Module 6 Lesson 8 - 4
Lesson 8 — Crossing Over Frequencies and Gene Mapping
Discuss
The Human Genome Project was one of the largest genetic projects ever completed. It involved the participation of public universities and private companies from around the world, and it took more than 13 years to complete. Now that it is complete, scientists have a relative map of all human genes found on all chromosomes.
However, the project was not without controversy. To encourage private companies to participate, they were allowed to patent certain tests that can locate specific genes in people, such as genes that may predict if a person will develop cancer. As a result, if a person is at risk for developing cancer due to family histories, hospitals must pay these companies to be granted the right to conduct these tests. In addition, tests for the presence of certain genes may also provide information about other genes that were not originally considered. This kind of information may be very dangerous if the information became available to insurance companies or to a person's place of employment.
Self-Check
Answer the following questions to check your understanding of the material to this point.
- If there were 50 recombination phenotypes in 250 offspring, what is the map distance between the linked alleles?
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A three-point test cross is performed to identify the locus of each of three alleles in relation to one another. The results were as follows:
- AC recombinations = 225
- BC recombinations = 165
- AB recombinations = 60
- Parental linkages = 550
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Total offspring = 1000
Show the positions and map the distances apart for each allele (A, B, and C) on a chromosome. Calculate the map units, then draw the chromosome.
Self-Check Answers
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«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»R«/mi»«mi»e«/mi»«mi»c«/mi»«mi»o«/mi»«mi»m«/mi»«mi»b«/mi»«mi»i«/mi»«mi»n«/mi»«mi»a«/mi»«mi»n«/mi»«mi»t«/mi»«mo»§#160;«/mo»«mi»F«/mi»«mi»r«/mi»«mi»e«/mi»«mi»q«/mi»«mi»u«/mi»«mi»e«/mi»«mi»n«/mi»«mi»c«/mi»«mi»y«/mi»«mo»§#160;«/mo»«mo»=«/mo»«mo»§#160;«/mo»«mfrac»«mn»50«/mn»«mn»250«/mn»«/mfrac»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»100«/mn»«mo»%«/mo»«mo»§#160;«/mo»«mo»=«/mo»«mo»§#160;«/mo»«mn»20«/mn»«mo»%«/mo»«/math»
Because 1% crossover represents 1 map unit, 20% crossover would mean 20 map units apart. -
The crossover percentages and map units are as follows:
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«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»A«/mi»«mi»C«/mi»«mo»§#160;«/mo»«mo»=«/mo»«mo»§#160;«/mo»«mfrac»«mn»225«/mn»«mn»1000«/mn»«/mfrac»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»100«/mn»«mo»%«/mo»«mo»§#160;«/mo»«mo»=«/mo»«mo»§#160;«/mo»«mn»22«/mn»«mo».«/mo»«mn»5«/mn»«mo»%«/mo»«mo»§#160;«/mo»«mo»=«/mo»«mo»§#160;«/mo»«mn»22«/mn»«mo».«/mo»«mn»5«/mn»«mo»§#160;«/mo»«mi»m«/mi»«mo».«/mo»«mi»u«/mi»«mo».«/mo»«/math»
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«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»B«/mi»«mi»C«/mi»«mo»§#160;«/mo»«mo»=«/mo»«mo»§#160;«/mo»«mfrac»«mrow»«mn»165«/mn»«mo»§#160;«/mo»«/mrow»«mn»1000«/mn»«/mfrac»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»100«/mn»«mo»%«/mo»«mo»§#160;«/mo»«mo»=«/mo»«mo»§#160;«/mo»«mn»16«/mn»«mo».«/mo»«mn»5«/mn»«mo»%«/mo»«mo»§#160;«/mo»«mo»=«/mo»«mo»§#160;«/mo»«mn»16«/mn»«mo».«/mo»«mn»5«/mn»«mo»§#160;«/mo»«mi»m«/mi»«mo».«/mo»«mi»u«/mi»«mo».«/mo»«/math»
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«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mi»A«/mi»«mi»B«/mi»«mo»§#160;«/mo»«mo»=«/mo»«mo»§#160;«/mo»«mfrac»«mn»60«/mn»«mn»1000«/mn»«/mfrac»«mo»§#160;«/mo»«mo»§#215;«/mo»«mo»§#160;«/mo»«mn»100«/mn»«mo»%«/mo»«mo»§#160;«/mo»«mo»=«/mo»«mo»§#160;«/mo»«mn»6«/mn»«mo».«/mo»«mn»0«/mn»«mo»%«/mo»«mo»§#160;«/mo»«mo»=«/mo»«mo»§#160;«/mo»«mn»6«/mn»«mo».«/mo»«mn»0«/mn»«mo»§#160;«/mo»«mi»m«/mi»«mo».«/mo»«mi»u«/mi»«mo».«/mo»«mo»§#160;«/mo»«/math»
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Therefore, the mapped chromosome would look like this:

Diploma Connection
Answer the following questions from a previous Biology 30 Diploma Examination.
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During meiosis, which of the following pairs of genes has the greatest chance of being separated by crossing over?
- (m) and (d)
- (ne) and (p)
- (m) and (lc)
- (p) and (o)
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The cross over frequency between genes O and S is
- 6%
- 29%
- 31%
- 97%
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On human chromosome 6, the order of the genes numbered above is ___, ___, ___ and ___.
-
What is the approximate cross over frequency between the diabetes mellitus gene and the ragweed sensitivity gene?
- 1.5%
- 10.5%
- 15.0%
- 22.5%
-
smooth, green seeds
-
wrinkled, green seeds
-
smooth, yellow seeds
- wrinkled, yellow seeds
-
If the traits for seed coat texture and seed coat colour had been located close together on the same chromosome, Mendel might not have conceptualized
- gene pairs
- dominance
- the Law of Segregation
- the Law of Independent Assortment
Use the following information to answer the next question.
Use the following additional information to answer the next question.
Genes | Recombinant Frequency |
normal leaf (M) and tall plant (D) | 12% |
normal leaf (M) and normal tomato (O) | 33% |
normal leaf (M) and simple inflorescence (S) | 64% |
tall plant (D) and normal tomato (O) | 21% |
tall plant (D) and simple inflorescence (S) | 52% |
Use the following information to answer the next two questions.
Cross over Frequencies of Some Genes on Human Chromosome 6 | |
Genes | Approximate Recombinant Frequencies |
Diabetes mellitus (1) and ovarian cancer (2) |
21% |
Diabetes mellitus (1) and Rhesus blood group (3) |
12% |
Ragweed sensitivity (4) and Rhesus blood group (3) |
10.5% |
Rhesus blood group (3) and ovarian cancer (2) |
9% |
Ragweed sensitivity (4) and ovarian cancer (2) |
19.5% |
Numerical Response
Use the following information to answer the next question.
Gregor Mendel examined the inheritance of two traits in pea plants: seed coat texture and colour. Seed coat texture can be represented as S-smooth and s-wrinkled, and seed coat colour can be represented as Y-yellow and y-green. SSYY plants were crossed with ssyy plants to yield F1 pea seeds that were all smooth and all yellow. By crossing plants grown from these F1 seeds, Mendel obtained four different phenotypes of F2 seeds:
Diploma Exam Answers
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C
Mottled and many locules are on the farthest sides of the chromosome segment. -
C
M - 12 -D -- 21 -- O --- 33 --- S -
1432 or 2341
-
A
- D