates. Place a copy of your finished product in your course folder and submit a copy to your teacher.

 

Self-Check

 

Complete “Practice” questions 1 to 3 on page 302 of your textbook.

 

Check your work.
Self-Check Answers

 

“Practice” questions 1 to 3, page 302


  1. H2SO4(aq)

    +

    2 NH3(aq)

    (NH4)2SO4(aq)

     

     

     






    The concentration of the sulfuric acid solution is 0.537 mol/L.


  2. 3 Ca(OH)2(aq)

    +

    Al2SO4(aq)

    3 CaSO4(s)

    +

    2 Al(OH)3(s)

    c = 0.0250 mol/L
    V = ?

     

     

     

     

     






    The volume of the calcium hydroxide solution required is 375 mL.


  3. 2 FeCl3(aq)

    +

    3 Na2CO3(aq)

    6 NaCl(aq)

    +

    Fe2(CO3)3(s)

     

    c = 0.250 mol/L
    V = ?

     

     

     

     






    The volume of the sodium carbonate solution required is 90.0 mL.