Lesson 5 Ionic Compounds - Naming and Formulas
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Course: | Science 10 [5 cr] - AB Ed copy 1 |
Book: | Lesson 5 Ionic Compounds - Naming and Formulas |
Printed by: | Guest user |
Date: | Sunday, 7 September 2025, 6:46 PM |
Table of contents
- Lesson 5 Introduction
- Naming Binary Ionic Compounds
- Formulas of Binary Ionic Compounds
- Naming Compounds That Contain Polyatomic Ions
- Formulas of Compounds That Contain Polyatomic Ions
- Writing Formulas for Compounds that contain Multivalent Ions
- Naming Ionic Compounds that Contain Multivalent Ions
- Hydrated Ionic Compounds
- Lesson 5 Conclusion
- 2.4 Assignment
Introduction
Please pass the salt!

B5.1 Salt shaker
Would you use this salt on your fries? I hope not! The compound in the container is actually copper(II) sulfate. The term āsaltā is a generic term that refers to a chemical compound consisting of an assembly of cations and anions. I think
you meant to say, please pass the table salt, or according to IUPAC rules, please pass the sodium chloride! In the previous lesson, you looked at why a system is needed to name compounds. In this lesson, you will learn about the IUPAC rules used to
name ionic compounds.
Targets
By the end of this lesson, you will be able to
-
write formulas for and name, using IUPAC rules, binary ionic compounds
-
write formulas for and name, using IUPAC rules, multivalent ionic compounds
-
write formulas for and name, using IUPAC rules, ionic compounds that contain polyatomic ions
-
write formulas for and name, using IUPAC rules, hydrated ionic compounds
Watch This
Formulae of Ionic Compounds & Their Names ā Part 1 @ YouTube FuseSchool ā Global Education
This is a simple introduction to the basic principles for writing formulas and naming simple binary ionic compounds. There are a few differences to keep in mind.
-
In the modified Bohr diagrams they use, they place the electrons separate in the first energy level.
-
At times, they place two electrons in one orbital.
- Compound names should not be capitalized.
Ionic Bonding of lithium fluoride and potassium oxide @ YouTube FuseSchool ā Global Education
Need a few more examples? Here are examples for two more ionic compounds. There are a few differences to keep in mind.
-
In the modified Bohr diagrams they use, they place the electrons separate in the first energy level.
-
At times they place two electrons in one orbital.
- Compound names should not be capitalized.
Naming Binary Ionic Compounds
What does the prefix ābiā mean?

B5. 2 bicycle
Bicycle, biyearly, bivalve, bifocal, binary are all words that utilize the prefix ābi.ā Do you know what the prefix ābiā stands for? The answer is two. In this part of the lesson, you will learn how to name binary ionic compounds, or compounds
that contain two elementsāa metal and a non-metalāby following a simple set of guidelines.
Remember from Science 9 that compound names are not proper nouns, so do not use capital letters.
1. You can identify the compound as binary ionic because it is a metal element bonded to a non-metal element.
2. Write the name of the metal element first.
3. Write the name of the non-metal element second, changing the ending to āide.ā
2. Write the name of the metal element first.
3. Write the name of the non-metal element second, changing the ending to āide.ā
Remember from Science 9 that compound names are not proper nouns, so do not use capital letters.
Examples
Each example has a video to go with it. To play the video, click on the play icon next to the example.Identify the elements in the compound as being a metal bonded to a non-metal.
potassiumāmetal
oxygenānon-metal
This is an ionic compound.
oxygenānon-metal
This is an ionic compound.
Write the name of the non-metal element, changing the ending to āide.ā
Oxygen becomes oxide.
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/d1xqd3gmp5
Identify the elements in the compound as being a metal bonded to a non-metal.
aluminiumāmetal
chlorineānon-metal
This is an ionic compound.
chlorineānon-metal
This is an ionic compound.
Write the name of the non-metal element, changing the ending to āide.ā
Chlorine becomes chloride.
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/0sbhpgcnjc
Identify the elements in the compound as being a metal bonded to a non-metal.
magnesiumāmetal
nitrogenānon-metal
This is an ionic compound.
nitrogenānon-metal
This is an ionic compound.
Write the name of the non-metal element, changing the ending to āide.ā
Nitrogen becomes nitride.
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/n2zvqb5s1s
Identify the elements in the compound as being a metal bonded to a non-metal.
bariumāmetal
sulfurānon-metal
This is an ionic compound.
sulfurānon-metal
This is an ionic compound.
Write the name of the non-metal element, changing the ending to āide.ā
Sulfur becomes sulfide.
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/0im0hviti9
Read This
Please read page 42 in your Science 10 textbook. Make sure you take notes on your readings to study from later. You should focus on naming binary ionic compounds. Remember,
if you have any questions or you do not understand something, ask your teacher! Practice Questions
Complete the following practice questions to check your understanding of the concept you just learned. Make sure you write complete answers to the practice questions in your notes. After you have checked your answers, make corrections to your responses
(where necessary) to study from.- Provide the correct IUPAC name for each of the following compounds.
ZnS Li3P NaF MgI2 CaBr2 K3N Al2O3
ZnS zinc sulfide Li3P lithium phosphide NaF sodium flouride MgI2 magnesium iodide CaBr2 calcium bromide K3N potassium nitride Al2O3 aluminium oxide
Formulas of Binary Ionic Compounds
Did you know that sapphires, emeralds, and rubies are all crystal lattice structures of the same binary ionic compound?

