In Thomson's experiment, the arrangement with a crossed (perpendicular) pair of uniform electric and magnetic fields is called a velocity selector.  If charged particles with various velocities enter the fields, only those whose velocity is perpendicular to both fields and whose speed satisfies v=EB  will continue in a straight line.  This arrangement is, therefore, able to select charged particles of a given velocity from all other particles by setting the fields to appropriate values.  Velocity selectors have an application in mass spectrometers.


The arrangement can be used to measure the speed of charged particles.  One must adjust the electric and magnetic fields until there is no deflection and then use the equation to solve for the speed.  Note that the value of the speed for which there is no deflection depends on neither the charge nor the mass of the particle.  Therefore, you can use a velocity selector to measure the speed of charged particles even if you do not know their charge or their mass like in the simulation.

 


Read
Read "Charge-to-mass Ratio of the Electron" on page 755 of your physics textbook.

 

Determining the Charge-to-Mass Ratio of a Cathode Ray Particle

Having determined the speed of the particles as they are coming from the source, you now have to perform a second experiment to determine the charge-to-mass ratio.  In the second experiment the particles go through the same apparatus, but with one of the fields turned off.  In this circumstance one field will deflect the particles because there is no other force from the other field to balance it.

Recall that a magnetic force will produce a perpendicular force on a moving charge as determined by the hand rule.  The uniform perpendicular force will cause the charged particle to move along a circular path of constant radius.  Therefore,

Finward = Fm

Given the definitions of the inward, centripetal force and the magnetic force, it is possible to derive an equation for the charge-to-mass ratio of the particle exhibiting circular motion in the magnetic field alone.

In a Thomson-style experiment, the velocity is first determined using both a known magnetic and electric field.  Then, by turning off the electric field and measuring the radius of the circular path made by the charged particles, you would be able to determine the charge-to-mass ratio of the particles.

Turn off the electric field strength by setting it to 0 V/m in the charge-mass simulation, but leave the magnetic field strength at 2.00T and the speed at 50.0 m/s.  Allow the simulation to run by pressing play.  The data will now display the radius, r. Record this value below and use it in the formula above to determine the charge to mass ratio used in the simulation.


r = ____ m


Thomson determined that the charge-to-mass ratio of the particles in a cathode ray was 1.76 × 1011 C/kg.  This value was unique to all cathode rays regardless of the metal electrodes used to produce them.  Thomson had discovered the electron, but, more importantly, he had determined that the charge-to-mass ratio for an electron was thousands of times larger than that of a hydrogen ion, which meant that the electron was a "subatomic" particle.  He proposed a radical idea at the time - the atom was divisible into smaller particles.  And, because no positive subatomic particles had been discovered at the time, he suggested that the atom consisted of electrons embedded in a blob of massless positive charge, what is now known as the raisin-bun model of the atom. You will learn more about this model later on in the lesson.


Read
Read "Determining Charge-to-mass Ratios" on pages 757 to 758 of your physics textbook.

 Self-Check

Answer the following self-check questions then click the "Check your work" bar to assess your responses.

SC 3. Using the charge and mass values on your physics data sheet, what is the charge-to-mass ratio of aNo

  1. proton
  2. alpha particle
  3. neutron

SC 4. How many times larger is the charge-to-mass ratio of the electron than the proton?

Self-Check

Contact your teacher if your answers vary significantly from the answers provided here.

SC 3.

  1. Proton

The charge-to-mass ratio of the proton is 9.58 × 107 C/kg.

  1. Alpha particle

The charge-to-mass ratio of the alpha particle is 4.81 × 107 C/kg.

  1. Neutron

The neutron is neutral, so it has no charge; as a result, the charge-to-mass ratio is zero.

 

SC 4.

Given

 

Required

the number of times larger the electron's charge-to-mass ratio is than the proton's charge-to-mass ratio

 

Analysis and Solution

 

Paraphrase

The charge-to-mass ratio of the electron is 1.84 × 103 larger.