Lesson 7

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Course: Math 20-2 SS
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Date: Saturday, 6 September 2025, 2:32 AM

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1. Lesson 7

Mathematics 20-2 M3 Lesson 7

Module 3: Quadratics

 

Lesson 7: Solving Quadratic Equations by Factoring or Graphing

 
Focus

 

This is a photo of parabolic satellite dishes.

iStockphoto/Thinkstock

Parabolic reflectors, whose shape can be modelled by quadratic functions, often receive radio waves from outer space. In the Very Large Array, 27 radio antennas on rails sit on the Plains of San Agustin, 50 miles west of Socorro, New Mexico. Each antenna is 25 m (the height of an eight-storey building) in diameter and weighs 209 t (tonnes). The data from the antennas is combined electronically to give the resolution of an antenna 36 km across and the sensitivity of a dish 130 m in diameter.

 

As you progress through this lesson, you will analyze parabolic shapes in sports and communications. You will learn how to use the zeros of a quadratic function to solve corresponding equations and answer related problems.

 

Lesson Questions
 

This lesson will help you answer the following inquiry questions:

  • How can you use a quadratic equation in factored form to solve problems involving the zeros of the corresponding quadratic function or the x-intercepts of the graph of the function?

  • How can you find the roots of a quadratic equation by graphing the corresponding quadratic function?
Assessment

All assessment items you encounter need to be placed in your course folder.

 

course folder

Save a copy of the Lesson 7 Assignment to your course folder. You will receive more information about how to complete the assignment later in this lesson.

 


Materials and Equipment
  • graphing calculator

1.1. Launch

Mathematics 20-2 M3 Lesson 7

Module 3: Quadratics

 
Launch
 

Before beginning this lesson, you should be able to

  • factor and solve quadratic equations

  • graph quadratic functions and find zeros using your graphing calculator

 

1.2. Are You Ready?

Mathematics 20-2 M3 Lesson 7

Module 3: Quadratics

 
Are You Ready?
  1. Solve each of the following quadratic equations using factoring.

    1. x2 + 5x + 4 = 0 Answer

    2. 2x2 + 4x − 30 = 0 Answer

    3. y2 − 16 = 0 Answer

    4. −5y2 + 125 = 0 Answer

    5. 2x2 + 5x − 3 = 0 Answer

  2. Using your calculator, graph and find the zeros of the following quadratic functions.

    1. f(x) = x2x − 6 Answer

    2. f(x) = 3x2 + x − 2 Answer

    3. f(x) = x2 + 6x + 9 Answer

If you successfully completed the Are You Ready? questions, move on to the Discover section of the lesson.

 

If you experienced difficulties with the questions, use the resources in the Refresher section to review the concepts before continuing through the lesson.

 

 

1.3. Refresher

Mathematics 20-2 M3 Lesson 7

Module 3: Quadratics

 
Refresher
 

Review the following examples to see how to factor quadratic equations. Once you have reviewed some examples, try some questions to make sure you understand the concepts provided here.

 

Example 1

 

x2 + 5x + 4 = 0

 

Since 1 and 4 have a sum of 5 and a product of 4, x2 + 5x + 4 = 0 is the same as

 

 

 

Example 2

 

x2 − 9x + 20 = 0

 

Since −4 and −5 have a sum of −9 and a product of 20, x2 − 9x + 20 = 0 is the same as

 

 

 

Example 3

 

x2 − 4x − 32 = 0

 

Since 4 and −8 have a sum of −4 and a product of −32, x2 − 4x − 32 = 0 is the same as

 

 

 

Example 4

 

2x2 + 4x − 30 = 0

 

The equation has a common factor of 2.

 

 

2(x2 + 2x − 15) = 0

 

Since −3 and 5 have a sum of 2 and product of −15, 2(x2 + 2x − 15) = 0 is the same as

 

 

 

Example 5

 

y2 − 16 = 0

 

Since both terms on the left side are squares, this is a difference of squares (16 = 42).

 

 

 

Example 6

 

−5y2 + 125 = 0

 

The equation has a common factor of −5.

 

 

−5(y2 − 25) = 0

 

Since both terms inside the brackets are squares, treat this like a difference of squares.

 

 

 

Example 7

 

x2 − 8x + 16 = 0

 

The equation has the form of a perfect square since −8x = 2(−4x) and 16 = (−4)2.

 

 


Now that you have had an opportunity to review some examples, solve the following factoring questions to ensure you understand the concepts presented here.

  1. 2x2 + 8x + 8 = 0 Answer

  2. 2x2 + 5x − 3 = 0 Answer

  3. 4x2 + 5x − 6 = 0 Answer

Go to How to Find Zeros, Minimums, and Maximums with Your Graphing Calculator to see directions for finding the zeros of a function for a graphing calculator. You may have to adapt the directions if you are using a calculator from a different manufacturer.

 

Go back to the Are You Ready? section, and try the questions again. If you are still having difficulty, contact your teacher.