B5.3 Three rings: one with a sapphire, one with an emerald, and one with a ruby
Sapphires, emeralds, and rubies are composed of aluminium oxide. The characteristic colours come from trace amounts of transition metals imbedded in the structures.
The formula of aluminum oxide is Al2O3, which seems to imply that the structure is a simple molecule of two Al atoms and three O atoms. How can large gem stones be created from this? In reality, the formula shows the ratio of cations to anions that exist in the giant crystal lattice structure.
Subscripts indicate the ratio of cations to anions needed to create a neutral compound.
The formula of aluminum oxide is Al2O3, which seems to imply that the structure is a simple molecule of two Al atoms and three O atoms. How can large gem stones be created from this? In reality, the formula shows the ratio of cations to anions that exist in the giant crystal lattice structure.
Subscripts indicate the ratio of cations to anions needed to create a neutral compound.
The guidelines for writing formulas for binary ionic compounds are as follows:
- Identify the type of compoundāa metal element with a non-metal element is ionic.
- Write the ion symbols.
- Determine the number of the ions of each element that will result in a neutral compound. Do this by determining the lowest common multiple.
- Determine the factor (number) that each ion needs to be multiplied by to create the lowest common multiple.
- Write these as subscripts. Do not write the subscript 1.
Examples
Each example has a video to go with it. To play the video, click on the play icon next to the example.
Identify the type of compound.
magnesiumāmetal
chlorideānon-metal
This is an ionic compound.
chlorideānon-metal
This is an ionic compound.
Write the ion symbols.
«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mi»Mg«/mi»«msup»«mn»2«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mo»§#160;«/mo»«msup»«mi»Cl«/mi»«mo»§#8211;«/mo»«/msup»«/math»
Determine the lowest common multiple of the two charges.
The lowest common multiple between 2 and 1 is 2.
Determine the factor to multiple each ion by.
«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mtable columnspacing=¨0px¨ columnalign=¨right center left¨»«mtr»«mtd»«msup»«mi»Mg«/mi»«msup»«mn»2«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»1«/mn»«mo»§#160;«/mo»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mo»§#160;«/mo»«mn»2«/mn»«mo»+«/mo»«/mtd»«/mtr»«mtr»«mtd»«msup»«mi»Cl«/mi»«mo»§#8211;«/mo»«/msup»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»2«/mn»«mo»§#160;«/mo»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mo»§#160;«/mo»«mn»2«/mn»«mo»§#8211;«/mo»«/mtd»«/mtr»«/mtable»«/math»
This will create a neutral compound.
The ratio of Ā«math xmlns=ĀØhttp://www.w3.org/1998/Math/MathML¨»«msup»«miĀ»MgĀ«/mi»«msup»«mnĀ»2Ā«/mn»«moĀ»+Ā«/mo»«/msup»«/msup»«/mathĀ» to Clā is 1:2.
This will create a neutral compound.
The ratio of Ā«math xmlns=ĀØhttp://www.w3.org/1998/Math/MathML¨»«msup»«miĀ»MgĀ«/mi»«msup»«mnĀ»2Ā«/mn»«moĀ»+Ā«/mo»«/msup»«/msup»«/mathĀ» to Clā is 1:2.
Short cut: There is a short cut that is known as swap and drop (or criss-cross the charges) to help you determine the subscripts. If you use this method, you need to remember to reduce the subscripts to lowest terms.
1. Write the formulas of the ions. |
«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mi»Mg«/mi»«msup»«mn»2«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mo»§#160;«/mo»«msup»«mi»Cl«/mi»«mo»§#8211;«/mo»«/msup»«/math» |
2. Swap and drop the charges (just the numbers, not the signs). |
![]() |
3. Reduce subscripts to lowest terms. | (cannot be reduced) |
4. Write the formula. |
MgCl2 |
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/aj2i67vem6
Identify the type of compound.
zincāmetal
nitrideānon-metal
This is an ionic compound.
nitrideānon-metal
This is an ionic compound.
Write the ion symbols.
«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mi»Zn«/mi»«msup»«mn»2«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mo»§#160;«/mo»«mo»§#160;«/mo»«msup»«mi mathvariant=¨normal¨»N«/mi»«msup»«mn»3«/mn»«mo»§#8211;«/mo»«/msup»«/msup»«/math»
Determine the lowest common multiple of the two charges.
The lowest common multiple between 2 and 3 is 6.
Determine the factor to multiple each ion by.
«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mtable columnspacing=¨0px¨ columnalign=¨right center left¨»«mtr»«mtd»«msup»«mi»Zn«/mi»«msup»«mn»2«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»3«/mn»«mo»§#160;«/mo»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mo»§#160;«/mo»«mn»6«/mn»«mo»+«/mo»«/mtd»«/mtr»«mtr»«mtd»«msup»«mi mathvariant=¨normal¨»N«/mi»«msup»«mn»3«/mn»«mo»§#8211;«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»2«/mn»«mo»§#160;«/mo»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mo»§#160;«/mo»«mn»6«/mn»«mo»§#8211;«/mo»«/mtd»«/mtr»«/mtable»«/math»
This will create a neutral compound.
The ratio of «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mi»Zn«/mi»«msup»«mn»2«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mi»to«/mi»«mo»§#160;«/mo»«msup»«mi mathvariant=¨normal¨»N«/mi»«msup»«mn»3«/mn»«mo»§#8211;«/mo»«/msup»«/msup»«/math» is 3:2.
This will create a neutral compound.
The ratio of «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mi»Zn«/mi»«msup»«mn»2«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mi»to«/mi»«mo»§#160;«/mo»«msup»«mi mathvariant=¨normal¨»N«/mi»«msup»«mn»3«/mn»«mo»§#8211;«/mo»«/msup»«/msup»«/math» is 3:2.
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/oy12333a3k
Identify the type of compound.
calciumāmetal
oxideānon-metal
This is an ionic compound.
oxideānon-metal
This is an ionic compound.
Write the ion symbols.
«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mi»Ca«/mi»«msup»«mn»2«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mo»§#160;«/mo»«mo»§#160;«/mo»«msup»«mi mathvariant=¨normal¨»O«/mi»«msup»«mn»2«/mn»«mo»§#8211;«/mo»«/msup»«/msup»«/math»

This can be reduced to CaO.

This can be reduced to CaO.
Determine the lowest common multiple of the two charges.
The lowest common multiple between 2 and 2 is 2.
Determine the factor to multiple each ion by.
«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mtable columnspacing=¨0px¨ columnalign=¨right center left¨»«mtr»«mtd»«msup»«mi»Ca«/mi»«msup»«mn»2«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»1«/mn»«mo»§#160;«/mo»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mo»§#160;«/mo»«mn»2«/mn»«mo»+«/mo»«/mtd»«/mtr»«mtr»«mtd»«msup»«mi mathvariant=¨normal¨»O«/mi»«msup»«mn»2«/mn»«mo»§#8211;«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»1«/mn»«mo»§#160;«/mo»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mo»§#160;«/mo»«mn»2«/mn»«mo»§#8211;«/mo»«/mtd»«/mtr»«/mtable»«/math»
This will create a neutral compound.
The ratio of «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mi»Ca«/mi»«msup»«mn»2«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mi»to«/mi»«mo»§#160;«/mo»«msup»«mi mathvariant=¨normal¨»O«/mi»«msup»«mn»2«/mn»«mo»§#8211;«/mo»«/msup»«/msup»«/math» is 1:1.
This will create a neutral compound.
The ratio of «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mi»Ca«/mi»«msup»«mn»2«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mi»to«/mi»«mo»§#160;«/mo»«msup»«mi mathvariant=¨normal¨»O«/mi»«msup»«mn»2«/mn»«mo»§#8211;«/mo»«/msup»«/msup»«/math» is 1:1.
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/kfqs0m6914
Identify the type of compound.
aluminiumāmetal
fluorideānon-metal
This is an ionic compound.
fluorideānon-metal
This is an ionic compound.
Write the ion symbols.
«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mi»Al«/mi»«msup»«mn»3«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mo»§#160;«/mo»«mo»§#160;«/mo»«msup»«mi mathvariant=¨normal¨»F«/mi»«mo»§#8211;«/mo»«/msup»«/math»
Determine the lowest common multiple of the two charges.
The lowest common multiple between 3 and 1 is 3.
Determine the factor to multiple each ion by.
«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mtable columnspacing=¨0px¨ columnalign=¨right center left¨»«mtr»«mtd»«msup»«mi»Al«/mi»«msup»«mn»3«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»1«/mn»«mo»§#160;«/mo»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mo»§#160;«/mo»«mn»3«/mn»«mo»+«/mo»«/mtd»«/mtr»«mtr»«mtd»«msup»«mi mathvariant=¨normal¨»F«/mi»«mo»§#8211;«/mo»«/msup»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»3«/mn»«mo»§#160;«/mo»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mo»§#160;«/mo»«mn»3«/mn»«mo»§#8211;«/mo»«/mtd»«/mtr»«/mtable»«/math»
This will create a neutral compound.
The ratio of Ā«math xmlns=ĀØhttp://www.w3.org/1998/Math/MathML¨»«msup»«miĀ»AlĀ«/mi»«msup»«mnĀ»3Ā«/mn»«moĀ»+Ā«/mo»«/msup»«/msup»«/mathĀ» to Fā is 1:3.
This will create a neutral compound.
The ratio of Ā«math xmlns=ĀØhttp://www.w3.org/1998/Math/MathML¨»«msup»«miĀ»AlĀ«/mi»«msup»«mnĀ»3Ā«/mn»«moĀ»+Ā«/mo»«/msup»«/msup»«/mathĀ» to Fā is 1:3.
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/sn7r92mttf
Interactive Activity
Creating Compounds Manipulative
To help you visualize how ions combine in certain ratios to make ionic compounds, work through the following examples. You can use this manipulative to help you write formulas for ionic compounds in the practice question section and on your
assignment.
For cations, each extension represents an electron that needs to be lost. For anions, each divot represents an electron that needs to be gained. The goal is to combine the correct ratio of cations to anions to create neutral compounds.
Click on the procedure 1 tab to continue.
For cations, each extension represents an electron that needs to be lost. For anions, each divot represents an electron that needs to be gained. The goal is to combine the correct ratio of cations to anions to create neutral compounds.
Click on the procedure 1 tab to continue.
- Click on the play icon to make a copy of the creating compound manipulative. Print students can access the document in the Online Resources for Print Students section of their online course.
- Predict the formula for magnesium chloride by dragging a magnesium ion to the work surface.
How many bonds will magnesium form?
- Drag a chloride ion onto the work surface.
How many bonds will chloride form?
- Drag enough chloride ions to create a stable compound.
How many magnesium ions are needed? Chloride ions?
magnesium ions = 1
chloride ions = 2 - Clear the work surface by returning all cations and anions.
- Click on the procedure 2 tab to continue.
- Predict the formula for zinc nitride by dragging a zinc ion to the work surface.
How many bonds will zinc form?
- Drag a nitride ion to the work surface.
How many bonds will nitride form?
- Drag enough zinc ions and nitride ions to create a stable compound.
How many zinc ions are needed? Nitride ions?
zinc ions = 3
Nitride ions = 2 - Clear the work surface by returning all cations and anions.
- Click on the procedure 3 tab to continue.
- Predict the formula for calcium oxide by dragging a calcium ion to the work surface.
How many bonds will calcium form?
- Drag an oxide ion onto the work surface.
How many bonds will oxide form?
- Drag enough oxide ions to create a stable compound.
How many calcium ions are needed? Oxide ions?
calcium ions = 1
oxide ions = 1 - Clear the work surface by returning all cations and anions.
- Click on the procedure 4 tab to continue.
- Predict the formula for aluminium fluoride by dragging an aluminium ion to the work surface.
How many bonds will aluminium form?
- Drag a fluoride ion onto the work surface.
How many bonds will fluoride form?
- Drag enough fluoride ions to create a stable compound.
How many aluminum ions are needed? Fluoride ions?
aluminum ions = 1
fluoride ions = 3 - Clear the work surface by returning all cations and anions.
Digging Deeper

