Example 1
Completion requirements
| Example 1 |
Solve \(x^2 = 9\).
\(\begin{align}
x^2 &= 9 \\
\sqrt {x^2 } &= \pm \sqrt 9 \\
x &= \pm 3 \\
\end{align}\)
The value of \(x\) is both positive and negative three because \(3^2 = 9\) and \(\left({-3} \right)^2 = 9 \).
x^2 &= 9 \\
\sqrt {x^2 } &= \pm \sqrt 9 \\
x &= \pm 3 \\
\end{align}\)
The value of \(x\) is both positive and negative three because \(3^2 = 9\) and \(\left({-3} \right)^2 = 9 \).