Lesson 2 β€” Mendel's Laws and Monohybrid Crosses


Test Cross


Read page 591

In a test cross, an individual with the recessive phenotype is crossed with an individual with unknown genotype displaying the dominant phenotype. Phenotypically dominant individuals can be either homozygous dominant or heterozygous. No way is available to determine which genotype they have by looking at them. To help with this problem, geneticists conduct test crosses in which the unknown is crossed with a homozygous recessive individual (such as aa or bb). The results of the cross indicate if the unknown was heterozygous or homozygous.

Two outcomes are possible:

  1. If all resultant offspring express the dominant trait, then the parent of unknown genotype is homozygous dominant.
  2. If half the offspring express the recessive trait, then the parent of unknown genotype is heterozygous.
Read more about a test cross and how to perform one on page 591 of your textbook.


How to Perform a Test Cross

You were given a yellow seeded pea plant. To determine the genotype of yellow seeded plants, you performed a test cross. After the test cross, you obtained 50% yellow and 50% green seeded pea plants. What is the genotype of the P1 yellow seeded pea plants?


Yellow and green seed colours.  Β© Jan 17, 2020 OpenStax. Textbook content produced by OpenStax is licensed under a Creative Commons Attribution License 4.0 license. Access for free


  1. Let Y represent the dominant allele for yellow seed. Let y represent the recessive allele for green seed.

    The phenotypically yellow seeded P1 plant can have YY or Yy genotype.

  2. There are two possibilities (YY or Yy), and we will cross both with a homozygous recessive green pea plant (yy).

  3. If unknown is YY:

    P1 Cross = YY x yy


     Y  Y
     y  Yy  Yy
     y  Yy  Yy

    F1 Generation Phenotype = 100% yellow seeded plants
    If unknown is Yy:

    P1 Cross = Yy x yy


     Y  y
     y  Yy  yy
     y  Yy  yy

    F1 Generation Phenotype = 50% yellow seeded plants : 50% green seeded plants

  4. Analyze the result: Because the F1 generation yielded 50% yellow and 50% green seeded plants, the genotype of the unknown yellow seeded plant is heterozygous dominant (Yy).


Note: A large sample size is required to determine the unknown parental genotype to ensure that the F1 generation phenotype ratio did not occur due to chance.



Watch and Listen

As you watch the following video on monohybrid crosses, look for answers to the questions below.

 

 Β©Alberta Education. Classical Genetics and Monohybrid Crosses: The Laws of Gregor Mendel (13:16-28:55); Series 25.  LearnAlberta.ca

 


  1. Explain Mendel's first law in your own words.

  2. What does a Punnett square tell you in a cross?

  3. Given two heterozygous parents for pea type (such as Rr), what phenotypic and genotypic ratios are expected in their offspring?

  4. What does a test cross help to determine?

  1. The Law of Segregation states that each allele pair in the parents is separated randomly in the production of gametes.

  2. Punnett square is a chart used to predict the outcome of a cross. It shows all possible combinations of genotypes in offspring.

  3. Given two heterozygous parents for pea type (such as Rr and Rr), the phenotype ratio is 3:1 and the genotypic ratio is 1:2:1.

     R  r
     R  RR  Rr
     r  Rr  rr

    Phenotype Ratio = 3 round (RR and Rr) : 1 wrinkled (rr)
    Genotype Ratio = 1 RR : 2 Rr : 1 rr

  4. Test crosses help determine the genotype of a phenotypically dominant individual.

Biology 30 Β© 2008  Alberta Education & its Collaborative Partners ~ Updated by ADLC 2019