Ā© Wikimedia Commons
B5.4 Star sapphire
B5.4 Star sapphire
The Star of Adam is the largest star sapphire in the world. It weighs 1 404 carats (281 g) and has been valued at over $300 million. It was discovered in Sri Lanka, which is a well-known location for gem mining.
Read This
Please read pages 42 to 43 in your Science 10 textbook. Make sure you take notes on your readings to study from later. You should focus on how to write formulas for
binary ionic compounds. Remember, if you have any questions or you do not understand something, ask your teacher! Practice Questions
Complete the following practice questions to check your understanding of the concept you just learned. Make sure you write complete answers to the practice questions in your notes. After you have checked your answers, make corrections to your responses
(where necessary) to study from.- Provide the correct IUPAC name for each of the following compounds.
zinc bromide potassium nitride lithium iodide barium phosphide aluminium sulfide magnesium oxide sodium arsenide
zinc bromide ZnBr2 potassium nitride K3N lithium iodide LiI barium phosphide Ba3P2 aluminium sulfide Al2S3 magnesium oxide MgO sodium arsenide Na3As
Naming Compounds That Contain Polyatomic Ions
Did you know that many common household substances, such as baking soda, are ionic compounds?

B5.5 Baking soda
Baking soda is a more complex ionic compound than the binary ionic compounds you just learned about. The IUPAC name of baking soda is sodium hydrogen carbonate and the chemical formula is NaHCO3. Ionic compounds that contain more than
two elements will contain a polyatomic ion.
A polyatomic ion is a group of elements that act as unit and have a charge. The majority of these ions are anions; however, there is one cation polyatomic that you will be working with in this course: ammonium, «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mi»NH«/mi»«mrow»«mn»4«/mn»«mo»+«/mo»«/mrow»«/msup»«/math».
In your Science 10 data booklet, there is a table that identifies the common polyatomic ions. Compounds that contain polyatomic ions are classified as ionic compounds and, as such, have similar rules for naming and writing formulas.
Watch This
Formulae of Ionic Compounds and Their Names: Part 2 @ YouTube FuseSchool ā Global Education
This video goes over some examples of writing formulas and naming compounds that contain polyatomic ions. Please note that in this video they use capital letters when writing names of compounds; this is not proper format. The last 40 s of this video goes on to give examples of multivalent ions. You will learn about multivalent ions later in the lesson.
Hint: If the compound contains a metal, it is an ionic compound.
Digging Deeper
Bleach has the IUPAC name of sodium hypochlorite and the formula NaClO. Many polyatomic ions contain oxygen. There is a pattern that relates the number of oxygen atoms to the polyatomic name. If the polyatomic ion ends with āāate,ā that is the
ābaseā oxyanion name in the series. If there is a āperā ā prefix added, there is one more oxygen in the ābaseā oxyanion formula. If the suffix changes to āāite,ā there is one less oxygen atom in the formula. And if there is a āhypoāā prefix,
there is even one fewer oxygen.

B5.6 Bleach
Did You Know?

