Module 4 Intro

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1. Module 4 Intro

Module Introduction

Module 4—Properties of Solutions

Module Introduction

 

Have you ever wondered why salt dissolves in water? Scientists approach such questions by studying the observable properties of a substance (also called empirical properties) and relating them to accepted scientific theories of the time.

 

According to Aristotle, an ancient Greek philosopher, all matter could be classified as fire, earth, air, and water. Aristotle reasoned that the dryness of salt makes it a kind of earth and that water acted on earth in a process similar to the way water erodes rocks.

 

In the 1800s, the scientific community generally accepted that small indivisible particles, called atoms, were the building blocks of matter. Using the concept of atoms, Svante Arrhenius was able to explain that the difference in conductivity between salt and sugar solutions is due to a phenomenon known as dissociation. In the 1900s electrons and intermolecular forces were known to chemists, so chemists were able to use these new ideas in their theories.

 

In this module you will explore the relationship between empirical properties and theoretical ideas, with an emphasis on qualitative and quantitative analysis.

 

Think about the following questions as you complete this module:

  • What are some of your preconceived notions about solution chemistry?

  • Have you acquired new knowledge from this module that contradicts your prior beliefs?

1.1. Big Picture

Big Picture

Module 4—Properties of Solutions

Big Picture

 

A photograph of a drinking glass being filled with water from a kitchen tap.

© Tommy Maenhout/shutterstock

Tap water is a critical component of your day-to-day life. In fact, you probably use far more water than you think! According to Environment Canada, the average Canadian household uses 335 L of water per day. The uses for water are broken down as follows:

 

35% bathing and showering

30% flushing the toilet

20% laundry

10% drinking and kitchen chores

5% cleaning

 

When you turn on the tap to fill a glass with water, you have certain expectations for what comes out. If the water is coloured or smells foul, you would likely suspect that something is present in the water that you do not want to consume. What is present in tap water? Why is it there? What substances were removed during its processing? You may have heard that Canadian drinking water is among the safest in the world, but are you aware of how water is treated and monitored?

 

In this module you will study the processes involved with bringing drinking water from a natural source, such as a river, to your home. You will also study how water is able to form solutions with many substances.

 

This module will focus on the big questions:

  • What is a solution?
  • Why are solutions often used to study chemical systems?

As you complete each lesson in this module, you will investigate the following essential questions:

  • What is a solution?

  • What kind of mixture is a solution?

  • How did Arrhenius contribute to the understanding of electrolytes, acids, and bases?

  • What does it mean to dissolve a substance?

  • What role does energy have in the dissolving of a substance?

  • How can you predict the solubility of a substance in water?

  • How is dynamic equilibrium involved when studying a saturated solution?

  • How is solution concentration expressed?

  • How do you calculate amount concentration and determine concentration of species in a solution?

  • How are solutions prepared?

As a citizen you will consume tap water for many years to come. You may become interested in questions such as “What is in the water?” and “How much is able to be made available?”

 

Understanding the science associated with drinking water quality will help you complete the Proactive Citizen Project components of assessment for this module. These components are located in the Reflect on the Big Picture sections within the module lessons.

 

1.2. In this Module

In This Module

Module 4—Properties of Solutions

In This Module

 

Lesson 1—Classifying Matter and Solutions

 

When you hear the term solution, you probably visualize all the cleaning supplies in your home. While it’s true these products are solutions, there are many other items around your home that are solutions as well! For example, a gold ring is a metal-metal solution called an alloy. In this lesson you will learn how to properly classify matter and solutions.

  • What is a solution?
  • What kind of mixture is a solution?
Lesson 2—Dissolving Substances

 

Dissolving a substance seems to be a very simple process when you observe it—simply throw a suitable solid into water and it disappears. However, the theoretical reasons for this process baffled scientists for centuries. In this lesson you will learn how Svante Arrhenius contributed to solution chemistry with his theories of electrolyte dissociation. You will also learn how bond energy plays a critical role in the dissolving process, allowing for the existence of products like cold packs and heat packs.

  • How did Arrhenius contribute to the understanding of electrolytes, acids, and bases?

  • What does it mean to dissolve a substance?

  • What role does energy have in the dissolving of a substance?
Lesson 3—Solubility

 

This lesson discusses the qualitative aspects of solubility. Solutions are not capable of holding an unlimited amount of solute. At some point the solute will simply start collecting at the bottom of the container. There are many factors that can affect the solubility of a solid or a gas in solution, and you will learn about these factors both empirically and theoretically.

  • What are saturated solutions?
  • How can you predict the solubility of a substance in water?
  • How is dynamic equilibrium involved when studying saturated solutions?
Lesson 4—Concentration I

 

Concentration is a quantitative aspect of solution chemistry that provides a comparison of the amount of solute to the amount of solution. There are many methods of expressing concentration in consumer products, and you will learn how and why these methods are used. You will also learn how concentration measurements are used in a wide variety of applications.

  • How can the concentration of solute in a solution be expressed?
Lesson 5—Concentration II

 

Concentration must be expressed in a lab using moles rather than mass. Otherwise, mathematical relationships between the entities in a balanced chemical equation cannot be described in a straightforward manner. In this lesson you will learn how to calculate amount concentrations in a variety of situations. You will then learn how amount concentrations can be applied to dissociated ions, dilution, and solution preparation.

  • How can the concentration of solute in a solution be expressed?

  • How do you calculate amount concentration and determine concentration of species in a solution?

  • How are solutions prepared in a lab?

Module Assessment

 

The assessment in this module consists of the following:

  • Module 5: Lesson 1 Assignment
  • Module 5: Lesson 3 Assignment
  • Module 5: Lesson 5 Assignment
  • Proactive Citizens Projects (two projects)

For the Proactive Citizen Projects, you will choose two of the topics listed in the Module 4 Summary and Assessment document and decide when you wish to complete them. You may wish to refer to the list of topics as you complete each lesson in the module. More information, including a list of topics and a scoring guide, is available in the Module 4 Summary and Assessment document.

 

1.3. Lesson 1 Intro

Lesson 1

Module 4—Properties of Solutions

Lesson 1—Classifying Matter and Solutions

 

Get Focused

 

A photograph of a lake surrounded by snow-capped mountains.

© 2007 Jupiterimages Corporation

Do you know where your drinking water comes from? Glacier meltwater in the Rocky Mountains is the source of all rivers in Alberta. The Bow River, which flows through Calgary, starts at the Bow Glacier in Banff National Park. The North Saskatchewan River, which flows through Edmonton, starts at the Saskatchewan Glacier in the Columbia Icefield.

 

Both Calgary and Edmonton, as well as many other communities in Alberta, use river water as drinking water. However, before the river water arrives at people’s homes, it undergoes inspection and treatment to make sure it is suitable for human consumption.

 

How do you know if your drinking water is safe? The Guidelines for Canadian Drinking Water Quality, published by Health Canada, gives maximum upper limits for the concentration of dangerous substances in the water supply. All drinking water must meet specific requirements in the following areas:

  • aesthetic quality (clarity and colour)

  • microbiological and chemical contamination

The inspection and treatment of water is a very complex process, and it requires a thorough understanding of solutions. In this lesson you will begin your study of solutions by learning how scientists classify matter and solutions.

 

Essential Questions
  • What is a solution?

  • What kind of mixture is a solution?

Module 4: Lesson 1 Assignment

 

Save a copy of the Module 4: Lesson 1 Assignment to your course folder. Later in the lesson you will receive more information about how to complete this assignment and when to submit it to your teacher.

 

The other questions in this lesson are not marked by the teacher; however, you should still answer these questions. The Self-Check and Try This questions are placed in this lesson to help you review important information and build key concepts that may be applied in future lessons.

 

After a discussion with your teacher, you must decide what to do with the questions that are not part of your assignment. For example, you may decide to submit to your teacher the responses to Try This questions that are not marked. You should record the answers to all the questions in this lesson and place those answers in your course folder.

 

In this module you will complete two of the Proactive Citizen Projects listed in the Module 4 Summary and Assessment document. Choose which two topics to complete and when you wish to complete them. A list of topics and a scoring guide are available in the Module 4 Summary and Assessment document.

 

1.4. Page 2

Lesson 1

Module 4—Properties of Solutions

Explore

 

Discuss

 

A photograph of many plastic bottles containing water. The bottles are aligned in a row.

© Clint Scholz/shutterstock

Companies that sell bottled water generate billions of dollars annually in profit. Bottled-water consumption is growing by approximately 10% every year.

 

On the discussion board, share your thoughts about the following topics related to bottled water:

  • Do you drink bottled water on a regular basis? Why or why not?
  • In your opinion, do you feel bottled water is safer than tap water? Give reasons or examples to back up your opinion.
  • Some religious and human rights organizations have expressed concern about the “privatization” of water and feel it is unethical to repackage a basic necessityof life for profit. Opponents to this objection often refer to the fact that food and shelter are just as vital, and since those items are sold as commodities, why not water too? What is your opinion about selling water?

Module 4: Lesson 1 Assignment

 

Retrieve the copy of the Module 4 Lesson 1 Assignment that you saved earlier in this lesson. Later you will paste into the assignment a copy of your posting, the posting of two other students, and your comments on their posting.

 

Before you start this part of the assignment, review the Discussion Rubric.

 

Post to the discussion board your thoughts on the above questions, and then respond to at least two other student postings. Paste these postings into Part 1 of the assignment and then reflect on your original posting. Finally, you may revise your original posting.

 

Module 4: Lesson 1 Assignment

 

Save the postings and revised version to Part 1 of Module 4: Lesson 1 Assignment. Make sure you save your work to your course folder. Later in the lesson you will receive information on how to complete Part 2 of the assignment.

 

Read

 

Matter is a very general term that refers to anything that has mass and occupies space. Scientists subdivide matter into two broad categories: pure substances and mixtures.

 

A pure substance consists of one chemical only and may be subcategorized as either an element or a compound.

 

A mixture consists of two or more substances and may be subcategorized as either homogeneous or heterogeneous.

 

A homogeneous mixture may appear to contain only one substance with uniform properties, but in reality it may contain several different substances. A solution is a type of homogeneous mixture composed of at least one solute and one solvent. Can you think of any other examples of homogeneous mixtures?

 

A heterogeneous mixture visibly contains two or more different components. A chocolate chip cookie is a heterogeneous mixture since the chocolate chips can be seen as being separate from the rest of the cookie.

 

For more information on the different forms of matter, read “Classifying Matter” on pages 12 and 13 of your textbook.

 

For more information on methods used to isolate the different components of matter in a mixture, read “Crystallization” and “Filtration” on pages 802 and 803 in your textbook.

 

1.5. Page 3

Lesson 1

Module 4—Properties of Solutions

Classification of Solutions

 

Two plain circular jewellery rings are shown. One ring is gold in colour and the other ring is grey.

Metals such as gold are called “precious metals” because they are rare in nature and have a high economic value. Since ancient times, gold jewellery has been produced as a means of displaying wealth and status.

 

One problem with the use of gold for jewellery is the softness of the metal. You may have seen a gold ring that has been worn so long that it is no longer round because it has shaped itself to the finger of the person wearing it. Gold in its pure form is actually too soft to use in jewellery—it can bend out of shape very easily. Fortunately, the strength of most jewellery is improved significantly by mixing the gold with other metals to form a solution called an alloy.

 

Are you wearing a gold ring? Can you read the stamp on the inside of the band? You may have noticed that the stamp indicated that the gold is 10 k or 14 k. When gold is labelled as being 24 karat, it means 24 parts are pure gold and no other metal is present. If gold is 18 karat, 18 parts of the 24 total possible parts are gold and the 6 remaining parts are some other metal, which together forms the alloy. A ring that is 24-karat gold will more easily bend out of shape than a ring that is 18-, 14-, or 10-karat gold.

 

Not only does an alloy solution improve the strength of the jewellery, it can dramatically change the appearance of the jewellery too! The only difference between yellow gold and white gold is the type of metal being mixed with the gold. You will soon understand how solution chemistry plays an important role in the production of yellow gold and white gold rings.

 

Definition and Types of Solutions

 

A solution is composed of a solute dissolved in a solvent. Solutes and solvents may be solids, liquids, or gases. The following table shows how various combinations lead to different types of solutions.

 

solution: a homogeneous mixture of at least one solute dissolved in a solvent


solute: a component of a solution, the material that dissolves in the solvent

 

solvent: a component of a solution, the material in which the solute dissolves


 

Types of Solutions Solvent

Solid

Liquid

Gas

Solute

Solid

brass (tin in copper)

ocean water (salt in water)

does not form solutions

Liquid

amalgam dental fillings (mercury in silver)

antifreeze (ethylene glycol in water)

does not form solutions

Gas

1980s cold fusion experiments (hydrogen absorbed into the crystalline lattice of palladium)

club soda (carbon dioxide in water)

air (oxygen in nitrogen)

 

The most important property of a solution is homogeneity. This means that the solution will have an identical composition throughout. If you use a micropipette to analyze an extremely small sample of a solution, it will have exactly the same composition as the larger mixture. Substances like milk and fog are not considered to be solutions because they are heterogeneous mixtures. In a true solution, the solute particles will not separate from the solvent on standing, nor can they be filtered out.

 

For further information, read “Solutions and Mixtures” on pages 192 and 193 in your textbook.

 

1.6. Page 4

Lesson 1

Module 4—Properties of Solutions

Aesthetic Qualities of Drinking Water

 

When you fill a glass with tap water, there are expectations for what this water should be like. You would not expect dirty or cloudy water; and if there were a bad smell, you might feel the water is unsuitable for drinking. There are a number of physical characteristics that must be inspected to make sure the water you drink meets guidelines for aesthetic quality.

 

Turbidity

 

turbidity: the measure of the clarity of a clear liquid

Turbidity is a measure of the water cloudiness that results from the suspension of small particles. In nature, water is continuously picking up sediment and organic matter. While the particles themselves may not pose a significant health risk, dangerous micro-organisms can attach themselves to these particles. During water treatment the sediment can actually protect the micro-organisms from disinfectant processes. If water is sterilized using ultraviolet (or UV) light, a micro-organism shielded by the sediment will not be destroyed.

 

Not all cloudy water is associated with turbidity. For example, tap water is sometimes cloudy when it first comes out of the tap, but clears up after it stands for a few minutes. This is due to air that is trapped in the water from turbulence in the pipes. This type of cloudiness has no health concerns associated with it.

