Solve the inequality \(x^2 - 2x \le 24\). Represent the solution set symbolically and on a number line.


Rearrange the inequality such that one side is zero.

\(\begin{align}
 x^2 - 2x &\le 24 \\
 x^2 - 2x - 24 &\le 0
 \end{align}\)


Determine the zeros of the corresponding function.

\(\begin{align}
 x^2 - 2x - 24 &= 0 \\
 \left( {x - 6} \right)\left( {x + 4} \right) &= 0
 \end{align}\)


\(\begin{align}
 x - 6 &= 0 \\
 x &= 6
 \end{align}\)

\(\begin{align}
 x + 4 &= 0 \\
 x &= -4
 \end{align}\)


The coefficient on \(x^2\) is positive, so the parabola will open up. Use the direction of opening and the zeros to sketch the graph.


The solution set is {\(x | -4 \le x \le 6, \thinspace x \in \rm{R}\)}.

Plot the solution set on a number line.