B5.7 Soap making
Strong bases, such as lye, which is used to make soap, are ionic compounds of hydroxide. This makes base formulas easy to recognize!
sodium hydroxideāNaOH
potassium hydroxideāKOH
lithium hydroxideāLiOH
Naming Compounds That Contain Polyatomic Ions Cont'd
Regardless of the number of elements in the compound formula, the name will consist of two parts: the cation name and the anion name. If you find yourself stringing several element names together to name a compound name, chances are the compound contains a polyatomic and you need to look for the polyatomic name in the table.
Examples
Each example has a video to go with it. To play the video, click on the play icon next to the example.
Identify the composition of the compound.
K+āmetal
Ā«math xmlns=ĀØhttp://www.w3.org/1998/Math/MathML¨»«msup»«msub»«miĀ»SOĀ«/mi»«mnĀ»4Ā«/mn»«/msub»«mrow»«mnĀ»2Ā«/mn»«moĀ»-Ā«/mo»«/mrow»«/msup»«/mathĀ»āpolyatomic
This is an ionic compound.
Ā«math xmlns=ĀØhttp://www.w3.org/1998/Math/MathML¨»«msup»«msub»«miĀ»SOĀ«/mi»«mnĀ»4Ā«/mn»«/msub»«mrow»«mnĀ»2Ā«/mn»«moĀ»-Ā«/mo»«/mrow»«/msup»«/mathĀ»āpolyatomic
This is an ionic compound.
Write the name of the anion (if it is a polyatomic, do not change the ending; if it is a non-metallic element, change the ending to āideā).
sulfate
Identify the composition of the compound.
Li+āmetal
Ā«math xmlns=ĀØhttp://www.w3.org/1998/Math/MathML¨»«msubsup»«miĀ»NOĀ«/mi»«mnĀ»2Ā«/mn»«moĀ»-Ā«/mo»«/msubsup»«/mathĀ»āpolyatomic
This is an ionic compound.
Ā«math xmlns=ĀØhttp://www.w3.org/1998/Math/MathML¨»«msubsup»«miĀ»NOĀ«/mi»«mnĀ»2Ā«/mn»«moĀ»-Ā«/mo»«/msubsup»«/mathĀ»āpolyatomic
This is an ionic compound.
Write the name of the anion (if it is a polyatomic, do not change the ending; if it is a non-metallic element, change the ending to āideā).
nitrite
Identify the composition of the compound.
Ā«math xmlns=ĀØhttp://www.w3.org/1998/Math/MathML¨»«msubsup»«miĀ»NHĀ«/mi»«mnĀ»4Ā«/mn»«moĀ»+Ā«/mo»«/msubsup»«/mathĀ»āpolyatomic
Clāānon-metal
This is an ionic compound.
Clāānon-metal
This is an ionic compound.
Write the name of the anion (if it is a polyatomic, do not change the ending; if it is a non-metallic element, change the ending to āideā).
Since Cl is chlorine, a non-metal, the element name changes to end in āide.ā
Identify the composition of the compound.
Ā«math xmlns=ĀØhttp://www.w3.org/1998/Math/MathML¨»«msup»«miĀ»CaĀ«/mi»«msup»«mnĀ»2Ā«/mn»«moĀ»+Ā«/mo»«/msup»«/msup»«/mathĀ»āmetal
H2PO4āāpolyatomic
This is an ionic compound.
H2PO4āāpolyatomic
This is an ionic compound.
Write the name of the anion (if it is a polyatomic, do not change the ending; if it is a non-metallic element, change the ending to āideā).
dihydrogen phosphate
Read This
Please read pages 44 to 46 in your Science 10 textbook. Make sure you take notes on your readings to study from later. You should focus on the rules for naming ionic compounds that contain polyatomic ions. Remember, if you have any questions or you do
not understand something, ask your teacher!
Practice Questions
Complete the following practice questions to check your understanding of the concept you just learned. Make sure you write complete answers to the practice questions in your notes. After you have checked your answers, make corrections to your responses
(where necessary) to study from.- Provide the correct IUPAC name for each of the following compounds.
ZnCO3 Li3PO4 Ba(OH)2 MgSO3 NH4Br KMnO4 NaHSO4
ZnCO3 zinc carbonate Li3PO4 lithium phosphate Ba(OH)2 barium hydroxide MgSO3 magnesium sulfite NH4Br ammonium bromide KMnO4 potassium permanganate NaHSO4 sodium hydrogen sulfate
Formulas of Compounds That Contain Polyatomic Ions
Did you know that the pyramids of Giza are made from limestone?