 

Colour

 

Most people expect their drinking water to be clear, but sometimes there are substances present that give the water a tint. In Canada, 90% of the drinking water comes from surface water, while the remaining 10% comes from groundwater. If surface water has a colour, it likely results from organic substances of natural origin. If groundwater has a colour, it likely results from dissolved minerals. One of the main problems with coloured water is that it can stain laundry and plumbing fixtures.

 

Water Tint

Common Cause

A diagram shows a half-filled beaker containing a yellow solution.

Humic Acid Discolouration.This discolouration can be caused by humic acid, which is present naturally in soil and vegetation. At the current time, it is assumed this substance has no significant effect on human health. Research is being done to see whether the chlorination process reacts with humic acid to create toxic by-products or whether the presence of humic acid correlates to the presence of heavy metals in the drinking water.

A diagram shows a half-filled beaker containing an orange solution.

Iron Discolouration. Iron can naturally enter drinking water from soil and rocks or from being leached out of pipes. In low doses iron is a nutrient required by the body, so there is no significant health risk.

 

Reddish-brown water can also occur if rust-coloured sediments are disturbed during water main repairs. This discolouration can often be remedied by letting the tap run for several minutes.

A diagram shows a half-filled beaker containing a blue solution.

Copper Discolouration. On rare occasions, specific conditions arise that allow copper to be leached out of pipes into the drinking water. This is not typically a hazard since copper in trace amounts is an essential nutrient. However, in older homes, lead may have been used in some of the pipes. The same conditions that can leach copper can also leach lead, which is very toxic and not easily detected.

 

If you suspect your home may be of the age where lead pipes were used during construction, you may want to contact your regional health authority to ask them to test your water.

A diagram shows a half-filled beaker containing a purple solution.

Manganese Discolouration. Much like iron, manganese can naturally enter drinking water from soil and rocks. In addition to tinting the water, it can sometimes be found as small black specks in a glass of water. Manganese is an essential nutrient, and in small qualities it does not have any negative health effects.

 

Taste and Odour

 

Some of the common problems experienced with the taste and smell of drinking water are listed in the following table.

 

Water Taste and Odour

Common Cause

chlorine

Chlorine. Chlorination is used in the water-treatment process.

To keep water free of bacteria all the way to your tap, some chlorine must be allowed to remain in the water. Occasionally, there may be enough chlorine that an odour can be detected. This low quantity is non-toxic, and you may drink the water. If the taste and smell of chlorine are not appealing you, simply let the water stand and the chlorine will dissipate.

rotten egg

Hydrogen Sulfide Gas. This can occur in cases where tap water is coming from a well. Decomposing deposits of underground organic matter produce this gas, which may then enter the well water. Hydrogen sulfide gas can also enter well water that is near coal deposits or oil fields.

 

In some cases, the water itself is not the cause of the rotten-egg smell; rather it is coming from the drain. Anaerobic bacteria can thrive in this environment, producing hydrogen sulfide gas that accumulates underneath the food trap. When the water is turned on, the gas is forced out of the drain, yielding the rotten-egg smell. This problem can be fixed by pouring a cup of household bleach down the drain to kill the bacteria.

 

It is also possible that the smell is coming from the hot water heater, which has a magnesium rod that can interact with sulfates in the water to produce hydrogen sulfide gas. This is likely the problem if the rotten-egg smell is present in hot water but not cold water.

 

Hydrogen sulfide gas is not harmful at the levels you would find in tap water, and the bacteria that produce it pose no known health risk. However, if the smell is indeed coming from the water and has appeared for no previously known reason, it would be a good idea to call your water supplier to inform them of the problem. Hydrogen sulfide gas can, in rare cases, result from pollution or sewage contamination.

fishy or swampy

Algae Growth. There are many different tastes and odours that are the result of algae growth in reservoirs. Depending on the type of algae, the water can taste and smell fishy, swampy, grassy, and even like cucumber! There are no health risks associated with smells related to algae growth.

 

Self-Check

 

SC 1. A number of substances, in addition to their possible classification, are listed in the following table. Recall that pure substances may be classified as an element or a compound. Mixtures may be classified as homogeneous or heterogeneous. Fill in this table. The first row is done for you.

 

Substance

Pure Substance
or
Mixture

Element
or
Compound

Homogeneous Mixture
or
Heterogeneous Mixture

distilled water

pure substance

compound

--------

smoke-filled air

 

 

 

24-karat gold ring

 

 

 

grape juice from concentrate

 

 

 

salty water

 

 

 

milk

 

 

 

sugar

 

 

 

18-karat gold ring

 

 

 

freshly squeezed orange juice

 

 

 

blood

 

 

 

methanol, CH3OH(l)

 

 

 

molten lead

 

 

 

 

SC 2. Some substances may form a homogeneous mixture or a heterogeneous mixture, depending on environmental conditions. For each of the following, explain when it would be classified as a homogeneous mixture and when it would be classified as a heterogeneous mixture.

  1. humid air
  2. soda pop
  3. ice cubes
Check your work.
Self-Check Answers

 

SC 1.

 

Substance

Pure Substance
or
Mixture

Element
or
Compound

Homogeneous Mixture
or
Heterogeneous Mixture

distilled water

pure substance

compound

--------

smoke-filled air

mixture

-------

heterogeneous mixture

24-karat gold ring

pure substance

element

-------

grape juice from concentrate

mixture

-------

homogeneous mixture

salty water

mixture

-------

homogeneous mixture

milk

mixture

-------

heterogeneous mixture

sugar

pure substance

compound

-------

18-karat gold ring

mixture

-------

homogeneous mixture

freshly squeezed orange juice

mixture

-------

heterogeneous mixture

blood

mixture

------

heterogeneous mixture

methanol, CH3OH(l)

pure substance

compound

-------

molten lead

pure substance

element

-------

 

SC 2.

  1. Humid air is normally a homogeneous mixture of air and water vapour; but if the air becomes so humid that fog or precipitation forms, it becomes a heterogeneous mixture because of the visible liquid water droplets that form.

  2. When soda pop is in a sealed bottle, it is a homogeneous mixture of the syrup solution and dissolved carbon dioxide. If the pressure is reduced, such as when you open the bottle and pour it into a glass, carbon dioxide gas bubbles form in the pop, making the solution heterogeneous.

  3. Tap water contains both solid and gas impurities. As water freezes, these impurities are pushed towards the centre of the ice cube. This process accounts for the cloudy centre of an ice cube. The presence of many small oxygen bubbles makes the ice cube heterogeneous. If the water is boiled for several minutes, all of the gases in the water will escape. This will result in a clear homogeneous ice cube.

 

1.7. Page 5

Lesson 1

Module 4—Properties of Solutions

Read

 

Read the section “Properties of Aqueous Solutions” on pages 193 and 194 in your textbook to learn more about the test for conductivity and the properties of acidic, basic, and neutral solutions.

 

The Aqueous Phase

 

As you read in the previous section, drinking water can contain many dissolved substances. Not only can dissolved substances provide colour or taste, but they can make a solution have other unique properties.

 

aqueous phase: a phase denoting a highly soluble substance that has been dissolved in water; denoted by (aq)

 

conductivity: the ability of a solution to transfer an electric current

 

electrolyte: a solution that conducts an electric current

 

nonelectrolyte: a solution that does not conduct an electric current

If sugar is dissolved in water, can it still it be written as C12H22O11(s)? The answer to this question is no, since the sugar molecules are no longer behaving as a crystalline solid—they are dispersed throughout the solution. The aqueous phase (aq) is used to indicate that a substance is dissolved in water. Note that a solute is said to be aqueous only if it is dissolved in water. If it is dissolved in a different solvent, such as alcohol, the phase would be written (alc).

 

Two other properties often considered when investigating solutions are conductivity and acidity. (Solubility is another property, which will be addressed in a later lesson.)

 

Some solutions demonstrate conductivity. A solution that conducts electricity contains electrolytes. Electrolytes are charged ions present within a solution. Their ability to move allows a current to be established within a solution. Tap water conducts electricity because the ions of dissolved solutes are present, while pure distilled water would not conduct electricity since no ions are present. Many molecular compounds form solutions that are nonelectrolytes because the solute does not form ions when it dissolves. Therefore, solutions containing dissolved molecular compounds do not conduct electricity.

 

Self-Check

 

SC 3. Examine the diagram below. Identify where an electrolyte and nonelectrolyte would appear on the chart.

 

A flowchart diagram is shown. The upper box contains the label “Does the solution conduct electricity?” Two branches are shown. The branch labeled yes ends at a box with the label “Does the solution affect litmus paper?” Three branches extend from this box. The first branch has the label “blue litmus turns red,” the box the branch extends to contains the label “It’s an acid.” The second branch has the label “No change to red or blue litmus.” the box the branch extends to has the label “It’s a neutral compound.” The third branch has the label “Red litmus turns blue.” The box at the end of the branch has the label “It’s a base.” The second branch from the first box is labeled “no,” the box at the end of the branch is labeled “It’s a neutral molecular solution”.

 

Check your work.
Self-Check Answers

 

SC 3.

 

A flowchart diagram is shown. The upper box contains the label “Does the solution conduct electricity?” Two branches are shown. The branch labeled yes ends at a box with the label “Does the solution affect litmus paper?” To the left of this box is the answer label “Electrolyte.” The second branch from the first box is labeled no. The box at the end of the branch is labeled “It’s a neutral molecular solution.” To the right of this box is the answer label “Nonelectrolyte.”

 

1.8. Page 6

Lesson 1

Module 4—Properties of Solutions

Going Beyond


Microbiological and Chemical Contamination of Drinking Water

 

A great deal of concern exists about substances in drinking water. Water purification processes focus on removing many micro-organisms that have the potential to be harmful. Recently additional attention has been placed on the presence of metals, pesticides, and pharmaceutical products that may be present in the water supply.

 

Further information about these sources of contamination can be accessed here.

 

Self-Check

 

SC 4. A number of solutions are listed in the following table. Fill in the table, using the example to guide you.

 

Mixture

Type of Solution

Solute

Solvent

carbonated water

gas in liquid

carbon dioxide

water

mercury amalgam dental filling

 

 

 

brass

 

 

 

grape juice from a powder

 

 

 

alcoholic beverage

 

 

 

milk

 

 

 

humid air

 

 

 

18-k gold ring

 

 

 

smoke-filled air

 

 

 

oxygen dissolved in water

 

 

 

 

SC 5. Classify each of the following substances as an electrolyte or a nonelectrolyte. Also, indicate whether the solution will be acidic, basic, neutral ionic, or neutral molecular.

  1. liquid bromine, Br2(l)
  2. table salt, NaCl(aq)
  3. table sugar, C12H22O11(s)
  4. methanol, CH3OH(l)
  5. lye, NaOH(aq)

SC 6. There are four beakers containing visually identical solutions. If the potential solutions are HCl(aq), NaOH(aq), NaCl(aq), and C12H22O11(aq), design an experiment that will determine the solution in each beaker.

 

Check your work.
Self-Check Answers

 

SC 4.

 

Mixture

Type of Solution

Solute

Solvent

carbonated water

gas in liquid

carbon dioxide

water

mercury amalgam dental filling

liquid in solid

mercury

silver

brass

solid in solid

tin

copper

grape juice from a powder

solid in liquid

powder

water

alcoholic beverage

liquid in liquid

ethanol

water

milk

not a solution

 

 

humid air

gas in gas

water vapour

air (or nitrogen)

18-k gold ring

solid in solid

various metals

gold

smoke-filled air

not a solution

 

 

oxygen dissolved in water

gas in liquid

oxygen

water

 

SC 5.

  1. nonelectrolyte, neutral molecular
  2. electrolyte, neutral ionic
  3. nonelectrolyte, neutral molecular
  4. nonelectrolyte, neutral molecular
  5. electrolyte, basic
Note the difference between CH3OH and NaOH. CH3OH is molecular and does not dissolve in water; NaOH is ionic and will dissolve in water.

 

SC 6. First, do a conductivity test. The solution that does not conduct electricity is C12H22O11(aq). Since the remaining three beakers all conduct electricity, they can be distinguished using a litmus test. The solution that turns blue litmus red is HCl(aq), the solution that has no effect on either colour is NaCl(aq), and the solution that turns red litmus blue is NaOH(aq).

 

1.9. Lab

Lesson 1

Module 4—Properties of Solutions

Module 4: Lesson 1 Assignment

 

Retrieve the copy of the Module 4 Lesson 1 Assignment that you saved earlier in this lesson. You will use the following lab to complete Part 2 of your Module 4: Lesson 1 Assignment.

Lab: Frozen Solutions

 

View the “Frozen Solutions” video. You may be required to login with a username and password. Contact your teacher for this information. Use the information contained on the video to answer the assignment questions based on the video. Replay sections of the video, if necessary, to obtain all your observations.

 

Save a copy of your work to your course folder. Later in the lesson you will receive instructions on when to submit the assignment to your teacher.

 

1.10. Page 8

Lesson 1

Module 4—Properties of Solutions

Reflect and Connect

 

Self-Check

 

SC 7. For each of the following, determine whether the statement is true or false. For those that are false, write a brief sentence indicating the required correction.

  1. Mixtures may be homogeneous or heterogeneous.

  2. Distilled water is obtained by letting the water sit until impurities settle out.

  3. Homogenized milk is a heterogeneous mixture.

  4. A perfectly clear solution is a pure substance.

  5. In a solution, the solute is the substance present in a lesser amount.

  6. Liquid water in air forms a solution of humid air.

  7. A solution of ethanol does not conduct electricity since C2H5OH is a molecular compound.

  8. Pure water does not conduct electricity.

  9. Pure water may be classified as a solution.

SC 8. There are four beakers with visually identical liquids—Sr(OH)2(aq), C12H22O11(aq), H3PO4(aq), and H2O(l). A student must correctly identify which liquid is in each beaker.

  1. For each beaker, identify the results of a conductivity test and a litmus test.

    Beaker Contents

    Result of Conductivity Test

    Result of Litmus Test

    Sr(OH)2(aq)

       

    C12H22O11(aq)

       

    H3PO4(aq)

       

    H2O(l)

       
  2.  
  3. Is it possible to correctly identify all four solutions by only performing conductivity and litmus tests? Explain.

SC 9. Read the following information and then answer the questions.