 

What are the factors of −24 that have a sum of 5?
What are the factors of −6 that have a sum of 5?
This has a common factor of 2. The factor inside the brackets has the form for a perfect square.

 

1.4. Discover

Mathematics 20-2 M3 Lesson 7

Module 3: Quadratics

 
Discover
 

Try This 1 gives you a chance to play with the factored form of the quadratic function. The activity will let you see how the various parameters affect the shape of the function’s graph.

 

Try This 1
 

Use Polynomial Function Explorer to explore the factored form of the quadratic equation. Change the “Degree =” slider to 2 so you get a second-degree polynomial—a quadratic function. Choose “Show x-intercepts” by clicking on the square. Experiment with the b-slider to see how the slider changes the values in the factored form of the function, the intercepts, and the position of the graph.

 

 

This is a play button that opens Polynomial Function Explorer.

  1. When you are satisfied that you know what the b-slider does and how changing the value affects the graph, set the value of b to 4. Experiment with the k-slider to see how the value of k changes the function, the intercepts, and the position of the graph. How many different graphs are possible that have x-intercepts of 1 and 4?

  2. If you put k = 2, the graph passes through (5, 8). Can you make another graph with the x-intercepts of 1 and 4 that passes through (5, 8)? Move the k-slider and see if you can find one. What can you conclude about a graph where the x-intercepts and one other point are defined?
Share 1
 

assignment

Submit your work for Share 1 to your teacher for marking.

 

Based on your observations using Polynomial Function Explorer, discuss the following questions with another student or appropriate partner.

  • How many functions can have exactly the same x-intercepts?

  • One way to specify a particular function is to give the constants in the formula, such as f(x) = 2(x − 1)(x − 4). What is another way involving the x-intercepts?

Summarize your discussion by creating a short paragraph describing the answers to the questions that you and your partner agreed upon. (4 marks)

 

course folder Place a copy of this in your course folder for reference later in the course.

1.5. Explore

Mathematics 20-2 M3 Lesson 7

Module 3: Quadratics

 
Explore
 
This is a digital image of Earth sitting on top of a parabola.

Comstock/Thinkstock

You’ve just discovered some facts about quadratic functions. You’re now going to use this information and your knowledge of factoring to solve quadratic equation questions.

 

As you saw in Discover, it is straightforward to find the x-intercepts of a quadratic function in factored form. Is it as simple to find the factored form of a quadratic given its x-intercepts?

 

Suppose you are given a quadratic function with x-intercepts of x = −1 and x = 3. Write two quadratic functions that match this information.

 

Since you know that x = −1 and x = 3 are x-intercepts, you can find the (xr) and (xs) factors of f(x) = a(xr)(xs) quite easily.

 

 

 

The equations show that f(x) = a(x + 1)(x − 3) has the required x-intercepts.

 

To find more solutions, you can change the value of a. Options here are endless. You might choose 2 or or −3, giving the following functions with the same x-intercepts:

 

 

f(x) = 2(x2 − 2x − 3)

 

 

f(x) = (x2 − 2x − 3)

 

 

f(x) = −3(x2 − 2x − 3 )

 

The first two functions open upwards, and the third function opens downwards.

 

This photo shows a football player about to kick a football.

© Nicholas Piccillo/5526682/Fotolia

Self-Check 1
 

Suppose the height of a kicked ball is given as a function of distance, h = −0.0218d2 + 1.308d, where the distance and the height are in metres. How far will the ball go if it hits the ground before being caught? Answer

 

Solve by factoring. Factor the equation by dividing both terms by −0.0218.

 

1.6. Explore 2

Mathematics 20-2 M3 Lesson 7

Module 3: Quadratics

 
Manipulating Equations to Equal Zero
 

Quadratic equations may not always have one side equal to 0 (e.g., −6 = x2 + 5x). If you are working with a quadratic equation like this, you can manipulate the equation to get all non-zero terms on one side and 0 on the other side. Then you can use an appropriate factoring strategy to solve the equation.

 

For example, if you were asked to solve −6 = x2 + 5x, you might proceed as follows.

 

To move −6, add 6 to both sides.

 

 

 

You can now factor the right side of the equation.

 

 

 

Now you can find values for x easily.

 

 

So, x = −2 and x = −3 are the required solutions.

 

Self-Check 2
 

textbook

For more practice, complete “Check Your Understanding” questions 9 and 14 on pages 412 and 413 of the textbook. Answer

 

 

1.7. Explore 3

Mathematics 20-2 M3 Lesson 7

Module 3: Quadratics


Solving Equations Using Technology
 

In the next few activities you will use a graphing calculator or graphing technology to find the intercepts of a quadratic function or points of intersection of two functions.



textbook

Sometimes you will encounter a question in which the quadratic function is not written in standard, factored, or vertex form. In these cases, a graphing calculator can also be a great help. For examples that use a graphing calculator, see “Example 1: Verifying solutions to a quadratic equation” on pages 397 and 398 and “Example 3: Solving a quadratic equation in non-standard form” on page 401 of the textbook. The solution to “Example 1” finds the x-intercepts, whereas the solutions to “Example 3” are the x-coordinates of the points where the two graphs intersect.

