11.7 Charges moving through Parallel Plates
Self-CheckAnswer the following self-check (SC) question then click the "Check your work" bar to assess your response. |
SC 19.
The following diagram shows an electron entering the region between two oppositely charged plates. The plates are 55.0-mm long and are separated by 19.5 mm. A potential difference of 0.133 V across the plates generates a uniform electric field in the region between the plates. The electron is given an initial velocity of 8.50 × 10 5 m/s in the positive y direction. Use this information to determine the final velocity of the electron when it leaves the region between the plates.
Be sure to begin your solution with a free-body diagram and an analysis of the physics principles that will support your solution.
Self-Check Answer
SC 19.
Given
Required
The magnitude and direction of the final velocity of the electron.
Analysis and Solution
Step 1: Free-body diagram and statement of the physics principles.
-
The electric field between the plates points in the negative
x
direction.
-
Since the particle is negatively charged, the electrostatic force on the particle will act in the positive
x
direction.
-
The electrostatic force will cause the particle to accelerate in the positive
x
direction. This is in accordance with Newton's second law of motion.
-
Since there is no unbalanced force acting in the
y
direction, the particle will move with uniform motion in the positive
y
direction. This is in accordance with Newton's first law of motion.
- The path of the particle is a parabolic trajectory. This is a consequence of uniform motion in the positive y direction combined with accelerated motion in the positive x direction.
Step 2: Determine the magnitude of the electrostatic force.
Step 3: Determine the magnitude of the acceleration in the positive x direction
Step 4: Determine the time for the particle to travel to the end of the region between the plates. Use the fact that the motion in the y direction is uniform.
Step 5: Determine the final velocity in the x direction.
Step 6: Use the x and y components to find the final velocity. Since the motion in the y direction is uniform v f y = +8.50 × 10 5 m/s.

Paraphrase
The final velocity of the electron when it leaves the region between the plates is 8.54 × 10 5 m/s [85°].