B5.8 The Great Sphinx and the pyramids of Giza
Limestone is the common name for calcium carbonate, CaCO3. Just as you learned how to write chemical formulas for binary ionic compounds, you will now learn how to write formulas for ionic compounds that contain polyatomic ions.
Because these are ionic compounds, there still needs to be a balancing of charges to create a neutral substance. One of the key points to remember when writing formulas for ionic compounds that contain polyatomic ions is to use brackets around the polyatomic ion when there is the need of a subscript.
Because these are ionic compounds, there still needs to be a balancing of charges to create a neutral substance. One of the key points to remember when writing formulas for ionic compounds that contain polyatomic ions is to use brackets around the polyatomic ion when there is the need of a subscript.
Hint: If the compound name ends with āateā or āite,ā then it contains a polyatomic. There are also some polyatomic ions that end in āide.ā
Examples
Each example has a video to go with it. To play the video, click on the play icon next to the example.
Identify the type of compound.
sodiumāmetal
chloriteāpolyatomic
This is an ionic compound.
chloriteāpolyatomic
This is an ionic compound.
Write the ion symbols.
«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mi»Na«/mi»«mo»+«/mo»«/msup»«mo»§#160;«/mo»«mo»§#160;«/mo»«msubsup»«mi»ClO«/mi»«mn»2«/mn»«mo»-«/mo»«/msubsup»«/math»
Determine the lowest common multiple of the two charges.
The lowest common multiple between 1 and 1 is 1.
Determine the factor to multiple each ion by.
«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mtable columnspacing=¨0px¨ columnalign=¨right center left¨»«mtr»«mtd»«msup»«mi»Na«/mi»«mo»+«/mo»«/msup»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»1«/mn»«mo»§#160;«/mo»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mo»§#160;«/mo»«mn»1«/mn»«mo»+«/mo»«mo»§#160;«/mo»«/mtd»«/mtr»«mtr»«mtd»«msubsup»«mi»ClO«/mi»«mn»2«/mn»«mo»-«/mo»«/msubsup»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»1«/mn»«mo»§#160;«/mo»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mo»§#160;«/mo»«mn»1«/mn»«mo»§#8211;«/mo»«/mtd»«/mtr»«/mtable»«/math»
This will create a neutral compound.
The ratio of Na+ to «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msubsup»«mi»ClO«/mi»«mn»2«/mn»«mo»-«/mo»«/msubsup»«/math» is 1:1.
This will create a neutral compound.
The ratio of Na+ to «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msubsup»«mi»ClO«/mi»«mn»2«/mn»«mo»-«/mo»«/msubsup»«/math» is 1:1.
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/sodiarn5sj
Identify the type of compound.
magnesiumāmetal
hydroxideāpolyatomic
This is an ionic compound.
hydroxideāpolyatomic
This is an ionic compound.
Write the ion symbols.
«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mi»Mg«/mi»«msup»«mn»2«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«msup»«mi»OH«/mi»«mo»§#8211;«/mo»«/msup»«/math»
Determine the lowest common multiple of the two charges.
The lowest common multiple between 2 and 1 is 2.
Determine the factor to multiple each ion by.
«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mtable columnspacing=¨0px¨ columnalign=¨right center left¨»«mtr»«mtd»«msup»«mi»Mg«/mi»«msup»«mn»2«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»1«/mn»«mo»§#160;«/mo»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mo»§#160;«/mo»«mn»2«/mn»«mo»+«/mo»«mo»§#160;«/mo»«/mtd»«/mtr»«mtr»«mtd»«msup»«mi»OH«/mi»«mo»§#8211;«/mo»«/msup»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»2«/mn»«mo»§#160;«/mo»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mo»§#160;«/mo»«mn»2«/mn»«mo»§#8211;«/mo»«/mtd»«/mtr»«/mtable»«/math»
This will create a neutral compound.
The ratio of Ā«math xmlns=ĀØhttp://www.w3.org/1998/Math/MathML¨»«msup»«miĀ»MgĀ«/mi»«msup»«mnĀ»2Ā«/mn»«moĀ»+Ā«/mo»«/msup»«/msup»«/mathĀ» to OHā is 1:2.
This will create a neutral compound.
The ratio of Ā«math xmlns=ĀØhttp://www.w3.org/1998/Math/MathML¨»«msup»«miĀ»MgĀ«/mi»«msup»«mnĀ»2Ā«/mn»«moĀ»+Ā«/mo»«/msup»«/msup»«/mathĀ» to OHā is 1:2.
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/7atovzgclg
Identify the composition of the compound.
ammoniumāpolyatomic
fluorideānon-metal
This is an ionic compound.
fluorideānon-metal
This is an ionic compound.
Write the ion symbols.
«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msubsup»«mi»NH«/mi»«mn»4«/mn»«mo»+«/mo»«/msubsup»«mo»§#160;«/mo»«mo»§#160;«/mo»«msup»«mi mathvariant=¨normal¨»F«/mi»«mo»§#8211;«/mo»«/msup»«/math»
Determine the lowest common multiple of the two charges.
The lowest common multiple between 1 and 1 is 1.
Determine the factor to multiple each ion by.
«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mtable columnspacing=¨0px¨ columnalign=¨right center left¨»«mtr»«mtd»«msubsup»«mi»NH«/mi»«mn»4«/mn»«mo»+«/mo»«/msubsup»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»1«/mn»«mo»§#160;«/mo»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mo»§#160;«/mo»«mn»1«/mn»«mo»+«/mo»«/mtd»«/mtr»«mtr»«mtd»«msup»«mi mathvariant=¨normal¨»F«/mi»«mo»§#8211;«/mo»«/msup»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»1«/mn»«mo»§#160;«/mo»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mo»§#160;«/mo»«mn»1«/mn»«mo»§#8211;«/mo»«/mtd»«/mtr»«/mtable»«/math»
This will create a neutral compound.
The ratio of Ā«math xmlns=ĀØhttp://www.w3.org/1998/Math/MathML¨»«msubsup»«miĀ»NHĀ«/mi»«mnĀ»4Ā«/mn»«moĀ»+Ā«/mo»«/msubsup»«/mathĀ» to Fā is 1:1.
This will create a neutral compound.
The ratio of Ā«math xmlns=ĀØhttp://www.w3.org/1998/Math/MathML¨»«msubsup»«miĀ»NHĀ«/mi»«mnĀ»4Ā«/mn»«moĀ»+Ā«/mo»«/msubsup»«/mathĀ» to Fā is 1:1.
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/xkw64p8llr
Identify the type of compound.
aluminiumāmetal
sulfateāpolyatomic
This is an ionic compound.
sulfateāpolyatomic
This is an ionic compound.
Write the ion symbols.
«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mi»Al«/mi»«msup»«mn»3«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mo»§#160;«/mo»«msubsup»«mi»SO«/mi»«mn»4«/mn»«mrow»«mn»2«/mn»«mo»-«/mo»«/mrow»«/msubsup»«/math»
Determine the lowest common multiple of the two charges.
The lowest common multiple between 3 and 2 is 6.
Determine the factor to multiple each ion by.
«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mtable columnspacing=¨0px¨ columnalign=¨right center left¨»«mtr»«mtd»«msup»«mi»Al«/mi»«msup»«mn»3«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»2«/mn»«mo»§#160;«/mo»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mo»§#160;«/mo»«mn»6«/mn»«mo»+«/mo»«/mtd»«/mtr»«mtr»«mtd»«msubsup»«mi»SO«/mi»«mn»4«/mn»«mrow»«mn»2«/mn»«mo»-«/mo»«/mrow»«/msubsup»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»3«/mn»«mo»§#160;«/mo»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mo»§#160;«/mo»«mn»6«/mn»«mo»§#8211;«/mo»«/mtd»«/mtr»«/mtable»«/math»
This will create a neutral compound.
The ratio of «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mi»Al«/mi»«msup»«mn»3«/mn»«mo»+«/mo»«/msup»«/msup»«/math» to «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msubsup»«mi»SO«/mi»«mn»4«/mn»«mrow»«mn»2«/mn»«mo»-«/mo»«/mrow»«/msubsup»«/math» is 2:3.
This will create a neutral compound.
The ratio of «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mi»Al«/mi»«msup»«mn»3«/mn»«mo»+«/mo»«/msup»«/msup»«/math» to «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msubsup»«mi»SO«/mi»«mn»4«/mn»«mrow»«mn»2«/mn»«mo»-«/mo»«/mrow»«/msubsup»«/math» is 2:3.
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/00g9pxgtli
Identify the type of compound.
lithiumāmetal
hydrogen phosphateāpolyatomic
This is an ionic compound.
hydrogen phosphateāpolyatomic
This is an ionic compound.
Write the ion symbols.
«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msup»«mi»Li«/mi»«mo»+«/mo»«/msup»«mo»§#160;«/mo»«mo»§#160;«/mo»«msubsup»«mi»HPO«/mi»«mn»4«/mn»«mrow»«mn»2«/mn»«mo»-«/mo»«/mrow»«/msubsup»«/math»
Determine the lowest common multiple of the two charges.
The lowest common multiple between 2 and 1 is 2.
Determine the factor to multiple each ion by.
«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mtable columnspacing=¨0px¨ columnalign=¨right center left¨»«mtr»«mtd»«msup»«mi»Li«/mi»«mo»+«/mo»«/msup»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»2«/mn»«mo»§#160;«/mo»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mo»§#160;«/mo»«mn»2«/mn»«mo»+«/mo»«/mtd»«/mtr»«mtr»«mtd»«msubsup»«mi»HPO«/mi»«mn»4«/mn»«mrow»«mn»2«/mn»«mo»-«/mo»«/mrow»«/msubsup»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»1«/mn»«mo»§#160;«/mo»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mo»§#160;«/mo»«mn»2«/mn»«mo»§#8211;«/mo»«/mtd»«/mtr»«/mtable»«/math»
This will create a neutral compound.
The ratio of Li+ to «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msubsup»«mi»HPO«/mi»«mn»4«/mn»«mrow»«mn»2«/mn»«mo»-«/mo»«/mrow»«/msubsup»«/math» is 2:1.
This will create a neutral compound.
The ratio of Li+ to «math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«msubsup»«mi»HPO«/mi»«mn»4«/mn»«mrow»«mn»2«/mn»«mo»-«/mo»«/mrow»«/msubsup»«/math» is 2:1.
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/h941wfwzfh
Read This
Please read pages 44 to 46 in your Science 10 textbook. Make sure you take notes on your readings to study from later. You should focus on the rules for writing formulas
for ionic compounds that contain polyatomic ions. Remember, if you have any questions or you do not understand something, ask your teacher!
Practice Questions
Complete the following practice questions to check your understanding of the concept you just learned. Make sure you write complete answers to the practice questions in your notes. After you have checked your answers, make corrections to your responses
(where necessary) to study from.- Provide the correct IUPAC name for each of the following compounds.
zinc sulfate potassium dichromate ammonium iodide barium phosphate aluminium sulfite magnesium cyanide sodium hydrogen sulfide
zinc sulfate ZnSO4 potassium dichromate K2Cr2O7 ammonium iodide NH4I barium phosphate BA3(PO4)2 aluminium sulfite Al2(SO3)3 magnesium cyanide Mg(CN)2 sodium hydrogen sulfide NaHS
Writing Formulas for Compounds that contain Multivalent Ions
How do we deal with particular metals that have multiple ion charges?