 

Gold jewellery is very common in society, and an understanding of alloy solutions will help you next time you make a purchase at a jewellery store. First, the purity of gold rings is measured in karats (k). A 24-k gold ring is 100% gold, an 18-k gold ring is 75% gold, and so on. To determine the percentage of gold in a ring, simply divide the karat number by 24 and multiply by 100%.

 

Gold rings need not be confined to the traditional yellow colour; white gold is an enormously popular alternative. The difference between yellow gold and white gold comes from other metals present in the alloy solution. Yellow gold contains elemental gold mixed with metals such as copper and zinc, while white gold contains elemental gold mixed with metals such as silver and palladium. Since white gold is still not completely white even after the addition of these metals—it’s more of an off-white or light grey—a layer of rhodium is added to the ring to give the final shiny appearance. This layer can be rubbed off over time, so white gold jewellery typically requires a rhodium replating after approximately two or three years of use.

 

White gold has led to some health concerns in the past, as nickel metal was used as one of the metals in the alloy. About 12% to 15% of the population suffers from skin allergies from nickel. Often, white gold rings will be described as “hypoallergenic,” meaning that no nickel was used in the production of the ring. Palladium is typically used as an alternative.


  1. What percentage of a 10-k gold ring is actually gold?

  2. 22-k gold rings and higher are typically not produced. Why would these rings make poor jewellery?

  3. Is it possible to make a 24-k white gold ring?
     
  4. Give three examples of how the use of alloys in ring production is advantageous.

  5. Suggest two reasons why it is important to replace the rhodium coating on a white gold ring.
Check your work.
Self-Check Answers

 

SC 7.

  1. True

  2. False

  3. True

  4. False

  5. True

  6. False

  7. True

  8. True (to any measurable extent)

  9. False

SC 8.


  1. Beaker Contents

    Result of Conductivity Test

    Result of Litmus Test

    Sr(OH)2(aq)

    Conductive

    Red litmus turns blue

    C12H22O11(aq)

    Not conductive

    No change

    H3PO4(aq)

    Conductive

    Blue litmus turns red

    H2O(l)

    Not conductive

    No change


  2. No, C12H22O11(aq) and H2O(l) both have the same test results.

SC 9.

  1. % = (10K/24K) 100 = 42%

  2. Gold is a soft (malleable) metal and quickly loses its shape.

  3. No, 24K means no other metals are added.

  4. Reason 1: Adding other metals makes the ring less malleable and therefore it will last longer.

    Reason 2: Addition of less expensive metals makes ring less costly.

    Reason 3: Adding other metals changes the colour of the ring, providing more choice to the consumer.

  5. Reason 1: The rhodium coat is required to give the ring its shiny appearance, since white gold actually has a dull grey colour.

    Reason 2: Some people have allergies to metals such as nickel. The rhodium coating prevents contact between these metals and the skin.

 

Reflect on the Big Picture

 

Proactive Citizen Projects

 

In this module you will complete two of the Proactive Citizen Projects listed in the Module 4 Summary and Assessment document. Choose which two topics to complete and when you wish to complete them. More information, including a list of topics and a scoring guide, is available in the Module 4 Summary and Assessment document.

 

Assessment

 

Submit the following item to your teacher:

  • Module 4: Lesson 1 Assignment

You may have selected your topics for the Proactive Citizen Projects listed in the Module 4 Summary and Assessment document. As you work on these projects, save your work to your course folder. You will receive information later in this module about submitting your completed work to your teacher.

 

1.11. Page 9

Lesson 1

Module 4—Properties of Solutions

Lesson Summary

 

At the beginning of this lesson, you were asked the following essential questions:

  • What is a solution?
  • What kind of mixture is a solution?

Many people know that gold is a yellow metal, but they have no idea what white gold is. People will often say that a white gold ring contains platinum! You have now learned that white gold does indeed contain gold, but the gold is in an alloy solution with other metals.

 

Before completing this lesson, you likely thought the term solution was nothing more than another way of saying that something is a liquid. As you have seen, solutions are far more varied and may exist as solids, liquids, or gases. You also learned that solutions are defined as homogeneous mixtures, preventing things like milk and fog from being classified as solutions. Finally, the unique properties of solutions were explored, and you learned how they can be used to distinguish visually identical solutions from one another in the lab.

 

Lesson Glossary

 

aqueous phase: a phase denoting a highly soluble substance that has been dissolved in water; denoted by (aq)

 

conductivity: the ability of a solution to transfer an electric current

 

electrolyte: a solution that conducts an electric current

 

nonelectrolyte: a solution that does not conduct an electric current

 

solution: a homogeneous mixture of at least one solute dissolved in a solvent


solute: a component of a solution, the material that dissolves in the solvent

 

solvent: a component of a solution, the material in which the solute dissolves

 

turbidity: the measure of the clarity of a clear liquid

 

1.12. Lesson 2 Intro

Lesson 2

Module 4—Properties of Solutions

Lesson 2—Dissolving Substances

 

Get Focused

 

A photograph shows tropical fish swimming near coral in a reef.

© Ian Scott/shutterstock

All organisms require clean water in order to survive. Have you ever tried to keep tropical fish? The chemistry of successfully maintaining an aquarium—especially a saltwater aquarium—is underestimated by most people who have not had to maintain one.

 

To properly manage an aquarium, you must test the water’s composition of dissolved substances. Some of these substances include

  • chlorine
  • ammonia and nitrites
  • phosphates
  • oxygen
  • salt (only in a saltwater aquarium)

If you wish to know more about aquarium water quality, read here.

 

In this lesson you will learn why substances dissolve in water. You will also learn that aquarium chemistry provides valuable insight into the role of dissolved substances in delicate natural ecosystems.

 

Essential Questions
  • How did Arrhenius contribute to the understanding of electrolytes, acids, and bases?
  • What does it mean to dissolve a substance?
  • What role does energy have in the dissolving of a substance?
Assessment

 

There is no Module 4: Lesson 2 Assignment.

 

In this lesson you will continue your work on the two Proactive Citizen Projects listed in the Module 4 Summary and Assessment document. The topics and a scoring guide are available in the Module 4 Summary and Assessment document.

 

You must decide what to do with the questions that are not marked by the teacher.

 

Remember that these questions provide you with the practice and feedback that you need to successfully complete this course. You should respond to all the questions and place those answers in your course folder.

 

1.13. Page 2

Lesson 2

Module 4—Properties of Solutions

Explore

 

Read

 

Arrhenius’s Theory of Electrolytes, Acids, and Bases

 

A photograph of Svante Arrhenius

© 2007 Jupiterimages Corporation

In 1887, while working on his PhD in chemistry, Svante Arrhenius did substantial research on the freezing-point depression of solutions containing electrolytes. This research led to the development of a unique theory to describe the changes that occur to solutes when they dissolve in water.

 

Read pages 197 through 199 in your textbook to learn about Arrhenius’s theory.

 

You may also wish to read a summary of Arrhenius’s theory. Understanding this theory requires you to interpret the observable changes to a system in a new way, and to integrate what you have learned about intermolecular bonding from your study in Unit A in this course.

 

Self-Check

 

SC 1. Each of the following substances is placed in water. Determine whether it dissociates, ionizes, or neither. Also, identify whether it will be an acidic, neutral, or basic in solution. The first one is done for you.


 

Substance

Dissociates, Ionizes, or Neither

Acidic, Neutral, or Basic

KCl

dissociates neutral

HF

   

CH4

   

CH3COOH

   

C2H5OH

   

H2SO4

   

Ca(OH)2

   

MgCl2

   

C12H22O11

   

 

SC 2. How can you tell whether a molecular compound will yield a neutral solution or an acidic solution?

 

SC 3. State three important theories credited to Arrhenius.

 

SC 4. State one theoretical property of an acid and one theoretical property of a base.

 

SC 5. Why does a solution containing an electrolyte conduct electricity, whereas a solution containing a nonelectrolyte does not?

 

SC 6. What are three similarities and one difference between sodium nitrate and sodium hydroxide in solution?

 

Check your work.
Self-Check Answers

 

SC 1.

 

Substance

Dissociates, Ionizes, or Neither

Acidic, Neutral, or Basic

KCl

dissociates

neutral

HF

ionizes

acidic

CH4

neither (molecular)

neutral

CH3COOH

ionizes

acidic

C2H5OH

neither (molecular)

neutral

H2SO4

ionizes

acidic

Ca(OH)2

dissociates

basic

MgCl2

dissociates

neutral

C12H22O11

neither (molecular)

neutral

 

SC 2. A molecular compound can become an acid, but only if it ionizes in water to yield a hydrogen ion, H+(aq). Most molecular compounds, such as CH4(g), will not yield a hydrogen ion.

 

In Module 5 you will learn more about compounds that behave as acids or bases and how to use a chemical formula to predict whether a substance will have acidic or basic properties.

 

You may wish to look at the table “Relative Strengths of Acids and Bases at 298.15 K” in the Chemistry Data Book. Several acids are listed here, so you can check to see whether a particular molecular substance will form an acid.  The acids HF, CH3COOH, and H2SO4 listed above in SC 1. are included in the data book.

 

SC 3. Ionic compounds dissociate into their charged ions upon dissolving, acids ionize to produce H+(aq), and bases dissociate to yield OH(aq).
  
SC 4. According to Arrhenius, an acid ionizes to produce H+(aq) in solution and a base dissociates to form OH(aq).

 

SC 5. An electrolyte, when dissolved, dissociates into its charged particles. This allows a current to flow. Nonelectrolytes dissolve but do not dissociate, so there are no charged particles in solution. This prevents a current from flowing.

 

SC 6. Similarities

  • They are both electrolytes.
  • They both dissociate in water.
  • They both contain a negatively charged polyatomic ion.
The difference is that sodium nitrate is neutral, whereas sodium hydroxide is basic.

 

1.14. Page 3

Lesson 2

Module 4—Properties of Solutions

Read

 

Energy Changes and Dissolving Substances

 

A photograph of two commercial cold packs.

Have you or someone you know ever sprained an ankle or wrist? Did it swell and change colour? It was probably wrapped in a stretchy bandage and iced. When a tissue injury occurs, such as a pulled muscle or a sprain, capillaries break and blood leaks into the surrounding tissue. This leakage causes swelling to occur and leads to significant pain.

 

If cold is applied to the injury immediately after it happens, the blood vessels constrict and release less fluid. This change can minimize the pain associated with the injury. The advantages of quickly reducing swelling to an injured area have made cold packs a required item in most sports trainers' kits.

 

An unused cold pack is normally at room temperature and feels like a plastic bag filled with water. However, when the cold pack is forcefully squeezed, an inner package breaks and the contents are allowed to mix. The cold pack becomes cold! By the end of this lesson, you will understand how a theoretical understanding of solution chemistry can explain this surprising result.

 

endothermic process: a change in matter that requires an input of energy to occur

 

exothermic process: a change in matter that releases energy when it occurs

Read the section “Energy Changes” on pages 199 and 200 in your textbook.

 

As you read in the section of your textbook, several steps are involved when a solid dissolves in water to form aqueous ions. The first two steps require energy to break bonds and are endothermic. An endothermic process absorbs energy from the surroundings, making the surroundings cooler. The final step releases energy as bonds form and is exothermic. An exothermic process is the opposite of an endothermic one, releasing energy into the surroundings and warming the surroundings.

 

The following steps essentially happen simultaneously but are separated for your understanding.

 

A diagram shows alternating yellow and green spheres organized in three dimensions. The green spheres are labeled with a negative sign, and the yellow spheres are labeled with a plus sign. A water molecule represented by a single red sphere and two white spheres is beside one of the outer yellow spheres. Another water molecule is beside one of the outer green spheres. Red arrows point from each of the water molecules toward the yellow and green spheres. A label beside the arrow reads: Energy is required to break the ionic bonds holding the ions together.

Step 1: Breaking Bonds in the Solute (Endothermic)

 

The ions in the solid are held together with ionic bonds. These bonds must be broken before dissociation can occur. This step is endothermic because the energy required to break the bond comes from polar interactions with water molecules. (Think of the water molecule pulling the ion out from the solid.) As the water molecules use up their energy to break this bond, the solution cools.

 


 

The diagram shows a single green sphere surrounded by many water molecules. At the other side of the diagram, a single yellow sphere is surrounded by water molecules. Attractive forces between particles are shown by dotted lines. Dotted lines are shown between one water molecule and the green sphere. Dotted lines are shown between one water molecule and the yellow sphere.  Dotted lines are shown between the other water molecules in the diagram. The dotted lines between the water molecules are labeled with  red arrows. The label on the arrows reads: Energy must be supplied to break hydrogen bonds between water molecules.

Step 2: Breaking Bonds in the Solvent (Endothermic)

 

The water molecules in the solution may be hydrogen bonded to other water molecules. These hydrogen bonds must be broken before the water molecules can be available for dissolving the ions from the solute. This step is also endothermic, and the surrounding water cools.

 


 

The diagram shows a single green sphere surrounded by many water molecules. Dotted lines are shown between the yellow sphere and the water molecules.  At the other side of the diagram, a single yellow sphere is surrounded by water molecules. The diagram label reads: Energy is finally released when bonds form between the ions and water molecules.

Step 3: Dissolving the Solute (Exothermic)

 

Now that the ions are in solution and sufficient water molecules are free, bonds form between the water molecules and the ions. This step is exothermic and releases energy, warming the surrounding water.

 

As you have just learned, the dissolving process involves both endothermic and exothermic processes. The overall energy of dissolving a solid can be determined using the following formula:

 

energy released to break bonds in solute
+ energy required to break bonds in solvent
– energy required to form bonds between solute and solvent
______________________________________________________
= total change in energy

Based on this formula, if the energy required is more than the energy released, there is an energy deficit and the solution will cool down. If the energy required is less than the energy released, there is an energy surplus and the solution will warm up. In Chemistry 20 you will not be able to predict whether dissolving an ionic compound is an endothermic or exothermic process. The only way you can tell, for now, is by dissolving each substance in water and measuring the change in temperature. In Chemistry 30 you will learn how to use mathematics to predict the energy released.

 

1.15. Page 4

Lesson 2

Module 4—Properties of Solutions

Watch and Listen

 

In the following videos, you will see how dramatic endothermic and exothermic reactions can be!


Endothermic



Exothermic



 

Self-Check

 

A drawing of a pouch that is labelled as a Heat Pack. Part of the diagram shows the organization of the contents inside the pack. An inner pouch containing water is surrounded on all sides by solid calcium chloride.

