Determine the solution set to \(3a - 1 \le 17 - 5a\). Show the solution set on a number line. Use a value of the solution set to verify the solution.


\[\begin{align}
 3a - 1 &\le 17 - 5a \\
 8a &\le 18 \\
 a &\le \frac{9}{4} 
 \end{align}\]


The solution set is {\(a | a \le \frac{9}{4}, \thinspace a \in \rm{R}\)}.

Verification using \(x = 0\):

Left Side Right Side
\(\begin{array}{r}
 3a - 1 \\
 3\left( 0 \right) - 1 \\
  - 1  \end{array}\)

\(\begin{array}{l}
 17 - 5a \\
 17 - 5\left( 0 \right) \\
 17 \end{array}\)

LS \(\le \) RS