 

Example 1: In the Cafeteria
 

A cafeteria owner is planning a new cafeteria in a local hospital. She believes that the monthly profit of a cafeteria can be modelled by the quadratic function P(x) = −0.25x2 + 17.5x + 1500, where x is the seating capacity and P(x) is the profit. How many seats would the cafeteria need in order to earn a monthly profit of $1700 or more?

 

Since you know that the owner is looking for a profit of at least $1700, replace P(x) with 1700.

 

 

1700 = −0.25x2 + 17.5x + 1500

 

Input the following values into your graphing calculator:

 

 

Y1 = 1700

 

 

Y2 = −0.25x2 + 17.5x + 1500

 

This is a screenshot of a graphing calculator.

 

Change the window settings to show the intersection points. Sometimes this takes a bit of trial and error.

 

This is a screenshot of a graphing calculator.

 

Now find the points of intersection using the CALCULATE feature (2nd and TRACE); choose option “5: Intersect” from the menu.

 

This is a screenshot of a graphing calculator. This is a screenshot of a graphing calculator.

 

There are two points of intersection: x = 14.38 and x = 55.6.

 

Since the problem is asking about seats in a cafeteria, fractional numbers don’t make sense. So, you would use x = 15 and x = 55 as your solutions.

 

The owner would earn a profit of $1700 starting at 14.38 seats; and she would earn $1700 or more until 55.6 seats were filled.

 

The answer to the question is, yes, she could earn a monthly profit of $1700 or more if between 15 and 55 seats were filled. Note: You would round up for 14.38 because 14 is not enough to get to the line and you would round down for 55.6 because the parabola is below the line after 56.

 

Example 2: Parabolic Reflectors
 

View The Structure of Parabolic Reflectors for an example of using a quadratic function to model an object.

 

 
This is a play button that opens The Structure of Parabolic Reflectors.

Photo: Hemera/Thinkstock


 

Self-Check 3

 

This photo shows a man passing a basketball.

© TheSupe87/17467520/Fotolia

Johan made a long pass down court to Yuan. Alise, a friend from Johan’s math class, calculated that the height of the pass was a function of the distance from the thrower.

 

Alise’s function is h(x) = −0.136d2 + 1.63d + 1.67, where d is the distance and h is the height of the ball in metres. The height of Yuan’s hands catching the ball matched the function h = −0.21(d −10.5) + 2.5.

 

At what height and at what distance away from Johan did Yuan catch the ball? Solve by graphing the two functions with a graphing calculator or some other graphing tool. Round the answer to one decimal place. Answer



notes organizer

If you haven’t done so already, you may want to add what you have learned about quadratic functions in this lesson to your notes organizer.


If you feel you need a bit more practice, complete Self-Check 4 before moving to Connect.

 

Self-Check 4


textbook

Complete all or parts of questions 4, 7, 8, and 13 on pages 411 to 413 and questions 2, 3, 7, 8, and 9 on pages 402 and 403 of the textbook. When you finish a question, check your work using the shortened answers given on pages 560 to 564 of the textbook. If you are still unclear about how to answer any of the questions, ask your teacher for help.


The solution will be the coordinates of an intersection point.

 

1.8. Connect

Mathematics 20-2 M3 Lesson 7

Module 3: Quadratics

 
Connect
 
Lesson Assignment
 

assignment

Complete the Lesson 7 Assignment that you saved to your course folder.

 

Project Connection
 

Open the Module 3 Project and complete Part 3.

 

 

1.9. Lesson 7 Summary

Mathematics 20-2 M3 Lesson 7

Module 3: Quadratics

 
Lesson 7 Summary
This is a photo of two teams playing a soccer game.

© Ian MacLellan/493481/Fotolia

 

In this lesson you investigated the following questions:

  • How can you use a quadratic equation in factored form to solve problems involving the zeros of the corresponding quadratic function or the x-intercepts of the graph of the function?
  • How can you find the roots of a quadratic equation by graphing the corresponding quadratic function?

You found that there could be an infinite number of quadratic functions that have the same zeros or x-intercepts. Among those functions, a certain function could be specified by giving the coordinates of a third point on the parabola or by giving the value of a in the function y = a(xr)(xs).

 

You also learned that the roots of a quadratic equation are the solutions to the corresponding function equal to zero. The roots have the same values as the x-intercepts of the graph of the corresponding function and the zeros of that function.

 

By changing a function into a corresponding equation with one side equal to zero, you were able to solve for the x-intercepts of the graphs and the zeros of the function. This enabled you to answer questions involving the functions.

 

You learned how to find the x-intercepts of a function using a graphing calculator. You practised using the zero capability of the CALCULATE feature to answer problems involving a variety of situations.

 

In Lesson 8 you will learn a new process for solving quadratic equations to find their roots.