Similar to the cold pack mentioned earlier, a heat pack contains two compartments: a large outer pouch containing calcium chloride, and water stored in the hollow inner cavity. A heat pack is used by breaking the pouch containing the calcium chloride crystals, allowing them to come into contact with water and dissolve.

 

SC 7. Write the balanced chemical equations for the changes that occur when calcium chloride dissolves in the water in the hot pack.

 

SC 8. Explain the type of energy changes involved in the hot pack during its operation.


Check your work.
Self-Check Answers

 

SC 7.  CaCl2(s) → Ca2+(aq)  +  2 Cl-(aq)

 

SC 8.  Many energy changes are involved:

  • The calcium chloride dissociates, separating the calcium ions from the chloride ions. This is an endothermic process, which absorbs energy.

  • The formation of bonds between water and the ions is very exothermic, releasing a lot of energy.

  • The overall result is that far more energy comes out of calcium chloride than is absorbed. The overall process is exothermic, and the water heats up.

 

1.16. Page 5

Lesson 2

Module 4—Properties of Solutions

Reflect and Connect

 

Dissolved Nutrients in Lakes

 

A photograph of Dr. David Schindler.

© Creative Services, University of Alberta

Dr. David Schindler is an internationally renowned ecologist at the University of Alberta. He has conducted extensive research on how human activities can damage freshwater reserves.

 

“Of all the environmental problems we face today, fresh water is probably the most important. Our lakes and streams are Mother Nature’s sewers, and the water tends to reflect everything we do. There exists here a myth of abundance with regard to fresh water. We are told that Canada has more fresh water than any other country. In fact, there is a lack of fresh water available to the most populated parts of Canada, and most fresh water is in the north or flowing towards the north. Alberta, in particular, has a water deficit: evaporation is greater than precipitation.”

 

In the late 1960s, Dr. Schindler conducted research in the ELA (Experimental Lakes Area), a set of 58 lakes in the Precambrian Shield of northwestern Ontario. This set of lakes is reserved for large-scale experiments of ecosystem stressors. One of Dr. Schindler’s main contributions to ecology was his research on the effect of phosphorus-based fertilizers and detergents on lakes. Dr. Schindler helped show that not all nutrients dissolved in water are necessarily beneficial—they can have unforeseen consequences when imposed on delicate ecosystems.

 

Self-Check

 

SC 9. When a solid is dissolved in solution, it seems to disappear. Why does this happen? Is dissolving a physical change or chemical change?
 
SC 10. Explain the difference between an endothermic process and an exothermic process.

 

SC 11. Is it theoretically possible to dissolve a substance without using energy?

 

SC 12. Why is it important to consider the breaking of hydrogen bonds between water molecules when calculating the net energy of dissolving a solid?

 

Check your work.
Self-Check Answers

 

SC 9. Dissolving occurs when the molecules of a liquid surround the solute, resulting in dissociation, ionization, or dispersion. Dissolving a substance is a physical change since no new substances are produced.

 

SC 10. An endothermic process draws energy from the surroundings. An observation of many endothermic changes is a reduction in the temperature of the system or matter being investigated. For example, water evaporation is endothermic. Your skin feels colder when water evaporates because energy is drawn from your skin to fuel the evaporation.

 

An exothermic process releases energy to the surroundings, increasing the temperature. For example, the chemical reaction in a heat pack is exothermic. The surplus energy warms up the solution and the heat pack feels hot.

 

SC 11. No. The act of dissolving always requires energy to dissociate, ionize, or disperse a substance.

 

SC 12. Water molecules do not simply float around in isolation; they are closely packed with other water molecules and experience intermolecular forces. Before a group of water molecules can come together to surround and dissolve a solute, they must first break free from the hydrogen bonds with adjacent water molecules. Therefore hydrogen bonds between water molecules can be considered to have attractive forces between them, some of which must be overcome in order for associations to occur between water molecules and the solute particles. Given the large number of water molecules involved in this process, the energy can be significant even though it is typically far less than the energy required to break the ionic bond.

 

Reflect on the Big Picture

 

Proactive Citizen Projects

 

You may have selected your topics for the Proactive Citizen Project topics listed in the Module 4 Summary and Assessment document. As you work these projects, save your work to your course folder. You will receive information later in this module about submitting your completed work to your teacher.

 
Assessment

 

There is no Module 4: Lesson 2 Assignment.

 

In this lesson you continued your work on two of the Proactive Citizen Projects listed in the Module 4 Summary and Assessment document. As you work on these projects, save your work to your course folder. You will receive information later in this module about submitting your completed work to your teacher.

 

1.17. Page 6

Lesson 2

Module 4—Properties of Solutions

Lesson Summary

 

In this lesson you explored the following essential questions:

  • How did Arrhenius contribute to the understanding of electrolytes, acids, and bases?
  • What does it mean to dissolve a substance?
  • What role does energy have in the dissolving of a solid?

 

Dissolving a solute might seem quite simple, but as you have learned from your work in this lesson, many events at the molecular level are involved with this process. Imagine for a moment what life would be like if dissociation and intermolecular forces did not exist. Without dissociation, a beaker of water could not dissolve ionic solids—they would simply accumulate at the bottom. Without intermolecular forces, sugars could not dissolve, and you would be deprived of an energy source required for survival.

 

Now that you have learned about the many chemical events required to dissolve a solid, you can appreciate how complex processes at the molecular level can result in simplicity at the macroscopic level. While billions of bonds are being broken and formed in the endothermic process of dissolving ammonium chloride in a cold pack, you get to simply squeeze the bag, shake, and apply.

 

Lesson Glossary

 

Arrhenius acid: a substance that ionizes in water to produce hydrogen ions

 

Arrhenius base: an ionic compound that dissociates in water to produce hydroxide ions

 

dissociation: the separation of ions that occurs when an ionic compound dissolves in water

 

endothermic: absorbing energy from the surroundings

 

exothermic: releasing energy to the surroundings

 

ionization: a process by which a neutral atom or molecule is converted to an ion; the reaction of substances in water to create ions


1.18. Lesson 3 Intro

Lesson 3

Module 4—Properties of Solutions

Lesson 3—Solubility

 

Get Focused

 

A photograph shows the end of an iron pipe. Inside the pipe is an orange-coloured mass that surrounds the inside of the pipe.

© L Kragt Bakker/shutterstock

Have you ever had a shower that left you feeling like you weren’t able to wash all the soap off your body?  Tap water, especially in Alberta is often “hard” due to the presence of calcium and magnesium dissolved in the water. While hard water is safe to drink, there are problems associated with its use.

 

The minerals found in hard water have a tendency to form limescale deposits in household pipes, reducing the flow of water. Also, kitchen and bathroom fixtures that regularly use tap water may build up soap scum due to the fact that calcium and magnesium can react with detergents to form a residue that is difficult to rinse away. You may wish to view some examples of problems caused by hard water.

 

In this lesson you will learn about the solubility of various substances in water. You will also learn about the chemistry of water softeners, a common way to treat hard water.

 

Essential Questions
  • What are saturated solutions?
  • How can you predict the solubility of a substance in water?
  • How is dynamic equilibrium involved when studying saturated solutions?
Module 4: Lesson 3 Assignment

 

Save a copy of the Module 4: Lesson 3 Assignment to your course folder. Later in the lesson you will receive more information about how to complete this assignment and when to submit it to your teacher.

 

In this lesson you will continue to work on the two Proactive Citizen Projects listed in the Module 4 Summary and Assessment document. The topics and a scoring guide are available in the Module 4 Summary and Assessment document.

 

You must decide what to do with the questions that are not marked by the teacher.

 

Remember that these questions provide you with the practice and feedback that you need to successfully complete this course. You should respond to all the questions and place those answers in your course folder.

 

1.19. Page 2

Lesson 3

Module 4—Properties of Solutions

Explore

 

Try This

 

A photograph shows a spoon held above a white surface. Inside the spoon are many small white crystals. Some of the crystals are falling from the spoon.

© Stephen Beaumont/shutterstock

Fill a cup with approximately 100 mL of lukewarm water. Add a teaspoon of salt, stirring until all of the salt has dissolved. Repeat this procedure until you notice salt on the bottom that does not dissolve, no matter how much you stir.

 

What you are observing is an example of a saturated salt solution. You were probably able to get 5 teaspoons to dissolve, but the sixth one would not.

 

Now pour the solution into another glass, making sure none of the undissolved salt is transferred. Put this glass in your freezer for about half an hour, and then observe it. Record your observations. Allow the cooled salt water from the freezer to sit at room temperature. Record any changes that occur.

 

Can you explain the changes that occurred with the salt water as you cooled it and allowed it to warm?

 

Send your observations and your explanation for these changes to your teacher. Where possible, use appropriate terms that have been introduced in Lessons 1 and 2.

 

 

1.20. Page 3

Lesson 3

Module 4—Properties of Solutions

Read

 

Saturated Solutions

 

saturated solution: a solution that contains the maximum quantity of solute for a specified temperature; in which no more solute will dissolve at a specified temperature; at maximum solute concentration

 

solubility: the concentration of a saturated solution at a specified temperature

In the Try This activity above you observed a saturated solution undergoing change.

 

There is a limit to how much solute can be dissolved in a solvent. You may notice this when you pour sugar into tea or coffee. If you pour in too much, the sugar will simply sit at the bottom of the cup. The following illustration shows what happens when maximum solubility is reached.
 

The solubility of NaCl(s) in water at 20 °C is 36 g/100 mL. What that means is only 36 g of solute may be absorbed by 100 mL of water at this temperature.

 

The diagram shows four identical beakers, each half-filled with water. Above each beaker is a drawing of a spoon containing a powder.  The spoon above the first beaker has the maximum amount of powder in it. The contents of the beaker appear light grey in colour. The label below the first beaker reads: There are 50g of salt in the spoon. The spoon above the second beaker has some of the powder removed. The contents of the second beaker appears light blue in colour. The label below the second beaker reads: 30g is poured into the solution. All the solute dissolves. The spoon above the third beaker has most of the powder removed. The contents of the third beaker appears light blue in colour. Some white powder is shown on the bottom of the beaker. The label below the third beaker reads: Another 10g is poured into the solution. 4g of undissolved solute remains on the bottom. The spoon above the fourth beaker has all of the powder removed. The contents of the fourth beaker appears light blue in colour. A larger quantity of white powder is shown on the bottom of the beaker. The label below the fourth beaker reads: When the rest of the salt is poured into the solution, 14g of undissolved solute remains on the bottom.


 

A photograph shows a colourless drinking glass containing a light brown liquid. Within the liquid are many ice cubes and small spherical bubbles.

© Claudio Baldini /shutterstock

To learn about how temperature and pressure affect the solubility of solids, liquids, and gases in water, read pages 221 and 222 in your textbook.

 

Hard Water vs. Soft Water

 

In the introduction to this lesson, you learned about some of the problems associated with hard water.

 

What is soft water, and how does a water softener work? Soft water is free of calcium and magnesium ions. A water softener works because of the presence of an ion-exchange resin, which is typically found in the water filter as small beads. The ion-exchange resin functions by removing magnesium and calcium ions from the water in a process that exchanges them for sodium ions. In other words, the price you pay for getting soft water is that the water becomes salty.

Some of the benefits of using soft water in the home include the following:

  • Soap lathers more readily and does not leave a residue (soap scum).
  • Laundry is brighter and can endure more washings before fading.
  • Pipes do not develop buildup, and hot water tanks last longer.

Some of the negative issues include the following:

  • Calcium and magnesium are required by the body, and the water-softening process removes these valuable minerals.

  • The characteristic taste of water is caused by the presence of minerals. Removing the minerals makes the water taste different. Some people may like the taste, but that is a matter of preference.

The process of softening water increases the sodium content of water. This results in the water being slightly salty.

 

1.21. Page 4

Lesson 3

Module 4—Properties of Solutions

Self-Check

 

SC 1. Use the kinetic molecular theory to explain why solids and gases have opposite solubility characteristics.

 

SC 2. The solubility of sucrose is 180 g/100 mL at 0 °C. How much sugar is dissolved in the following situations?

  1. 170 g is placed in 100 mL of water.
  2. 180 g is placed in 100 mL of water.
  3. 190 g is placed in 100 mL of water.
  4. 600 g is placed in 300 mL of water.

SC 3. The solubility of nitrogen gas is 0.003 g/100 mL at STP conditions. How much nitrogen gas is dissolved in the following situations?

  1. 0.002 g is bubbled in 100 mL of water.
  2. 0.003 g is bubbled in 100 mL of water.
  3. 0.004 g is bubbled in 100 mL of water.
  4. 0.010 g is bubbled in 400 mL of water.

SC 4. Explain the difference between the terms solubility and saturated solution.

 

SC 5. If you have a solution of table salt dissolved in water, describe three ways you could turn this into a saturated solution.

 

SC 6. Give two reasons why stains are easier to remove in warm water than in cold water.

 

SC 7. In the following graph, which substance is likely a gas?

 

A graph is shown. The vertical axis is titled Solubility. The horizontal axis is titled Temperature. Three lines are shown. Line A starts midway up the graph and extends upward at a 45 degree angle. Line B starts two-thirds of the way on the vertical axis and gently slopes downward. Line C starts three-quarters of the way up the vertical axis and extends directly across the graph.


 

Check your work.
Self-Check Answers

 

SC 1. Solids dissolve better in warm solutions because the water molecules have more energy to break bonds holding the solid together. Gases dissolve worse in warm solutions because the gas molecules have more energy and move faster, escaping the solution.

 

SC 2.

  1. All 170 g will dissolve.
  2. All 180 g will dissolve.
  3. Only 180 g will dissolve. 10 g will remain undissolved.
  4. First, determine the maximum amount of solute that can dissolve. If 100 mL can hold 180 g, then 300 mL can hold 540 g. If 600 g of sucrose is placed in the solution, only 540 g will dissolve. The other 60 g will remain undissolved.

SC 3.

  1. All 0.002 g will dissolve.
  2. All 0.003 g will dissolve.
  3. Only 0.003 g will dissolve. 0.001 g will escape the solution.
  4. First, determine the maximum amount of solute that can dissolve. If 100 mL can hold 0.003 g, then 400 mL can hold 0.012 g. If 0.010 g of nitrogen is placed in the solution, all of it will dissolve.