Ā© Wikimedia Commons
B5.9 Chromium(VI) oxide
B5.9 Chromium(VI) oxide
The movie Erin Brockovich is based on a real court case in which a company caused hexavalent chromium to leach into water supplies, resulting in devastating health effects of the residents of Hinkley, California. Hexavalent chromium is toxic,
corrosive, and carcinogenic. But what does hexavalent mean?
Some metals can form ions with various ion charges; for example, chromium can have ion charges of «math»«msup»«mi»Cr«/mi»«msup»«mn»6«/mn»«mo»+«/mo»«/msup»«/msup»«mo»,«/mo»«mo»§#160;«/mo»«msup»«mi»Cr«/mi»«msup»«mn»3«/mn»«mo»+«/mo»«/msup»«/msup»«mo»,«/mo»«mo»§#160;«/mo»«mi»and«/mi»«mo»§#160;«/mo»«msup»«mi»Cr«/mi»«msup»«mn»2«/mn»«mo»+«/mo»«/msup»«/msup»«/math» and more rarely «math»«msup»«mi»Cr«/mi»«mo»+«/mo»«/msup»«mo»,«/mo»«mo»§#160;«/mo»«msup»«mi»Cr«/mi»«msup»«mn»4«/mn»«mo»+«/mo»«/msup»«/msup»«mo»,«/mo»«mo»§#160;«/mo»«mi»and«/mi»«mo»§#160;«/mo»«msup»«mi»Cr«/mi»«msup»«mrow»«/mrow»«mrow»«mn»5«/mn»«mo»+«/mo»«/mrow»«/msup»«/msup»«/math». Unlike hexavalent chromium, most other chromium ion compounds are not dangerous. The compound name that contains a multivalent metal must clearly identify which valiancy is in the compound. This is achieved by the use of Roman numerals.
The steps for writing formulas for multivalent ionic compounds are essentially the same as they are for binary ionic compounds. The one difference is that you can determine the cation charge without checking the periodic table. The given Roman numeral following the metal ion is equal to the magnitude of the positive charge on the ion.
Some metals can form ions with various ion charges; for example, chromium can have ion charges of «math»«msup»«mi»Cr«/mi»«msup»«mn»6«/mn»«mo»+«/mo»«/msup»«/msup»«mo»,«/mo»«mo»§#160;«/mo»«msup»«mi»Cr«/mi»«msup»«mn»3«/mn»«mo»+«/mo»«/msup»«/msup»«mo»,«/mo»«mo»§#160;«/mo»«mi»and«/mi»«mo»§#160;«/mo»«msup»«mi»Cr«/mi»«msup»«mn»2«/mn»«mo»+«/mo»«/msup»«/msup»«/math» and more rarely «math»«msup»«mi»Cr«/mi»«mo»+«/mo»«/msup»«mo»,«/mo»«mo»§#160;«/mo»«msup»«mi»Cr«/mi»«msup»«mn»4«/mn»«mo»+«/mo»«/msup»«/msup»«mo»,«/mo»«mo»§#160;«/mo»«mi»and«/mi»«mo»§#160;«/mo»«msup»«mi»Cr«/mi»«msup»«mrow»«/mrow»«mrow»«mn»5«/mn»«mo»+«/mo»«/mrow»«/msup»«/msup»«/math». Unlike hexavalent chromium, most other chromium ion compounds are not dangerous. The compound name that contains a multivalent metal must clearly identify which valiancy is in the compound. This is achieved by the use of Roman numerals.
If no indication is given (i.e., no Roman numerals), then assume the most common ion charge is present, which is the one written first on the periodic table.
The steps for writing formulas for multivalent ionic compounds are essentially the same as they are for binary ionic compounds. The one difference is that you can determine the cation charge without checking the periodic table. The given Roman numeral following the metal ion is equal to the magnitude of the positive charge on the ion.

Ā© Wikimedia Commons
B5.10 Chromium(III) oxide
B5.10 Chromium(III) oxide
Examples
Each example has a video to go with it. To play the video, click on the play icon next to the example.
Identify the type of compound.
chromiumāmetal
fluorideānon-metal
This is an ionic compound.
fluorideānon-metal
This is an ionic compound.
Write the ion symbols.
«math»«msup»«mi»Cr«/mi»«msup»«mn»3«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mo»§#160;«/mo»«mo»§#160;«/mo»«msup»«mi mathvariant=¨normal¨»F«/mi»«mo»§#8211;«/mo»«/msup»«/math»
Determine the lowest common multiple of the two charges.
The lowest common multiple between 3 and 1 is 3.
Determine the factor to multiple each ion by.
«math»«mtable columnspacing=¨0px¨ columnalign=¨right center left¨»«mtr»«mtd»«msup»«mi»Cr«/mi»«msup»«mn»3«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»1«/mn»«mo»§#160;«/mo»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mo»§#160;«/mo»«mn»3«/mn»«mo»+«/mo»«/mtd»«/mtr»«mtr»«mtd»«msup»«mi mathvariant=¨normal¨»F«/mi»«mo»§#8211;«/mo»«/msup»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»3«/mn»«mo»§#160;«/mo»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mo»§#160;«/mo»«mn»3«/mn»«mo»§#8211;«/mo»«/mtd»«/mtr»«/mtable»«/math»
This will create a neutral compound.
The ratio of Ā«math»«msup»«miĀ»CrĀ«/mi»«msup»«mnĀ»3Ā«/mn»«moĀ»+Ā«/mo»«/msup»«/msup»«/mathĀ» to Fā is 1:3.
This will create a neutral compound.
The ratio of Ā«math»«msup»«miĀ»CrĀ«/mi»«msup»«mnĀ»3Ā«/mn»«moĀ»+Ā«/mo»«/msup»«/msup»«/mathĀ» to Fā is 1:3.
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/0cj3jt7ano
Identify the type of compound.
copperāmetal
sulfateāpolyatomic
This is an ionic compound.
sulfateāpolyatomic
This is an ionic compound.
Write the ion symbols.
«math»«msup»«mi»Cu«/mi»«msup»«mn»2«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mo»§#160;«/mo»«mo»§#160;«/mo»«msubsup»«mi»SO«/mi»«mn»4«/mn»«mrow»«mn»2«/mn»«mo»-«/mo»«/mrow»«/msubsup»«/math»

These subscripts can be reduced to CuSO4.

These subscripts can be reduced to CuSO4.
Determine the lowest common multiple of the two charges.
The lowest common multiple between 2 and 2 is 2.
Determine the factor to multiple each ion by.
«math»«mtable columnspacing=¨0px¨ columnalign=¨right center left¨»«mtr»«mtd»«msup»«mi»Cu«/mi»«msup»«mn»2«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»1«/mn»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mo»§#160;«/mo»«mn»2«/mn»«mo»+«/mo»«/mtd»«/mtr»«mtr»«mtd»«msubsup»«mi»SO«/mi»«mn»4«/mn»«mrow»«mn»2«/mn»«mo»-«/mo»«/mrow»«/msubsup»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»1«/mn»«mo»§#160;«/mo»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mo»§#160;«/mo»«mn»2«/mn»«mo»§#8211;«/mo»«/mtd»«/mtr»«/mtable»«/math»
This will create a neutral compound.
The ratio of «math»«msup»«mi»Cu«/mi»«msup»«mn»2«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mi»to«/mi»«mo»§#160;«/mo»«msubsup»«mi»SO«/mi»«mn»4«/mn»«mrow»«mn»2«/mn»«mo»-«/mo»«/mrow»«/msubsup»«/math» is 1:1.
This will create a neutral compound.
The ratio of «math»«msup»«mi»Cu«/mi»«msup»«mn»2«/mn»«mo»+«/mo»«/msup»«/msup»«mo»§#160;«/mo»«mi»to«/mi»«mo»§#160;«/mo»«msubsup»«mi»SO«/mi»«mn»4«/mn»«mrow»«mn»2«/mn»«mo»-«/mo»«/mrow»«/msubsup»«/math» is 1:1.
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/vize8c3fee
Read This
Please read page 44 in your Science 10 textbook. Make sure you take notes on your readings to study from later. You should focus on determining the cationās charge from
the Roman numerals. Remember, if you have any questions or you do not understand something, ask your teacher!
Practice Questions
Complete the following practice questions to check your understanding of the concept you just learned. Make sure you write complete answers to the practice questions in your notes. After you have checked your answers, make corrections to your responses
(where necessary) to study from.- Provide the correct IUPAC name for each of the following compounds.
iron(III) sulfate gold(I) sulfide nickel(II) nitrite manganese(IV) oxide
iron(III) sulfate Fe2(SO4)3 gold(I) sulfide Au2S nickel(II) nitrite Ni(NO2)2 manganese(IV) oxide MnO2
Naming Ionic Compounds that Contain Multivalent Ions
Can you believe that these two containers both hold copper chloride?

