Tangent Side Length Ratios Examples
Completion requirements
Lesson 1: The Tangent Ratio - Tangent Side Length Ratios Examples
Multimedia
A video describing the use of the tangent ratio table is provided.
EXAMPLE 1
The ratios for angle measures of 35° and 50° have been left blank in the table from the previous section. Draw a right triangle with an acute angle of 35°, and measure the opposite and adjacent side lengths. Use these lengths to calculate the \(\frac{\text{length opposite}\,\theta}{\text{length adjacent to}\,\theta}\) ratio for 35°. Repeat this process for 50°. Complete the table on the previous page.
Solution
The ratio for 35° is approximately 0.70, and the ratio for 50° is approximately 1.19
EXAMPLE 2
Use the table from the previous section to state a ratio of sides for each of the following triangles. Explain what each ratio represents.
Solution
- The value produced when the length of the side opposite 25° is divided by the length of the side adjacent to 25° is 0.47
- The value produced when the length of side b is divided by the length of side a is 2.14
EXAMPLE 3
Use the table from the previous section to determine the values of the variables.
Solution
- \(\frac{6}{6}=1,\,\text{so}\,x=45°\)
- \(\frac{42.0}{15.3}=2.75,\,\text{so}\,y=70°\)
EXAMPLE 4
Use the table from the previous section to determine the value of the unknown variable, to the nearest tenth, in the triangle shown.

Solution
\(\begin{align} \frac{\text{length opposite 20°}}{\text{length adjacent to 20°}}&=0.36 \\ \\ \frac{v}{15}&=0.36 \\ \\ \frac{v}{\cancel{15}}\times \cancel{\color{red}{15}}&=0.36\times {\color{red}{15}} \\ \\ v&=5.4 \\ \end{align}\)
Now, it is your turn! Complete the questions in your Chapter 4, Lesson 1 Practice Makes Perfect that refer to Tangent Side Length Ratios.
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