SC 4. The term solubility refers quantitatively to the maximum amount of solute that can be dissolved in water. It can be expressed as a number with units of g/mL (or mol/L). A saturated solution is a qualitative term describing a solution that will not dissolve any more solute at a given temperature.

 

The two terms may be used in a sentence as follows:

 

A saturated solution of sucrose has a solubility of 487 g/100 mL at 100 ºC.

 

SC 5. Three ways you could turn this solution into a saturated solution are as follows:

  • You could add more NaCl(s) until the solution is saturated.
  • You could cool the solution to reduce the solubility.
  • You could allow water to evaporate from the solution.

 

SC 6. At warmer temperatures, both the detergent and stain substances will have a higher solubility in water. Also, with the increase in temperature, the rate of chemical reactions increases.

 

SC 7. Substance B is likely a gas because the solubility decreases as temperature increases.

 

1.22. Page 5

Lesson 3

Module 4—Properties of Solutions

Read

 

Understanding the Solubility Table

 

One of the most important tools you will use while doing chemistry is a solubility table. A solubility table is used to determine the state of an ionic substance when it is placed in water. Copies of this table are also located inside the back cover of your textbook and in the Chemistry Data Book.

 

Ion

H+, Na+, NH4+, NO3, ClO3, ClO4, CH3COO

F

Cl, I, Br

SO42–

CO32–, PO43–, SO32–,

IO3, C2O42–

S2–

OH

Solubility greater than or equal to 0.1 mol/L (very soluble)

most

except:


RbClO4, CsClO4, AgCH3COO, Hg2 (CH3COO)2

most

most

most

H+, Na+, K+, NH4+

Except: Li2CO3

H+, Na+, K+, NH4+, Li+, Ni2+, Zn2+

Except:

Co(IO3)2,

Fe2(C2O4)3

H+, Na+, K+, NH4+, Li+, Mg2+, Ca2+

H+, Na+, K+, NH4+, Li+, Sr2+, Ca2+, Ba2+

Solubility less than 0.1 mol/L (slightly soluble)

none

Li+, Mg2+, Ca2+, Sr2+, Ba2+, Fe2+, Hg22+, Pb2+

Cu+, Ag+, Hg22+, Hg2+, PbI2

Ca2+, Sr2+, Ba2+, Hg22+, Pb2+, Ag+

most

most

most

most

 

You may wonder why the solubility table says “very soluble” and “slightly soluble” instead of simply saying a solution is aqueous or solid. The reason these phrases are used is because all substances dissolve to some extent, so even a relatively insoluble compound, like CaCO3(s), may have a few errant ions in solution. However, for the sake of simplicity, you are allowed to use the aqueous state (aq) for “very soluble” and the solid state (s) for “slightly soluble” because the vast majority of entities will exist in these states.

 

Example 1: Determine the state of calcium carbonate in water.

 

First, locate the carbonate ion in the top row, and then locate the calcium ion underneath. Since the calcium ion is not listed as one of the ions in the "very soluble" section, it must be in the “most” category.

 

Calcium carbonate has low solubility in water, so it can be written CaCO3(s).

 

Example 2: Determine the state of barium hydroxide in water.

 

First, locate the hydroxide ion in the top row, and then locate the barium ion underneath. Barium hydroxide has high solubility in water, so it can be written Ba(OH)2(aq).

 

While the solubility table provides a lot of useful information, it is limited to predicting the state of ionic solids in water. Since you will need to predict the states of many other substances in water, you should memorize the following rules and apply them when you write dissociation equations:

  • Elements have low solubility in water. For example, a copper wire in water would be Cu(s) and nitrogen gas bubbled through water is N2(g).
  • Liquid water is always written H2O(l). It is never written H2O(aq) because water cannot dissolve in itself.
  • All ions are soluble and written with the state (aq).
  • Polar molecules will dissolve in water to become aqueous solutions. Nonpolar molecules do not dissolve in water and retain their original state.

Now work through the following examples to put these four rules into use.

 

Example 3: Determine the state of ethanol, C2H5OH(l), in water.

 

Ethanol is a polar molecule, so it will dissolve in water to become C2H5OH(aq).

 

Example 4: Determine the state of octane, C8H18(l), in water.

 

Octane is a nonpolar molecule and does not dissolve. It stays as C8H18(l).

 

Example 5: State the major entities present when Sr(OH)2(s) is placed in water.

 

According to the solubility chart, Sr(OH)2(s) is highly soluble, so it will dissociate. The major entities present in water will be Sr2+(aq), OH(aq), and H2O(l). When you are asked to state the major entities present, coefficients are not required and water should be included in the list since solvent molecules also count.

 

Example 6: Write the balanced dissociation equation for sodium sulfate.

 

According to the solubility chart, Na2SO4(s) is soluble in water, so the balanced dissociation equation is

Na2SO4(s) → 2 Na+(aq) + SO42–(aq).
 
When you are asked to write a dissociation equation, coefficients are required. However, water does not need to be written in a dissociation equation since it is assumed to be present on both sides.

 

1.23. Page 6

Lesson 3

Module 4—Properties of Solutions

Self-Check

 

SC 8. For each of the following substances, state whether it has high or low solubility and list the major entities present when placed in water. The first row is done for you.

 

Substance to Be Placed in Water

Solubility

Major Entities Present

Ag

low

Ag(s), H2O(l)

SrCl2

 

 

HCl

 

 

HNO3

 

 

(NH4)2HPO4

 

 

C8H18

 

 

NH4NO3

 

 

Au(OH)3

 

 

CH4

 

 

O2

 

 

CaCO3

 

 

Ag2SO4

 

 

MgCl2

 

 

CH3OH

 

 

HF

 

 

 

SC 9. Each of the following substances was on the table in question 1. Explain how to predict the major entities present.

  1. C8H18

  2. O2

  3. CH4

  4. C2H5OH

SC 10. Complete the dissociation equations for each of the following substances in water. Make sure you balance the equation.

  1. Na2SO4(s) →

  2. HF(g) →

  3. Au(OH)3(s) →

  4. C6H12O6(s) →

  5. Zn(s) →

  6. Al2(SO4)3(s) →

  7. N2(g) →

Check your work.
Self-Check Answers

 

SC 8.

 

Substance to Be Placed in Water

Solubility

Major Entities Present

Ag

low

Ag(s), H2O(l)

SrCl2

high

Sr2+(aq), Cl(aq), H2O(l)

HCl

high

H+(aq), Cl(aq), H2O(l)

HNO3

high

H+(aq), NO3(aq), H2O(l)

(NH4)2HPO4

high

NH4+(aq), HPO42–(aq), H2O(l)

C8H18

low

C8H18(l), H2O(l)

NH4NO3

high

NH4+(aq), NO3(aq), H2O(l)

Au(OH)3

low

Au(OH)3(s), H2O(l)

CH4

low

CH4(g), H2O(l)

O2

low

O2(g), H2O(l)

CaCO3

low

CaCO3(s), H2O(l)

Ag2SO4

low

Ag2SO4(s), H2O(l)

MgCl2

high

Mg2+(aq), Cl(aq), H2O(l)

CH3OH

high

CH3OH(aq), H2O(l)

HF

high

H+(aq), F(aq), H2O(l)

 

SC 9.

  1. This is liquid octane, a nonpolar molecular substance. It will not dissolve in water.
  2. Elemental gases have low solubility in water and keep their original state.
  3. Methane is a nonpolar molecule that will not dissolve in water.
  4. Ethanol is a polar molecule that will dissolve in water.

SC 10.

  1. Na2SO4(s) → 2 Na+(aq) + SO42–(aq)
  2. HF(g) → H+(aq) + F(aq)
  3. Au(OH)3(s) → Au3+(aq) + 3 OH(aq)
  4. C6H12O6(s) → C6H12O6(aq)
  5. Zn(s) → Zn(s)
  6. Al2(SO4)3(s)→ 2 Al3+(aq) + 3 SO42–(aq)
  7. N2(g)→ N2(g)

 

1.24. Page 7

Lesson 3

Module 4—Properties of Solutions

Read

 

Dynamic Equilibrium

 

At the beginning of this lesson you completed a Try This exercise where you made observations and wrote explanations about what was occurring within a saturated solution.

 

dynamic equilibrium: the idea that there is a balance between two opposing processes (forward and reverse) occurring at the same rate

When the solution was cooled, you observed that salt crystals were seen on the bottom of the beaker. While it may appear the salt crystals are no longer dissolving, they actually are. The amount of solid appears to remain constant because even though some of the solid is dissolving, an equal amount of solid is crystallizing out of the solution. This process is called dynamic equilibrium.

 

Read the section “Explaining Saturated Solutions” on page on 224 in your textbook. Pay close attention to the description of the experimental evidence that was used to test the theory of dynamic equilibrium described on pages 225 and 226.

 

How does the figure below demonstrate the dynamic equilibrium in the saturated solution of salt water you observed earlier in this lesson?

 

A diagram shows an ionic crystal as alternating green and orange spheres arranged in three dimensions. The green spheres are labeled with a minus sign. The orange spheres are labeled with a plus sign. In the upper left corner an orange sphere is shown leaving the crystal. In the upper right corner a green sphere is shown leaving the crystal. In the bottom right corner an orange sphere is shown joining the crystal. In the bottom left corner a green sphere is shown joining the crystal.

 

In the dynamic equilibrium involving a salt crystal in a saturated solution, there is still dissociating, but the ions that leave are immediately replaced by other ions that enter the solid from the solution. This process is similar to having a party for 20 people—if two new guests arrive and two people leave, the total number of people present at the party remains the same.

 

Self-Check

 

SC 11. State two conditions required for a solution to be in dynamic equilibrium.

 

SC 12. While salt is being poured into a beaker that initially contains distilled water, would the system be in a state of dynamic equilibrium?

 

SC 13. Explain what is happening to a salt crystal in a dynamic equilibrium system.

 

SC 14. Describe an experimental technique to test for dynamic equilibrium in a saturated solution of strontium chloride.

 

Check your work.
Self-Check Answers

 

SC 11. Two opposing processes must be occurring at exactly the same rate. The solution must be in a closed system (the volume of water is constant, the amount of solute is constant, the temperature is constant, etc.).

 

SC 12. No. Dynamic equilibrium means two opposing processes must be occurring at exactly the same rate. When the salt is being poured in, it is dissolving at a far greater rate than it is crystallizing.

 

SC 13. A salt crystal is both dissolving and crystallizing at the same rate. As such, the mass of the crystal remains constant, even though it is constantly being broken and reformed.

 

SC 14. Create a saturated solution of strontium chloride with some undissolved solute visible at the bottom. Add a few drops of radioactive strontium chloride; then measure where the radiation is coming from within the solution. After time passes, if radiation is coming from within the solid, that means the radioactive sample has crystallized into the solid.

 

 

1.25. Lab

Lesson 3

Module 4—Properties of Solutions

Module 4: Lesson 3 Assignment

 

Retrieve the copy of the Module 4: Lesson 3 Assignment that you saved earlier in this lesson. You will use the following lab to complete Part 1 of your Module 4: Lesson 3 Assignment.

 

Lab: Shower of Lead(II) Iodide

 

View the “Shower of Lead(II) Iodide” video. You may be required to login with a username and password. Contact your teacher for this information.

 

Note: To start the video you must click inside the video window. The play button may not start the video.

 

Use the information contained on the video to answer the assignment questions. You may wish to replay sections of the video to obtain all your observations.

 

Save a copy of your work to your course folder. Later in the lesson you will receive instructions on when to submit the assignment to your teacher.

 

Module 4: Lesson 3 Assignment

 

Retrieve the copy of the Module 4 Lesson 3 Assignment that you saved earlier in this lesson. Complete the questions in Part 2 of the assignment. Save your work to your course folder.

 

1.26. Page 9

Lesson 3

Module 4—Properties of Solutions

Reflect and Connect

 

In the first three lessons of this module, you learned about the qualitative aspects of solution chemistry. Review the first three lessons and state eight things you learned, giving an example to support your statement. Here is one example:

“I learned that as the temperature of an aqueous solution increases, the solubility of a gas in the water decreases. For example, warm pop will go flat faster than cold pop.”

 

Also, discuss six things you learned in these lessons that have challenged your prior knowledge about solutions.
 
Save your lists in your course folder.

 

You may wish to share your list with other students using the class discussion area. If you do so, make sure to look at the posting of other students to see if there are similar aspects between the lists posted.

 

Going Beyond

 

Watch and Listen

 

Is it possible to make a solution supersaturated?   View the “Solutions: Unsaturated, Saturated, and Supersaturated video.” You may be required to login with a username and password. Contact your teacher for this information.

 

Reflect on the Big Picture

 

Proactive Citizen Projects

 

You may have selected your topics for the Proactive Citizen Project topics listed in the Module 4 Summary and Assessment document. As you work these projects, save your work to your course folder. You will receive information later in this module about submitting your completed work to your teacher.

 

Assessment

 

Submit the following item to your teacher:

  • Module 4: Lesson 3 Assignment

In this lesson you continued your work on two of the Proactive Citizen Projects listed in the Module 4 Summary and Assessment document. As you work on these projects, save your work to your course folder. You will receive information later in this module about submitting your completed work to your teacher.

 

1.27. Page 10

Lesson 3

Module 4—Properties of Solutions

Lesson Summary

 

In this lesson you explored the following essential questions:

  • What are saturated solutions?
  • How can you predict the solubility of a substance in water?
  • How is dynamic equilibrium involved when studying saturated solutions?

In this lesson you learned that solubility is an important aspect of solution chemistry. The solubility of a substance is directly linked to the temperature of the solution, and in the case of gases, external pressure can be a major solubility factor as well. Solubility rules can be used to successfully predict the states of elements and compounds in water. Finally, you learned about dynamic equilibrium, a theoretical explanation of what is happening in a saturated solution at the molecular level.

 

The first three lessons of this unit focused exclusively on qualitative aspects of solution chemistry. In Lessons 4 and 5, you will investigate the quantitative aspects of solutions.

 

Lesson Glossary

 

dynamic equilibrium: the idea that there is a balance between two opposing processes (forward and reverse) occurring at the same rate

 

immiscible: a term used to describe liquids that do not dissolve in each other

 

saturated solution: a solution that contains the maximum quantity of solute for a specified temperature; in which no more solute will dissolve at a specified temperature; at maximum solute concentration

 

solubility: the concentration of a saturated solution at a specified temperature

 

1.28. Lesson 4 Intro

Lesson 4

Module 4—Properties of Solutions

Lesson 4—Concentration I

 

Get Focused

 

A photograph of a water treatment facility. The photograph shows 14 open circular tanks containing water. A narrow bridge extends across each tank. Within each tank is an arm-like extension from its centre.