Ā© Wikimedia Commons
B5.11 White solid in a liquid
B5.11 White solid in a liquid
When naming ionic compounds that contain multivalent ions, the valency (charge) of the transition metal must be identified as a Roman numeral written directly after the metal name. The vial in image B5.11 contains copper(I) chloride, a white solid with
low solubility in water; and the vial in image B5.12 contains a solution of copper(II) chloride, which is highly soluble in water.
Eighty percent of the time if you uncross the subscripts (from the swap and drop), the correct charge on the multivalent ion is indicated. The exception would be when charges were reduced; so remember to also check the charge on the anion.
Eighty percent of the time if you uncross the subscripts (from the swap and drop), the correct charge on the multivalent ion is indicated. The exception would be when charges were reduced; so remember to also check the charge on the anion.
It should be noted that according to IUPAC nomenclature standards, no space is placed between the name of the multivalent cation and the bracketed Roman numeral. For example, it is incorrect to name CuCl as copper (I) chloride. Rather,
it should be named copper(I) chloride. Please notice this important detail as you work through the following examples to solidify your understanding of multivalent ionic nomenclature.

B5.12 Blue liquid in a vial
Examples
Each example has a video to go with it. To play the video, click on the play icon next to the example.
Identify the composition of the compound.
Coāmultivalent metal
Clānon-metal
This is an ionic compound that needs Roman numerals.
Clānon-metal
This is an ionic compound that needs Roman numerals.
Write the name of the cation.
cobalt
Cobalt is multivalent, so it will either be cobalt(II) or cobalt(III).
āUncrossā the subscripts to determine the charge on cobalt.

As a double check, look on the periodic table: Is the charge on chloride 1ā? Yes! This means that the formula has not been reduced and this method is valid.
Cobalt is multivalent, so it will either be cobalt(II) or cobalt(III).
āUncrossā the subscripts to determine the charge on cobalt.

As a double check, look on the periodic table: Is the charge on chloride 1ā? Yes! This means that the formula has not been reduced and this method is valid.
Write the name of the anion (if it is a polyatomic, do not change the ending; if it is a non-metallic element, change the ending to āideā).
Cl is the non-metal chlorine, so the end changes to āide.ā
chloride
chloride
Combine the ion names, including the Roman numeral representing the charge on the cation.
cobalt(II) chloride
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/2px35op6kq
Identify the composition of the compound.
Feāmultivalent metal
Sānon-metal
This is an ionic compound that needs Roman numerals.
Sānon-metal
This is an ionic compound that needs Roman numerals.
Write the name of the cation.
iron
Iron is multivalent, so it will either be iron(II) or iron(III).
āUncrossā the subscripts to determine the charge on iron.

As a double check, look on the periodic table: Is the charge on sulfide 2-? Yes! This means that the formula has not been reduced and this method is valid.
Iron is multivalent, so it will either be iron(II) or iron(III).
āUncrossā the subscripts to determine the charge on iron.

As a double check, look on the periodic table: Is the charge on sulfide 2-? Yes! This means that the formula has not been reduced and this method is valid.
Write the name of the anion (if it is a polyatomic, do not change the ending; if it is a non-metallic element, change the ending to āideā).
S is the non-metal sulfur, so the end changes to āide.ā
sulfide
sulfide
Combine the ion names, including the Roman numeral representing the charge on the cation.
iron(III) sulfide
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/c0odxvlpcc
Identify the composition of the compound.
Snāmultivalent metal
Oānon-metal
This is an ionic compound that needs Roman numerals.
Oānon-metal
This is an ionic compound that needs Roman numerals.
Write the name of the cation.
tin
Tin is multivalent, so it will either be tin(II) or tin(IV).
āUncrossā the subscripts to determine the charge on tin.

As a double check, look on the periodic table: Is the charge on oxide 1ā? No! This means that the formula has been reduced, the charge on oxide is 2ā, so this compound has been reduced by a factor of 2; therefore the charge on Sn needs to be doubledāĀ«math»«msup»«miĀ»SnĀ«/mi»«msup»«mnĀ»4Ā«/mn»«moĀ»+Ā«/mo»«/msup»«/msup»«/mathĀ».
Tin is multivalent, so it will either be tin(II) or tin(IV).
āUncrossā the subscripts to determine the charge on tin.

As a double check, look on the periodic table: Is the charge on oxide 1ā? No! This means that the formula has been reduced, the charge on oxide is 2ā, so this compound has been reduced by a factor of 2; therefore the charge on Sn needs to be doubledāĀ«math»«msup»«miĀ»SnĀ«/mi»«msup»«mnĀ»4Ā«/mn»«moĀ»+Ā«/mo»«/msup»«/msup»«/mathĀ».
Write the name of the anion (if it is a polyatomic, do not change the ending; if it is a non-metallic element, change the ending to āideā).
O is the non-metal oxygen, so the end changes to āide.ā
oxide
oxide
Combine the ion names, including the Roman numeral representing the charge on the cation.
tin(IV) oxide
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/xp3pxkknks
Identify the composition of the compound.
Crāmultivalent metal
Ā«math»«msubsup»«miĀ»NOĀ«/mi»«mnĀ»3Ā«/mn»«moĀ»-Ā«/mo»«/msubsup»«/mathĀ»āpolyatomic
This is an ionic compound that needs Roman numerals.
Ā«math»«msubsup»«miĀ»NOĀ«/mi»«mnĀ»3Ā«/mn»«moĀ»-Ā«/mo»«/msubsup»«/mathĀ»āpolyatomic
This is an ionic compound that needs Roman numerals.
Write the name of the cation.
chromium
Chromium is multivalent, so it will either be chromium(II) or chromium(III).
āUncrossā the subscripts to determine the charge on tin.

As a double check, look on the table of polyatomics: Is the charge on NO3 1ā? Yes! This means that the formula has not been reduced and this method is valid.
Chromium is multivalent, so it will either be chromium(II) or chromium(III).
āUncrossā the subscripts to determine the charge on tin.

