Module 5

1. Module 5

1.19. Page 2

Lesson 4

Module 5—Wave Theory of Light

 

Explore

 

A ray diagram shows partial refraction and reflection. The diagram represents a straw in a glass of water, with water at the bottom half of the image and air at the top. A broken diagonal line passes from the top left, in the air, to the bottom right, in the water. At the point where the line intersects the surface of the water, its angle changes. The incident and refracted angles are shown.

Refraction is a change in the direction of a light wave caused by a change in its speed as the light wave passes at an angle from one medium to the next. In the ray diagram example, a light ray is incident on the surface of water. Some of the light is reflected and some of the light slows down as it enters the water and is refracted.

 

According to the law of reflection, the angle of reflection is identical to the angle of incidence.

 

The angle of refraction, however, is not the same as the angle of incidence. It is determined by Snell’s Law. The simplest way to write Snell’s Law is as follows:

 

, where n is the index of refraction

 

The simple form of Snell’s Law assumes that the medium the light is leaving is air. The refractive index of air is 1.0003, which is close to, and usually assumed to be the same as, the refractive index of a vacuum (n = 1.000). This is true because the speed of light in air is nearly identical to its speed in a vacuum so, as it passes from air into a vacuum, it is only refracted by a very small amount, making the ratio of the  equal to 1. The amount of refraction in other materials, as light enters them from air or a vacuum, is much more and leads to higher indexes of refraction. Therefore, the index of refraction is a relative measure of how much the light changes speed and is bent as it moves between two mediums.

 

refraction: a change in the direction of a wave due to a change in its speed

 

Snell’s Law: for any angle of incidence greater than zero, the ratio of

 

 

refractive index: a ratio comparing the speed of light in a vacuum to its speed in a given medium

Table 1: Absolute Refractive Indexes of Some Common Materials

 

Medium

Index of Refraction

vacuum

1.0000

air

1.0003

ice

1.31

water

1.33

quartz glass

1.47

crown glass

1.52

lucite (plexiglass)

1.52

diamond

2.42

 

Try This

 

TR 1. Based on Table 1, in which medium is light most refracted as it enters the medium from air?

 

A useful rule of thumb to remember concerns how light bends as it either enters a region of increased refractive index or vice versa. You can discover this rule using this Light Refraction simulation.

 

Once the simulation is open, do the following:

  • Click the “Add” button (). This will add a second medium to the display window (medium 1 and medium 2), both with a refractive index (n) = 1.0.

  • Double-click anywhere in the bottom layer and enter the refractive index (n) of water 1.33.

  • Click and drag the laser into the top layer. Next, click the tip of the laser and point it down into the water layer. Vary the angle of the beam by adjusting the laser’s direction. Note the way in which the light bends as it enters the denser (water) layer. (Toward or away from the normal?)

  • Move the laser pointer to the water layer and point it upward into the air layer. Vary the angle and note the way in which the light bends as it enters the rarer (air) layer. (Toward or away from the normal?)
A ray diagram shows the angle of incidence and the angle of refraction.
Module 5: Lesson 4 Assignment

 

Remember to submit your answers to LAB 1 to your teacher as part of your Module 5: Lesson 4 Assignment. 

 

LAB 1. Use the Light Refraction simulation to determine the answer to the following two questions:

  1. When light travels from a low-index medium (fast) into a high-index medium (slower), does the ray bend toward or away from the normal?
  1. When light travels from a high-index (slower) medium into a low-index (fast) medium, does the light ray bend toward or away from the normal?
Self-Check

 

SC 1. A laser is directed into a pool of water (nwater = 1.33). The beam contacts the air-water interface with an angle of incidence equal to 35.0°. Using the simple form of Snell’s Law, calculate the angle of refraction (relative to the normal) with which it travels through the water. Show your calculations and label the ray diagram showing the angle of incidence and angle of refraction. Verify your answer using the Light Refraction simulation.

 

Check your work.
Self-Check Answers

 

Contact your teacher if your answers vary significantly from the answers provided here.

 

SC 1.

 

Given

 

 

Required

 

the angle of refraction, n2

 

Analysis and Solution

A ray diagram shows an incident light ray at 35 degrees and a refracted light ray at 25.5 degrees in a representation similar to the previous one in which the diagonal line entered the water.

 

 

Paraphrase

 

The angle of refraction is 25.5°.

 

 

A More General Form of Snell’s Law

 

The general form of Snell’s Law is used to describe the change in direction of light when it moves between any two media and not just out of air. The Light Rerfraction simulation will be used to determine the general form of Snell’s Law.

 

Module 5: Lesson 4 Assignment

 

Remember to submit your answer to LAB 2 to your teacher as part of your Module 5: Lesson 4 Assignment. 

 

LAB 2. Set up the Light Refraction simulation with two refractive layers. You will need to vary the refractive index for each layer and the angle of the light ray in order to complete Table 2. Select "Show Calcs" () to assist in recording angles. Get as close to the θin as you can, but record the actual value that you use.

 

Table 2: Refraction Data

 

n1

θin

n1sinθin

n2

θout

n2sinθout

1.20

45°

 

1.40

 

 

1.30

32°

 

1.66

 

 

1.45

45°

 

1.23

 

 

1.51

40°

 

1.00

 

 

1.65

45°

 

1.80

 

 

 

According to your data in Table 2, which two values are always equal to one another?

 

Snell’s Law: The general form of Snell’s Law relates the ratio of the indexes of refraction to the ratio of the sine of the angles of incidence and refraction.

 

Expressed as an equation,

 

 

Quantity Symbol SI Unit
refractive index of the first medium n1 coefficient (no units)
refractive index of the second medium n2 coefficient (no units)
angle of incident (measured from the normal) θ1 degrees
angle of refraction (measured from the normal) θ2 degrees

 


 

Try This

 

TR 2. Snell’s Law may also be written as n1sinθ1 = n2sinθ2. Does the data collected in Table 2 support the general form of Snell’s Law? Explain and provide two sample calculations to support your explanation.

 

Self-Check

 

SC 2. A laser is submerged in oil (noil = 1.48) and directed into a pool of water (nwater = 1.33) with an angle of incidence equal to 35.0°. Calculate the angle of refraction. Show your calculations and use the Light Refraction simulation to verify your answer.

 

Check your work.
Self-Check Answers

 

Contact your teacher if your answers vary significantly from the answers provided here.

 

SC 2. 


Given

 

 

Required

 

the angle of refraction, θ2

 

Analysis and Solution

 

 

Paraphrase

 

The angle of refraction is 39.7°.

 

 

Try This

 

TR 3. Complete “Practice Problems" 1–4 on page 668 of your textbook.

 

Snell’s Law can be expanded when you consider light as a transverse wave. In the expanded form, frequency, wavelength, and speed are related according to the following equation:

 

Read

 

Read “Snell’s Law, Refraction, and Wavelength” on pages 669–670 for a derivation of this equation based on the transverse wave model of EMR.

 

Try This

 

TR 4. Complete “Practice Problems” 1(a), 1(b), 2, and 3 on page 670 of your textbook. Note: Index of refraction values are given on page 667.