© Wade H. Massie/shutterstock

Now that you have considered where your drinking water comes from, how do you know if it is really safe to drink? Does it come from a well or a reservoir? How is it treated before it gets to your home? Who is accountable if something goes wrong with your tap water?

 

Various government agencies set safety standards that water treatment plants must adhere to. Since it is nearly impossible to remove all dissolved substances from a solution, maximum allowable concentrations are in place to protect those who drink the water.

 

In this lesson you will learn how concentration can be expressed using a variety of units. You will then use this knowledge to gain a better understanding of the chemistry associated with water quality.

 

Essential Question
  • How can the concentration of solute in a solution be expressed?
Assessment

 

There is no Module 4: Lesson 4 Assignment.

 

In this this lesson you will continue to work on the two Proactive Citizen Projects listed in the Module 4 Summary and Assessment section. The topics and a scoring guide are available in the Module 4 Summary and Assessment section.

 

You must decide what to do with the questions that are not marked by the teacher.

 

Remember that these questions provide you with the practice and feedback that you need to successfully complete this course. You should respond to all the questions and place those answers in your course folder.

 

1.29. Page 2

Lesson 4

Module 4—Properties of Solutions

Explore

 

Read

 

A diagram shows three fractions. One is upper case W over upper case W, the second is upper case W over upper case V, the third is upper case V over upper case V. The three letters ppm and ppb are also shown in the diagram.

Many terms are used to describe the concentration of a solution. A powdered drink mix added to a large quantity of water is called a dilute solution, whereas a powdered drink mix added to a small quantity of water is considered to be a concentrated solution.

 

Dilute and concentrated are qualitative terms that only have meaning in the context of comparing similar solutions. Saying a solution is dilute provides no information about the specific quantities of solute and solvent.


concentration: a property of solutions; the mass, volume, or number of moles of solute present in proportion to the quantity of solvent or total solution

 

Concentration is defined as the ratio of the quantities of solute to the total solution. This ratio can be written in a variety of ways. As you progress through your exploration of solution chemistry, you will encounter concentrations in many different forms. These forms of showing concentration will be important when you study the maximum allowable concentrations of contaminants in drinking water.

 

Percentage Concentrations

 

The next time you pick up a container, look at the label. Chances are that the liquid inside is a solution, and the label will express the concentration of a component. What might surprise you is that a variety of means to express concentration is used. In this section you will learn about the most common methods for expressing the concentration for commercial and other purposes.

 

Percentage Volume per Volume (% V/V)

 

Read and carefully work through “COMMUNICATION example 1” on page 203 in your textbook.

 

After you have completed your reading, work through the following example, followed by the Self-Check problems below.

 

Example 1: 40 mL of hydrogen peroxide is poured into 150 mL of water. Determine the % V/V concentration of this solution.

 

This question is different since the water volume is given instead of the total solution volume. It’s easy to get the solution volume. It is 40 mL + 150 mL = 190 mL.

 

Now, divide the volume of hydrogen peroxide by the total volume of the solution.

 

 

Self-Check

 

SC 1. A 350-mL solution contains 140 mL of ethanol. Determine the % V/V concentration of this solution.

 

SC 2. A 450-mL solution contains 160 mL of liquid hydrogen peroxide. Determine the % V/V concentration of this solution.

 

SC 3. 65 mL of methanol is poured into 230 mL of water. Determine the % V/V concentration of this solution.

 

SC 4. A 2.1-L solution contains 54 mL of methanol. Determine the % V/V concentration of this solution.

 

SC 5. A vinegar solution contains acetic acid in water and is labelled 11% V/V. Express this concentration as mL per 100 mL of solution.

 

Check your work.
Self-Check Answers

 

SC 1.

 

 

SC 2.

 

 

SC 3. Remember, you must use the total volume of the solution (65 mL + 230 mL = 295 mL).

 

 

SC 4. Remember, the volumes need to be expressed in the same units.

 

 

SC 5.

 

 

 

1.30. Page 3

Lesson 4

Module 4—Properties of Solutions

Read
 
Percentage Weight per Volume (% W/V)
 

A photograph shows a night time scene in which police officers wearing reflective vests are directing cars to stop. Other police officers are talking with the drivers of the stopped vehicles.

© Larry St. Pierre/Shutterstock

A percentage weight per volume (% W/V) concentration expresses the mass of solute as a percentage of total solution volume. Breathalyzers use % W/V percentages to indicate the alcohol content in blood. If a breathalyzer gives a reading of 0.05% W/V, it means 0.05 g of alcohol is present for every 100 mL of blood.

 

To learn more about this calculation, read from the last paragraph on page 203 to “COMMUNICATION example 2” on page 204 in your textbook.

 

After you have completed this reading, answer the Self-Check questions below.

 

Self-Check

 

SC 6. A student dissolved 16 g of sodium bicarbonate in water to make a 135-mL solution. Determine the % W/V concentration of the resulting solution.

 

SC 7. In making a 860-mL solution, 71 g of copper(II) sulfate was dissolved in water. Determine the % W/V concentration of copper(II) in the solution.

 

SC 8. Suppose 0.020 kg of sodium bicarbonate is dissolved in water to make an 810-mL solution. Determine the % W/V concentration of the resulting solution.

 

SC 9. A solution contains 9.3% W/V ethanol. Express this in units of g/100 mL.

 

SC 10. A breathalyzer gives a reading of 0.120% W/V. Determine the mass (in mg) of alcohol present in 100 mL of blood.

 

Check your work.
Self-Check Answers

 

SC 6.

 

 

SC 7.

 

 

SC 8.

 

 

SC 9.

 

 

SC 10.

 

 

 

There is 120 mg present in 100 mL of blood.

 

1.31. Page 4

Lesson 4

Module 4—Properties of Solutions

Read

 

Percentage Weight per Weight (% W/W)

 

 A photograph shows toothpaste being applied to a toothbrush

© RTimages/shutterstock

A percentage weight per weight (% W/W) concentration expresses the mass of a substance as a percentage of total mass. % W/W concentrations may be used in many different contexts, including mixtures that are not true solutions. For example, toothpaste may read sodium monofluorophosphate (0.76% W/W). This means that 0.76 g of sodium monofluorophosphate is found in every 100 g of toothpaste.

 

Work through “COMMUNICATION example 2” on page 204 of your textbook. Then work through Example 2 below.

 

Example 2: A 0.43-kg solution contains 98 mg of potassium iodide. Calculate the % W/W concentration of this solution.

 

To calculate the % W/W concentration, the units for mass must be the same. For this example, both masses were converted into grams, although the conversion could have been milligrams or kilograms. The key thing is that both the numerator and denominator have identical units.

 

 

Self-Check

 

SC 11. A 9.83-g sterling silver ring contains 0.76 g of copper. Determine the % W/W concentration of the copper in the ring.

 

SC 12. A salt solution has a mass of 354 g. After evaporating all the water, 58 g of solute remain. Determine the % W/W concentration of the salt in solution.

 

SC 13. 72 mg of sodium nitrate is dissolved in 450 mg of water. Determine the % W/W concentration of the sodium nitrate.

 

SC 14. A 0.51-kg solution contains 89 mg of copper(II) sulfate. Calculate the % W/W concentration of this solution.

 

SC 15. A solution contains 2.3% W/W magnesium chloride. Express this in mg/100 mg.

 

Check your work.
Self-Check Answers

 

SC 11.

 

 

SC 12.

 

 

SC 13. Remember, you must use the total mass of the solution (72 mg + 450 mg = 522 mg).

 

 

SC 14. Remember, the masses must be expressed in the same units. In this case, both masses were converted into grams (g).

 

 

SC 15.

 

 

Summary of Percentage Concentrations

 

What to Remember When Using Each Type of Calculation

% V/V Calculations

% W/V Calculations

% W/W Calculations

Units

Make sure the solute and solution volumes are the same units (both expressed as mL or L).

The mass (numerator) will be in grams (g) and the volume (denominator) will be in millilitres (mL).

Make sure that both solute and solution masses are the same units (g or kg) before dividing to get the percentage.

What the Fraction Means

The volume of solute divided by the total (combined) volume of the solution. (The combined volume can be found by adding solute and solvent, provided the units are the same.)

The mass of the solute divided by the total volume of the solution. (In % W/V solutions, the solute and solvent are not added to get the total volume because the units are different.

The mass of solute divided by the total (combined) mass of solution. (The combined mass can be found by adding solute and solvent, provided the units are the same.)

Word Description for Expressing Concentration This Way

“ ______ mL of solute per 100 mL of solution.”

“ ______ g of solute per 100 mL of solution.”

“ ______ g of solute per 100 g of solution.”

 

1.32. Page 5

Lesson 4

Module 4—Properties of Solutions

Read

 

Parts per Million/Billion Concentrations

 

Parts per Million

 

A photograph of a bathtub.

© Nikola Hristovski/shutterstock

Sometimes the concentration of solute in a solution is very small. To communicate the concentration of such solutions, parts per million or parts per billion concentrations are used.

 

You may have heard reports on climate change often refer to the ppm concentration of carbon dioxide in the atmosphere. A part per million may be thought of as one drop of water in a bathtub full of water or as 1 second every 11.6 days.

 

Read ”Parts per Million Concentration” and “COMMUNICATION example 3” on pages 204 and 205 in your textbook.

 

Parts per million, as the name suggests, requires that the mass of solute be a million times less than the mass of solution. For that reason, the units expressing solute are typically milligrams (mg), whereas the units expressing solvent are typically kilograms (kg). This leads to a ppm concentration in mg/kg. Water is a unique solvent in that 1 L has a mass of 1 kg. As such, ppm concentrations in water can be expressed as mg/L instead of mg/kg. In this course you can always assume that water is the solvent unless specifically told otherwise. The following summarizes the three main ways you can approach ppm calculations:

 

Equivalent fractions for calculating parts per million concentration are shown. Milligrams of solute per kilogram of solution, milligrams of solute per litre of solution, and grams of solute per grams of solution all multiplied by 10 exponent 6.



This example shows how to convert one means of expressing concentration to another.

 

Example 3: Express 38 ppm as a % W/W concentration.

 

First, convert from ppm into mg/kg.

 

 

Next, express the numerator and denominator with the same unit. This is required for % W/W concentration calculations. In this example, convert the denominator from kilograms into milligrams.

 

 

Finally, divide and express a % W/W concentration.

 

 

For more practice on calculations involving concentration, carefully work through “COMMUNICATION examples” 5, 6, and 7 on page 207 in your textbook.

 

Self-Check

 

SC 16. 80 mg of potassium chloride is dissolved in water to make a 0.85-L solution. Express the concentration in ppm.

 

SC 17. 5.2 g of sodium nitrate is dissolved in water to make a 290-L solution. Express the concentration in ppm.

 

SC 18. 29 g of magnesium sulfate is dissolved in water to make a 0.80-kg solution. Express the concentration in ppm.

 

SC 19. 3.4 g of sucrose is dissolved in water to make a 759-g solution. Express the concentration in ppm.

 

SC 20. 0.050 g of sodium chloride is dissolved in water to make a 600-g solution. Express the concentration in ppm.

 

SC 21. 0.020 kg of lithium bromide is dissolved in water to make a 600-kg solution. Express the concentration in ppm.

 

SC 22. Express 780 ppm as a ratio in units of mg/L.

 

SC 23. Express 41 ppm as a % W/W concentration.

 

Check your work.
Self-Check Answers

 

SC 16.

 

 

SC 17.

 

 

SC 18.

 

 

SC 19.

 

 

SC 20.

 

 

SC 21.

 

 

SC 22.

 

 

SC 23.

 

 

Going Beyond

 

Parts per Billion

 

Recent improvements to the technology used to detect small quantities of substances has led to reporting concentrations at the parts per billion level. More information on how this calculation is performed with self-check problems can be accessed here.

 

1.33. Page 6

Lesson 4

Module 4—Properties of Solutions

Reflect and Connect

 

One of the more interesting field trips you may be able to do is to visit the water treatment facility in your local area. If you are unable to visit a facility directly, you may wish to view the video below.

 

Watch and Listen

 

You may wish to take a virtual tour of the City of Saskatoon's water treatment plant. You can find this virtual tour on the Internet using the combined search terms “Saskatoon,” “water treatment,” and “events.”

 

Reflect on the Big Picture

 

Proactive Citizen Projects

 

A photograph shows a drinking glass being filled with water from a kitchen tap.

© Muriel Lasure/shutterstock

You may have selected your topics for the Proactive Citizen Project from the topics listed in the Module 4 Summary and Assessment document. As you work on these projects, save your work to your course folder. You will receive information later in this module about submitting your completed work to your teacher.

 

If you have selected one of the topics related to guidelines for drinking water, you may want to view this additional information about the government’s role in ensuring water quality.

 

Assessment

 

There is no Module 4: Lesson 4 Assignment.

 

In this lesson you continued your work on two of the Proactive Citizen Projects listed in the Module 4 Summary and Assessment document. As you work on these projects, save your work to your course folder. You will receive information later in this module about submitting your completed work to your teacher.

 

 

1.34. Page 7

Lesson 4

Module 4—Properties of Solutions

Lesson Summary

 

In this lesson you explored the following essential question:

  • How can the concentration of solute in a solution be expressed?

You have performed calculations to express the concentration of various solutions as % V/V, % W/V, % W/W, and parts per million. Each means to express concentration has a purpose and a practicality about it. In the next lesson you will learn about another way to express concentration—one that has greatest use in the laboratory when chemical reactions are studied.

 

Lesson Glossary

 

concentration: a property of solutions; the mass, volume, or number of moles of solute present in proportion to the quantity of solvent or total solution

 

1.35. Lesson 5 Intro

Lesson 5

Module 4—Properties of Solutions

Lesson 5—Concentration II

 

Get Focused

 

A photomicrograph of plankton. The organism appears as a hollow sphere with spikes that extend from its surface.

© din/Shutterstock

Now that you have an understanding of the regulations protecting your drinking water from harmful levels of contaminants, it is time to consider how contaminants affect the rest of the water system.

