P ( A ) = P (leave Winnipeg on time) = 0.70 P ( A and B ) = P ( A ∩ B ) = P (arrive in Calgary on time and leave Winnipeg on time) = 0.56 P ( B | A ) = P (arrive Calgary on time given leave Winnipeg on time) = ?
The probability that the plane will arrive in Calgary on time given that it left Winnipeg on time is 0.80 or 80%. |
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Watch the video to see more examples involving conditional probability. |
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Read pages 185-186 Example 3 in your textbook, Principles of Mathematics 12 . Complete the Your Turn question on page 186 (a) for more practice on conditional probability. Click here to verify your answer . |
When much background information is known about a situation, predictions of future events are possible. A probability tree diagram helps sort this information as you proceed through the problem. Read in your textbook to see how.
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Read pages 186-187 Example 4 in your textbook, Principles of Mathematics 12 . Complete the Your Turn questions on page 187 (a & b) for more practice on making predictions using dependent events. Click here to verify your answers . Read page 188 In Summary and page 197 In Summary in your textbook, Principles of Mathematics 12 . |