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\(4x + 6\) and \(3x - 2\) are two consecutive terms in an arithmetic sequence. Write the common difference, \(d\), in terms of \(x\).
\(\begin{array}{l}
d = t_2 - t_1 \\
d = 3x - 2 - \left( {4x + 6} \right) \\
d = -x - 8 \\
\end{array}\)
d = t_2 - t_1 \\
d = 3x - 2 - \left( {4x + 6} \right) \\
d = -x - 8 \\
\end{array}\)
For further information about arithmetic sequences, see pp. 6 - 12 of Pre-Calculus 11. |