 

The water in rivers and lakes is a necessity of life for many organisms, including those at the bottom of the food chain. The term plankton refers to marine and freshwater organisms that live in water and serve as food for larger animals.

 

If plankton live in water contaminated with mercury, plankton will accumulate the toxin over time. Fish consume a large amount of plankton and, in doing so, accumulate the mercury stored in the plankton. This process continues all the way up the food chain and presents a significant health concern for higher-order mammals, including humans.

 

The process described here is called biomagnification, and it is a serious environmental concern.

 

In Canada’s North, the traditional Inuit way of life is threatened because the food supply contains dangerous levels of mercury. In this lesson you will learn how some of the products in your home pollute the water supply and contribute to biomagnification.

 

Essential Questions
  • How can the concentration of solute in a solution be expressed?

  • How do you calculate amount concentration and determine the concentrations of chemical species produced by dissociation?

  • How are solutions prepared in a lab?
Module 4: Lesson 5 Assignment

 

Save a copy of the Module 4: Lesson 5 Assignment to your course folder. Later in the lesson you will receive more information about how to complete this assignment and when to submit it to your teacher.

 

In this lesson you will continue to work on the two Proactive Citizen Projects listed in the Module 4 Summary and Assessment section. The topics and a scoring guide are available in the Module 4 Summary and Assessment section.

 

You must decide what to do with the questions that are not marked by the teacher.

 

Remember that these questions provide you with the practice and feedback that you need to successfully complete this course. You should respond to all the questions and place those answers in your course folder.

 

1.36. Page 2

Lesson 5

Module 4—Properties of Solutions

Explore

 

Discuss

 

A photograph of water being released from a large pipe into a stream.
© 2008 Jupiterimages Corporation

Photograph of a young woman holding a fish in one hand and her nose with her other hand.

© 2008 Jupiterimages Corporation


 

Historically, people believed that diluting any type of substance renders it permanently harmless. A foul odour that dissipates no longer smells bad, and red food dye poured into a vast body of water will eventually vanish. But do these substances really disappear? Use relevant chemical concepts to explain how the dilution of a substance is not a way to treat pollution.

If “The solution to pollution is NOT dilution,” then what processes can be used to treat waste? Consider what you have learned in this lesson about dissolving, solubility, and solutions. Is it a good strategy to dilute solutions containing harmful substances?  

 

Share your thoughts with your teacher or other students using your class discussion area.

 

1.37. Page 3

Lesson 5

Module 4—Properties of Solutions

Read

 

The formula to use to calculate molar concentration. Lower case c equals lower case n divided by upper case V.

In Lesson 4 you learned to express concentration as % V/V, % W/V, % W/W, and in parts per million. While labels like percentage weight per volume are great for consumer products, and parts per million is often used for environmental work, chemists in a lab typically express concentration using another set of units. In a previous science course you learned about the mole, the chemical quantity used to express matter. Do you remember what a “mole” is? Later, in Modules 5 and 6, you will see that expressing quantities of substances using moles is favoured because these values can be used to predict quantities of other substances involved in a chemical reaction.

 

To review your understanding of the mole, read page 51 in your textbook.

 

amount concentration: the proportion of solute (in moles) to volume of solution

In this lesson you will learn how to calculate amount concentration. You will also learn how amount concentration can be applied to a wide variety of situations, such as dilution and solution preparation in a lab.

 

Amount Concentration

 

Amount concentration expresses the solute in number of moles and the volume in litres. In many cases, you will have to convert a given mass into a number of moles before finding the amount concentration.

 

Two formulas are shown. The one on the left is the formula to calculate moles. Moles, lower case n, equals mass, lower case m, divided by molar mass, upper case m. The formula on the right is the concentration formula described earlier in the lesson. Lower case c equals lower case n divided by upper case V.

 

Use this formula to find the number of moles.

n = number of moles (mol)
m = mass (g)
M = molar mass (g/mol)

Use this formula to find the amount concentration.

c = amount concentration (mol/L)
n = number of moles (mol)
V = volume (L)



Read "Amount Concentration" on page 205 in your textbook and work through “COMMUNICATION example 4.” Carefully work through the additional example below.

 

Example 1: Determine the amount concentration of 0.42 mol of magnesium sulfate dissolved in a 200-mL solution.

 



Example 2: Determine the amount concentration of 3.0 g of copper(II) nitrate dissolved in a 200-mL solution.

 

 

First, determine the number of moles of solute.

 

 

Now, calculate the amount concentration.

 

 

The amount concentration of the copper(II) nitrate solution is 0.080 mol/L.

 

Self-Check

 

SC 1. Determine the amount concentration of 6.3 mol of magnesium sulfate dissolved in 5.4 L of solution.

 

SC 2. Determine the amount concentration of 2.0 g of iron(III) chloride dissolved in 50 mL of solution.

 

SC 3. Determine the amount concentration of 150 mg of sodium chloride dissolved in 47.0 mL of solution.

 

Check your work.
Self-Check Answers

 

SC 1.

 



The amount concentration of the magnesium sulfate solution is 1.2 mol/L.

 

SC 2.

 

 

Now, calculate the amount concentration.

 

 

The amount concentration of the iron(III) chloride solution is 0.25 mol/L.

 

SC 3.

 

 

First, determine the number of moles of solute.

 

 

Now, calculate the amount concentration.

 

 

The amount concentration of the sodium chloride solution is 0.0546 mol/L.

 

 

1.38. Page 4

Lesson 5

Module 4—Properties of Solutions

Read

 

Formulas are often required to be manipulated in order to solve for a desired quantity. The following diagrams show how the two formulas used in these examples can be manipulated.

 

Derivations of the equations for moles and concentration are shown.The equation for moles can be rearranged as: Lower case m equals lower case n multiplied by upper case M and as upper case M equals lower case m divided by lower case n. The equation for concentration can be rearranged as: Lower case n equals lower case c divided by upper case V, and as upper case V equals lower case n divided by lower case c.


 

Use the manipulated formulas as you work through “SAMPLE problem 5.1” and “COMMUNICATION examples” 10 and 11 on pages 209 and 210 of your textbook and Example 3 below.

 

Example 3: What volume is required to make a 0.54-mol/L solution with 21 g of sodium hydroxide?

 

The mass of NaOH is given. Convert the mass to number of moles, and then determine the volume.

 

 

First, determine the number of moles of solute.

 

 

Now, calculate the volume.

 

 

The volume of sodium hydroxide required is 0.97 L.

 

Self-Check

 

SC 4. What mass of sodium sulfate is present in 1.20 L of a 0.23-mol/L solution?

 

SC 5. What mass of magnesium phosphate is present in 5.00 L of a 230-mmol/L solution?

 

SC 6. What volume of solution is required to make a 0.86-mol/L solution with 18 g of ammonium nitrate?

 

SC 7. What volume of solution is required to make a 0.55-mol/L solution with 0.29 kg of sodium hydroxide?

 

Check your work.
Self-Check Answers

 

SC 4.

 

 

First, determine the number of moles of sodium sulfate.

 

 

Now, calculate the mass of sodium sulfate.

 

 

39 g of sodium sulfate is present.

 

SC 5.

 

 

First, determine the number of moles of magnesium phosphate.

 

 

Now, calculate the mass of magnesium phosphate.

 

 

302 g of magnesium phosphate is present.

 

SC 6.

 

 

First, determine the number of moles of solute.

 

 

Now, calculate the volume.

 

 

0.26 L of solution is required.

 

SC 7.

 

 

First, determine the number of moles of solute.

 

 

Now, calculate the volume.

 

 

13 L of solution is required.

 

1.39. Page 5

Lesson 5

Module 4—Properties of Solutions

Read

 

Ion Concentrations

 

A diagram depicts the dissociation of magnesium chloride. On the left of the arrow one purple sphere labelled Mg 2 plus is joined to two green spheres each labeled Cl minus. On the right side of the arrow the purple sphere is shown alone separated by the plus sign and the two separated green spheres.

Recall from previous lessons that many substances dissociate in water to form ions. It is possible to calculate the concentration of these ions using amount concentrations and a balanced chemical formula. Read “Concentration of Ions” on pages 210 and 211 in your textbook for more information on the effect dissociation has on the ion concentration in a solution. Then work through “COMMUNICATION examples” 12, 13, and 14 on pages 211 and 212.

 

Self-Check

 

SC 8. Determine the amount concentration of calcium ions and acetate ions in a 0.81-mol/L solution of calcium acetate.

 

SC 9. Determine the amount concentration of the sodium ions and carbonate ions in a 0.65-mol/L solution of sodium carbonate.

 

SC 10. Determine the amount concentration of the ammonium ions and the phosphate ions in a 1.15-mol/L solution of ammonium phosphate.

 

SC 11. Determine the amount concentration of potassium ions and dichromate ions in a solution made by dissolving 42.5 g of potassium dichromate to make a volume of 160 mL.

 

SC 12. What mass of aluminium chloride must be dissolved to make 52 L of solution with a chloride-ion concentration of 0.45 mol/L?

 

Check your work.

 

1.40. Page 6

Lesson 5

Module 4—Properties of Solutions

Read

 

Preparing Solutions

 

A photograph of multicoloured antacid tablets on a table next to an open pill container.

© Linda Muir/shutterstock

Many solutions found in a lab are not actually bought as solutions but as solutes—the solutions are made in the lab by dissolving the solute in water. This procedure greatly reduces the transportation costs of bringing chemical solutions to the end user. A bottle of antacid tablets is economical since you can make 100 antacid solutions from an initial purchase of five dollars. If these 100 solutions all had to be bought separately as solutions, they would cost hundreds of dollars!

 

Preparing solutions requires the use of specialized glassware. Using appropriate glassware allows for the preparation of solutions with precise concentrations. Here are some of the specialized glassware you will use in preparing solutions.

 


Volumetric Flask

 

A photograph of a volumetric flask. The bottom of the flask has a bulb shape and the flask has a long neck with a white graduation line along its length.

Volumetric containers are used to measure a specific volume with a very high degree of precision. For example, a 100-mL volumetric flask has a white line that indicates 100 mL. The line is specific for each flask, and its location was determined at standard temperature. This calibration process makes volumetric flasks some of the most precise equipment in a chemistry lab.

 

Volumetric Pipette
 

A volumetric pipette and bulb. The pipette is a long thin glass tube with an oval bulge in its middle. The bulb is a compressible rubber object with a plastic cap to fit over the end of the pipette.

A volumetric pipette is also a calibrated piece of glassware, but it is used for lower volumes. Look at the pipettes in Figures 12 and 13 on the bottom of page 800 of your textbook. A 10-mL volumetric pipette has only one line indicating precisely 10 mL. Graduated pipettes may have markings for each 0.1 mL. See the graduated pipette at the bottom of the page in Figure 13.

 

Watch and Listen
 
Preparing a Solution from a Solid

 

View the video “Preparation of a Solution by Direct Addition.” In this video presentation, you have the opportunity to watch the process to prepare a solution and to answer the questions that accompany the steps in the procedure. Pause the video so you can complete the questions and check your answers. If you experience any difficulty in completing the calculations in the pre-lab, refer to Example 4 below.

 

In the video the steps involved in making a solution of specific, accurate concentration (a standard solution) are shown. A listing of these steps also appears in "Preparing a Standard Solution from a Solid Reagent" on page 803 of your textbook.
 
Example 4: A standard solution of 0.350-mol/L iron(II) sulfate is to be prepared. The required volume is 100.00 mL, and the solute has the chemical formula FeSO4 • 7H2O(s). Describe how to prepare this solution.

 

Step 1: Calculate the mass of solute required.

 

 

First, determine the number of moles of FeSO4 • 7H2O(s) required.

 

 

Now, calculate mass of solute required.

 

 

The mass of FeSO4 • 7H2O(s) required is 9.73 g.

 

Step 2: Measure 9.73 g of iron(II) sulfate heptahydrate in a clean, dry beaker (weighing boat or weighing paper) using an electronic balance.

 

Step 3: Pour about 50 mL of distilled water into a beaker. Transfer the iron(II) sulfate heptahydrate to the beaker containing the water. Stir to dissolve.

 

Step 4: Transfer the contents of the beaker into a 100-mL volumetric flask. Rinse the beaker and transfer the rinse water to the volumetric flask.

 

Step 5: Add distilled water to the volumetric flask until the calibration line is almost reached. Use an eyedropper to add the remaining water so that the bottom of the meniscus meets the calibration line.

Step 6: Stopper the flask and mix the solution by inverting.

 

1.41. Page 7

Lesson 5

Module 4—Properties of Solutions

Read

 

Preparing a Solution by Dilution

 

stock solution: a concentrated solution that is used in the preparation of more dilute solutions of the same solute

Many labs prepare stock solutions of a specific chemical. Stock solutions are often used to create new, less concentrated solutions of the same solute by dilution, usually with water. A procedure for preparing a standard solution by dilution appears in "Preparing a Standard Solution by Dilution" on pages 803 and 804 of your textbook.

 

Dilution formula representation. Left-hand side of equation: lower case c subscript lower case I multiplied to upper case V subscript lower case i. Below this half of the equation is a beaker containing a small volume of solution with an intense grey colour. The right hand side of the equation is lower case c subscript lowercase f multiplied by uppercase V subscript lower case f. Below the right-hand side of the equation is a beaker containing a larger volume of solution, but with a less intense shade of grey.

Dilution is the process of increasing the amount of solvent, resulting in a less concentrated solution.

 

Read “Preparation of Standard Solutions by Dilution” on pages 216 and 217 in your textbook.

 

What quantities of a solution change when it is diluted? Which quantities do not change?

 

The dilution formula ciVi = cfVf, is a convenient way to calculate changes that will occur when a dilution is performed. The variables in this equation are

 

ci = initial concentration of solution

Vi = initial volume of solution

cf = final concentration of solution

Vf= final volume of solution

 

Why is the dilution formula expressed as an equality? What chemical quantity is equal to both sides of the equation? Send your answers to these questions to your teacher for feedback.

 

Watch and Listen
 

View the video “Preparation of an Aqueous Solution by Dilution.” In this video presentation, you have the opportunity to watch the process to prepare a solution and to answer the questions that accompany the steps in the procedure. Pause the video so you can complete the questions and check your answers.

 

Carefully work through the following example problem.

 

Example 5: Calculate the volume of water necessary to dilute 50 mL of a 0.50-mol/L sodium chloride solution to 0.30 mol/L.