As a double check, look on the table of polyatomics: Is the charge on NO3 1ā? Yes! This means that the formula has not been reduced and this method is valid.
Write the name of the anion (if it is a polyatomic, do not change the ending; if it is a non-metallic element, change the ending to āideā).
«math»«msubsup»«mi»NO«/mi»«mn»3«/mn»«mo»-«/mo»«/msubsup»«/math» is a polyatomic.
nitrate
nitrate
Combine the ion names, including the Roman numeral representing the charge on the cation.
chromium(III) nitrate
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/zqjej3g4eu
Read This
Please read page 44 in your Science 10 textbook. Make sure you take notes on your readings to study from later. You should focus on how to determine the charge on the
multivalent ion in an ionic compound. Remember, if you have any questions or you do not understand something, ask your teacher!
Practice Questions
Complete the following practice questions to check your understanding of the concept you just learned. Make sure you write complete answers to the practice questions in your notes. After you have checked your answers, make corrections to your responses
(where necessary) to study from.- Provide the correct IUPAC name for each of the following compounds.
CrBr3 HgS Ni2O3 MnO2 Fe3(Po4)2
CrBr3 chromium(III) bromide HgS mercury(II) sulfide Ni2O3 nickel(III) oxide MnO2 manganese(IV) oxide Fe3(Po4)2 iron(II) phosphate
Hydrated Ionic Compounds
Did you know that there are some solid ionic compounds that have water as part of their ionic formula?

B5.13 Desiccant pack

Ā© Wikimedia Commons
B5.16 Hydrated copper(II) sulfate
B5.16 Hydrated copper(II) sulfate

Ā© Wikimedia Commons
B5.17 Dehydrated copper(II) sulfate
B5.17 Dehydrated copper(II) sulfate

Desiccant packets are added to substances to absorb water; this prevents mold, mildew, and corrosion. These desiccants are anhydrous forms of hydrated
ionic compounds. It is important to note that hydrated compounds are not solutions; they are actually dry solids.
In these compounds, water is bound in the hydrated crystal lattice structure with a fixed ratio of water molecules. If the water is removed, the properties of the substance change and the compound is referred to as the anhydrous form. Some anhydrates are used as drying agents because they absorb water efficiently. The water in the formulas affects the properties of the compound, such as shape, colour, or melting point. Notice that the compound in image B5.16 is blue, whereas once it is dehydrated, it is white, as in image B5.17. Adding water back to the anhydrous form will re-create the hydrated compound, as in image B5.18.
The key guidelines to remember when assigning IUPAC names for hydrates are as follows:
In these compounds, water is bound in the hydrated crystal lattice structure with a fixed ratio of water molecules. If the water is removed, the properties of the substance change and the compound is referred to as the anhydrous form. Some anhydrates are used as drying agents because they absorb water efficiently. The water in the formulas affects the properties of the compound, such as shape, colour, or melting point. Notice that the compound in image B5.16 is blue, whereas once it is dehydrated, it is white, as in image B5.17. Adding water back to the anhydrous form will re-create the hydrated compound, as in image B5.18.
The key guidelines to remember when assigning IUPAC names for hydrates are as follows:
- The ionic compound is named first using the guidelines you have already learned.
- The second part is often referred to as the water of crystallization and is named by writing "-water (1/n)", where ānā is the coefficient in front of the water portion.
- When the chemical formula for a hydrated ionic compound is written, the formula for the ionic compound is separated from the waters of hydration by a centred "dot."
Examples
Each example has a video to go with it. To play the video, click on the play icon next to the example.Naming Hydrates
Name the ionic portion of the hydrate using the rules already learned.
barium hydroxide
In brackets, write the ratio of ionic compound to water molecules.
barium hydroxide-water (1/8)
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/by7w3jvghh
Name the ionic portion of the hydrate using the rules already learned.
calcium nitrate
In brackets, write the ratio of ionic compound to water molecules.
calcium nitrate-water (1/4)
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/4kn1d6c77z
Writing Formulas of Hydrates
Write the formula for the ionic portion of the hydrate using the rules already learned.
FeSO4
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/cy329tvg3n
Write the formula for the ionic portion of the hydrate using the rules already learned.
Na2CO3
Watch this video to see a teacher work through this example. https://adlc.wistia.com/medias/gzxr95f6hp
Did You Know?
The classical naming system of hydrates uses Greek prefixes. Copper(II) sulfate-water (1/5) is classically known as copper(II) sulfate pentahydrate.

Ā© Wikipedia
B5.19 Gypsum
B5.19 Gypsum

B5.20 caste made from plaster of Paris
Gypsum and plaster of Paris are two separate hydrates of the same ionic compound that can be converted from one form to the other. By heating the gypsum to release steam, plaster of Paris is formed; and if water is added to plaster of Paris, gypsum is formed.
Gypsum is a mineral that is used to make drywall for construction.
Once gypsum is heated, it is converted into plaster of Paris.
CaSO4ā¢2H2O + heat ā CaSO4ā¢0.5H2O + 1.5H2O (released as steam)
Plaster of Paris is a fine powder that when mixed with water, creates resilient lightweight solid. This is the traditional method for making orthopedic castes.
Practice Questions
Complete the following practice questions to check your understanding of the concept you just learned. Make sure you write complete answers to the practice questions in your notes. After you have checked your answers, make corrections to your responses
(where necessary) to study from.- Provide the correct IUPAC name for each of the following hydrates.
CoCl2ā¢6H2O sodium sulfate-water (1/10) nickel(II) nitrate-water (1/9) ZnSO4ā¢7H2O
cobalt(II) chloride-water (1/6) CoCl2ā¢6H2O sodium sulfate-water (1/10) Na2SO4ā¢10H2O nickel(II) nitrate-water (1/9) Ni(NO3)2ā¢9H2O zinc sulfate-water (1/7) ZnSO4ā¢7H2O
Naming Ionic Compounds
You will be successful with ionic nomenclature if you follow the guidelines and ensure the ion charges combine to create a neutral compound.

B5.21 Salt
You have had the opportunity to look at systematically naming and writing formulas for many compounds. By following guidelines and principles, the seemly overwhelming task of being able to name all ionic compounds has become a manageable task!
In the next lesson, you will learn the guidelines for naming molecular compounds.
Click on The Chemistry Name Game below to view.
In the next lesson, you will learn the guidelines for naming molecular compounds.
Click on The Chemistry Name Game below to view.
Naming Ionic Compounds
Naming Ionic Compounds ©Khan Academy
- Click on the play icon to open the interactive activity. The activity can also be accessed at https://quick.adlc.ca/khan
- Work through each of the problems, providing the IUPAC name for each compound.
- If you are stuck, there is a hint button that will provide you with guidance.
- Once you have answered all questions, you can either select
or you can move on to the next topicāPractice: Finding the formula for ionic compoundsā found on the bottom left of the screen.
2.4 Assignment
Unit 2 Assignment Lessons 5-8
It is now time to complete the Lesson 5 portion of 2.4 Assignment. This assignment has two parts.
- Part 1 Written Portion: Select the preferred document type from the options below. Download and save the assignment on your desktop (or documents folder).
PDF Document - Open and print this saved document.
- Record your responses in the appropriate textboxes.
- When you have completed the assignment, scan it and save it on your desktop (or documents folder).
- Once you have completed the written portion of your assignment, click on the button below to go to the submission page.
Written Portion Submission Page - Part 2 Online Portion: It is now time to complete the Lesson 5 questions of the online portion of this assignment. Click on the button below to go to the online questions of this assignment.
Online Questions
This assignment is worth ___% of your final grade.