Lesson 6 — Polygenic Traits


Polygenic Traits


Read pages 605 - 607

Many traits are regulated by more than one gene. Skin colour, eye colour, and height are a few examples in humans. For each of these traits, many genes interact to form the final phenotype. To make things a bit easier to understand, this lesson focuses on traits that result from the interaction of only two genes. Traits that are controlled by more than one gene area called polygenic traits.

Polygenic traits are caused mainly by two means: complementary interaction and suppression epistasis. A complementary interaction occurs when two genes must be present to yield a specific phenotype. An epistatic gene interferes with the expression of another gene. 


Complementary Interaction

The example of chicken combs from the introduction follows the complementary interaction type. In this case, two genes combine to form a phenotype that is not capable of producing itself alone.


Various types of chicken combs. Dr. Dana Krempels. University of Miami.  Used under the Fair Dealings Provision of the Canadian Copyright Act.


One of the genes, the rose gene, has two alleles: an "R" for a rose comb that is dominant over an "r" allele that leads to a single comb. The other gene, the pea gene, also has two alleles: a "P" for a pea comb that is dominant over a "p" allele that also leads to a single comb. Remember that a chicken has both of these genes at the same time. The possible genotypes for the given phenotypes are given in this table:

 Rose comb
 RRpp or Rrpp  One dominant 'R' allele is required to express the rose comb phenotype.
 Pea comb
 rrPP or rrPp
 One dominant 'P' allele is required to express the pea comb phenotype.
 Single comb
 rrpp  All recessive alleles result in a single comb.


The forth phenotype is the walnut comb. This results from the presence of both dominant alleles in the two different genes. The possible genotypes for this are in the following table:

Walnut comb  
RRPP  RrPP  RRPp  or RrPp   
 Two dominant alleles (R and P) are required to express the walnut comb phenotype.  


When analyzing polygenic traits, realize that the movement of alleles follows the same patterns as in dihybrid crosses. However, the resulting genotypes must be interpreted for only one trait instead of two. For example, if a true breeding rose chicken (RRpp) was crossed with a true breeding pea chicken (rrPP), the F1 would be all walnut (RrPp).



 Rp
rP
 RrPp


In the F2, there would be a 9 walnut : 3 rose : 3 pea : 1 single comb phenotypic ratio. This looks just like Mendel's work until you remember that those ratios are for four different phenotypes of one trait only.


Genotypes of the F2 Generation


 RP  Rp  rP  rp
 RP  RRPP  RRPp  RrPP  RrPp
 Rp  RRPp  RRpp  RrPp  Rrpp
 rP  RrPP  RrPp  rrPP  rrPp
 rp  RrPp  Rrpp  rrPp  rrpp
Phenotypes of the F2 Generation


 RP  Rp  rP  rp
 RP Walnut Walnut Walnut Walnut
 Rp Walnut Rose Walnut   Rose
 rP Walnut Walnut   Pea Pea
 rp Walnut Rose Pea Single


Suppression Epistasis



© Getty Images

This type of gene interaction occurs when one gene masks the expression of another gene. A good common example is coat colour in mice. Here, one gene determines if pigment is produced at all, and another gene determines the type of pigment, such as black or brown.

In the example, the gene that controls the production of pigment has two alleles. The allele to produce pigment "C" is dominant over the allele that leads to no pigment, "c". The other gene that controls the colour of the pigment also has two alleles. "B" is dominant and produces a black pigment, but "b" is recessive and  leads to brown pigment.

The possible phenotypes and their genotypes for this trait are provided in this table:

Black
BBCC  BbCC  BBCc  BbCc
Must have dominant alleles for both genes
Brown
bbCC  bbCc
Must be homozygous recessive for "B" gene and have at least one dominant allele for "C" gene
White BBcc  Bbcc  bbcc
Must be homozygous recessive for "C" gene

When you are trying to determine phenotype in the case of epistasis, considering a flow chart such as the one below often is helpful.



 

© Getty Images


For an example cross, start with a black mouse (BBCC) and a white mouse (bbcc). The F1 generation will all be black (BbCc).

 BC
 bc  BbCc




In the F2 generation (BbCc X BbCc), there will be 9 black : 3 brown : 4 white mice.

Genotypes of the F2 Generation


 BC  Bc  bC  bc
 BC  BBCC  BBCc  BbCC  BbCc
 Bc  BBCc  BBcc  BbCc  Bbcc
 bC  BbCC  BbCc  bbCC  bbCc
 bc  BbCc  Bbcc  bbCc  bbcc
Phenotypes of the F2 Generation


 BC  Bc  bC  bc
 BC Black Black Black   Black
 Bc Black White Black White
 bC Black Black Brown Brown
 bc Black White Brown White

This is an unusual ratio and not the typical 9:3:3:1 you might have expected, but it is characteristic for epistasis.


Biology 30 © 2008  Alberta Education & its Collaborative Partners ~ Updated by ADLC 2019