 


 

The final volume of the dilute solution is 83 mL. Since the volume transferred from the original solution was 50 mL, an additional 33 mL of water must be added to the original solution.

 

Self-Check

 

SC 13. A 100-mL solution of 0.180-mol/L sodium sulfate is required. Determine the mass of sodium sulfate required to make this solution.

 

SC 14. A 100-mL potassium permanganate solution with a concentration of 0.0870 mol/L is required. Write out the pre-lab and procedure for making this solution.

 

SC 15. A stock solution of phosphoric acid with a concentration of 14.6 mol/L is available in a lab. From the stock solution, a 1.50-L phosphoric acid solution is to be created with a concentration of 0.400 mol/L. Determine the volume of stock solution required to make the new solution.

 

SC 16. A 1.00-L stock solution containing 99% V/V isopropyl alcohol is available. What volume of the stock solution is required to make 200 mL of a 70% V/V solution?

 

SC 17. A 17.8-mol/L concentrated sulfuric acid solution is available in a lab. A 1.00-L solution with a concentration of 0.800 mol/L is required. Write out the pre-lab and procedure for making this solution.

 

Check your work.
Self-Check Answers

 

SC 13.

 

 

First, determine the number of moles of sodium sulfate.

 

 

Now, determine the mass of sodium sulfate.

 

 

The mass of sodium sulfate required is 2.56 g.

 

SC 14.


Step 1: Calculate the number of moles of solute required; then determine the mass of potassium permanganate required.

 

 

First, determine the number of moles of potassium permanganate.

 

 

Now, determine the mass of potassium permanganate.

 

 

The mass of KMnO4(s) required is 1.37 g.

 

Step 2: Measure out 1.37 g of potassium permanganate in a clean, dry beaker using an electronic balance.

 

Step 3: Pour about 50 mL of distilled water into the beaker containing the potassium permanganate. Stir to dissolve the solute.

 

Step 4: Transfer the contents of the beaker into a 100-mL volumetric flask, rinsing out the beaker and collecting the rinse water in the volumetric flask.

 

Step 5: Add distilled water until the calibration line is almost reached; then add distilled water using an eyedropper until the calibration line is reached.

 

Step 6: Stopper the flask, and mix by inverting.

 

SC 15.

 


 

SC 16.

 


 

Note that the total volume of the stock solution (1.00 L) was not required for this question.

 

SC 17.  Step 1: Calculate the volume of stock solution needed for the procedure.

 


 

Step 2: Pour approximately 0.5 L of distilled water into a 1.00-L volumetric flask.

 

Step 3: Measure 44.9 mL of sulfuric acid stock solution using a pipette.

 

Step 4: Slowly transfer the concentrated acid from the pipette to the volumetric flask containing the water. Caution: Mixing acids and water can produce a great deal of heat. Swirl the contents of the volumetric flask occasionally to distribute heat from the solution.

 

Step 5: Carefully add distilled water until the calibration line is almost reached; then use an eyedropper to add the water until the calibration line is reached. Swirl contents as in step 4 to distribute heat form the solution. If the flask feels too hot, stop adding water until the flask contents cool.

 

Step 6: Stopper the flask, and carefully mix by inverting.

 

Module 4: Lesson 5 Assignment

 

Retrieve the copy of the Module 4: Lesson 5 Assignment that you saved earlier in this lesson. Complete Part 1 of the assignment. Save a copy of your work to your course folder.

 

1.42. Page 8

Lesson 5

Module 4—Properties of Solutions

Reflect and Connect

 

Module 4: Lesson 5 Assignment

 

Study Sheet

 

Review Lessons 4 and 5 of this module and prepare a study sheet featuring 12 hints that can help you keep track of the major concepts you learned in these lessons. Provide an example for each hint on your list. In developing your list of hints, you may want to collaborate with other students using your class discussion area.

 

Save a copy of your list to your course folder. Place a copy of the list and supporting examples in Part 2 of the Lesson 5 Assignment that you saved earlier.

 

Reflect on the Big Picture

 

Proactive Citizen Projects

 

It is now time to complete the two Proactive Citizen Projects you chose from the topics listed in the Module 4 Summary and Assessment document. Save your work to your course folder. You will receive information later in this lesson about submitting your completed work to your teacher.

 

Assessment

 

Submit the following items to your teacher:

  • Module 4: Lesson 5 Assignment
  • Proactive Citizen Projects (two projects)

 

1.43. Page 9

Lesson 5

Module 4—Properties of Solutions

Lesson Summary

 

In this lesson you explored the following essential questions:

  • How can the concentration of solute in a solution be expressed?

  • How do you calculate amount concentration and determine the concentrations of chemical species produced by dissociation?

  • How are solutions prepared in a lab?

Your study in this lesson has expanded your knowledge of solution chemistry and has enabled you to prepare and dilute solutions of a desired concentration. In solution chemistry, many questions must be solved mathematically; and you now have an understanding of how formulas can be applied to predict the concentration of dissociated ions in a solution.

 

Lesson Glossary

 

amount concentration: the proportion of solute (in moles) to volume of solution

 

stock solution: a concentrated solution that is used in the preparation of more dilute solutions of the same solute

 

1.44. Module Summary/Assessment

Module Summary and Assessment

Module 4—Properties of Solutions

Module Summary

 

Think back to the questions you were asked at the beginning of the module.

  • What are some of your preconceived notions about solution chemistry?
  • Have you acquired new knowledge from this module that contradicts prior beliefs?

As you worked through these lessons, you likely came across a few things that challenged your prior beliefs about solutions. Perhaps the following thoughts came to mind:

  • Brass and air are solutions, even though you likely never thought they were.

  • While the dissolving process of sugar and salt may appear to be visually identical, they dissolve in water for different reasons.

  • Crystals of salt or sugar at the bottom of a saturated solution are not static.

  • The improper disposal of computers can have an effect on people living as far north as the Arctic.

While completing this module, you worked on two projects relating to drinking water and the environment. These projects may have given you some insight into the care that must be taken with many substances that have the potential to form hazardous solutions.

 

Module Assessment

 

The assessment in this module consists of the following:

  • Lesson 1 Assignment
  • Lesson 3 Assignment
  • Lesson 5 Assignment

You are also required to complete two of the following Proactive Citizen Projects. Choose from Projects A through I listed below. You may wish to refer to the work you completed in each of the lessons for ideas on relevant chemistry concepts that should be included in your project.

 

Remember to save your work on each of your projects into your course folder. Upon completion of your work in this module, you will submit both of your completed projects to your teacher.

 

Proactive Citizen Projects: Topics

 

Part 1: The Water Supply and You

 

Project A

 

Complete the following activity and add your work to your course folder.

  • Search your house and locate five potentially dangerous solutions. To find as many different types as possible, look in more places than underneath your kitchen sink. After you have decided on your five solutions, make a list of them and summarize all the important safety precautions for each solution.
  • Select two products that have specific warnings on the label, such as warnings about mixing one product with another and storage temperature. Using the Internet or your library, research what would happen if these warnings were ignored. Do not try any experiments yourself.
  • Select two solutions that are poisonous. Research what would happen if these particular solutions were ingested. What should be done if someone accidentally swallows these solutions?
  • Some of the solutions in your list may be dangerous to the environment. Research how to safely dispose of each of your five solutions.

Project B

Untreated water can lead to a variety of health problems. Fortunately, water treatment plants exist to make sure the water reaching your home meets strict government standards. Despite the efforts of municipalities to provide clean and safe drinking water, many people believe that tap water is still unsafe and they choose to drink bottled water. Write an essay that answers the following question:

 

Many people believe that bottled water is safer than tap water. Do scientific facts justify this belief?

 

You may use the Internet or your library to research this issue. To begin your research you may want to use relevant terms in a variety of combinations. Also, you may wish to consult your class and review the discussion postings from other students to find ideas for your essay.
 

Part 2: Who’s Looking Out for Your Safety?

 

Project C

Toxicologists study adverse effects of chemicals on living organisms. Write an essay or create an illustration, slide presentation, podcast, or mindmap describing the discipline of toxicology. You may wish to incorporate some of the following ideas into your paper. Feel free to come up with your own ideas too.

  • What are some examples of topics a toxicologist would study?

  • Which industries hire toxicologists?

  • What laboratory techniques do toxicologists use?

  • What kind of education is required to become a toxicologist? What are some of the different specializations?

Project D

 

Salt can be a problem in terrestrial ecosystems. Road salt used throughout the winter to melt ice can increase the salinity of freshwater reserves close to areas where it is used, impacting plants and animals.

 

What are the benefits and hazards of road salt?

 

Write an essay or create an illustration, slide presentation, or mindmap that addresses this question from many perspectives and situations.

 

Part 3: When Is Salty Water Not Safe to Consume?

 

Project E

 

A photograph showing a glass jar containing pickled cucumbers.

© EuToch/shutterstock

Water softeners use an ion-exchange resin that removes calcium and magnesium from hard water. However, this process releases sodium ions during the process.

 

Despite the increased salinity of soft water, the amount of sodium released from a water softener is tiny compared to the amount of salt people consume in food. Therefore, it does not pose a significant health risk, even to those on salt-reduced diets.

 

At what point would salty water become dangerous if consumed? Why can salt water be dangerous to consume, even if its concentration is similar to that of our blood?

 

Write text or create an illustration, cartoon, slide presentation, podcast, or mindmap to provide an explanation to these questions. In order to be convincing, you must include scientific principles that back up your statements. Save your work to your course folder.

 

Part 4: Understanding Guidelines for Canadian Drinking Water

 

Project F

 

In this project you will create a pamphlet, comic strip, or slide presentation that summarizes important details about drinking water in your area. Some of the topics you may wish to discuss are

  • the source of the water supply (surface water or groundwater; location)

  • the water treatment plant that services your area

  • environmental concerns about your local water

  • links to local websites that discuss your drinking water (e.g., municipal government websites)

  • consumer information (e.g., water rates)

Project G

 

Most water treatment plants give tours of their operations. Arrange a tour of your local water treatment plant and write a report that describes how your water is treated.

 

Part 5: Household Environmental Hazards

 

Project H

 

Batteries and computer equipment often contain heavy metals, such as mercury and cadmium. These metals can be released into environmental water systems if the equipment is disposed of improperly.

 

Research the ecological impact of heavy metals in the food chain. Design a poster, slide presentation, or diagram that explains the dangers of simply disposing of these items in the trash.

 

Project I

 

Pesticides can have tremendous value in the lawn and garden, but they do have environmental risks associated with them. Research the risks associated with pesticide use, and investigate possible alternatives. Imagine you are responsible for marketing a pesticide alternative for gardeners. Write a sales pitch and then create an ad or podcast that would convey the environmental need to switch products as well as make consumers feel it is a better choice for their backyards.

 

Proactive Citizen Projects: Scoring Guide

 

The projects listed above have different aspects and requirements. Therefore your teacher may decide to use one or more of the following scoring criteria to grade your project. Consult with your teacher to find out which criteria will be used to judge your work.

 

Although only criteria for grades of 4 and 2 out of 4 are shown, it will be possible for you to obtain grades of 3, 1, and 0 if your work falls below the criteria described.

 

Standard of Excellence and Acceptable Standard for Knowledge

 

Score

Scoring Description

4

 

Excellent

The response is well organized and addresses all the major points of the question using appropriate and clear communication strategies. The description of relevant scientific, technological, and/or societal concepts is explicit. Descriptions, explanations, and/or interrelationships between the concepts provided are correct and reflect a thorough understanding of the question.

2

 

Acceptable

The response is generally organized and addresses most of the major points of the question using adequate communication strategies. The description of relevant scientific, technological, and/or societal concepts is mentioned. Descriptions between the concepts provided are generally correct and reflect an adequate understanding of the question.

 

 

Standard of Excellence and Acceptable Standard for Skills

 

Score

Scoring Description

4

 

Excellent

The problem is thoroughly understood. Research results in a comprehensive and thorough set of information from many sources and perspectives. The data are accurately and completely analyzed. Accurate interpretations and conclusions are made based on an analysis of the data.

2

 

Acceptable

The problem is understood. Research results in a reasonable set of information representing a range of sources. The data are adequately analyzed. Interpretations and conclusions are generally based on an analysis of the data.

 

 

Standard of Excellence and Acceptable Standard for STS

 

Score

Scoring Description

4

 

Excellent

The interrelationships between science, technology, and society are thoroughly understood. Risks and benefits are thoroughly evaluated. Insightful and convincing arguments are used to support a decision or judgement, and a range of viewpoints is considered.

2

 

Acceptable

The interrelationships between science, technology, and society are generally understood. Risks and benefits are listed. Logical arguments are used to support a decision or judgement, and viewpoints are considered.

 

1.45. Module Glossary

Module Glossary

Module 4—Properties of Solutions

Module Glossary

 

amount concentration: the proportion of solute (in moles) to volume of solution

 

aqueous phase: a phase denoting a highly soluble substance that has been dissolved in water; denoted by (aq)

 

Arrhenius acid: a substance that ionizes in water to produce hydrogen ions

 

Arrhenius base: an ionic compound that dissociates in water to produce hydroxide ions

 

concentration: a property of solutions; the mass, volume, or number of moles of solute present in proportion to the quantity of solvent or total solution

 

conductivity: the ability of a solution to transfer an electric current

 

dissociation: the separation of ions that occurs when an ionic compound dissolves in water

 

dynamic equilibrium: the idea that there is a balance between two opposing processes (forward and reverse) occurring at the same rate

 

electrolyte: a solution that conducts an electric current

 

endothermic: absorbing energy from the surroundings

 

exothermic: releasing energy to the surroundings

 

immiscible: a term used to describe liquids that do not dissolve in each other

 

ionization: a process by which a neutral atom or molecule is converted to an ion; the reaction of substances in water to create ions

 

nonelectrolyte: a solution that does not conduct an electric current

 

saturated solution: a solution that contains the maximum quantity of solute for a specified temperature; in which no more solute will dissolve at a specified temperature; at maximum solute concentration

 

solubility: the concentration of a saturated solution at a specified temperature

 

solute: a component of a solution, the material that dissolves in the solvent

 

solution: a homogeneous mixture of at least one solute dissolved in a solvent


solvent: a component of a solution, the material in which the solute dissolves

 

stock solution: a concentrated solution that is used in the preparation of more dilute solutions of the same solute

 

turbidity: the measure of the clarity of a clear liquid