Unit A: Geometry

Chapter 1: Polygons


Practice


Instructions: Click the Download File button to download a printable PDF of the questions. Answer each of the following practice questions on a separate piece of paper. Step by step solutions are provided under the Solutions tab. You will learn the material more thoroughly if you complete the questions before checking the answers.


 1.
Complete the table below.

Triangle Classify with regard to angle measure.
Hint: Is the triangle acute, obtuse, or right?
Classify with regard to side length.
Hint: Is the triangle equilateral, isosceles, or scalene?
State the angle measure if any of the angles in the triangle are equal.

2.
Find the missing angle in each triangle

a.

 
 
 
b.

 
 
 
c.

 
 
 

1.
Complete the table below.

Triangle Classify with regard to angle measure.
Hint: Is the triangle acute, obtuse, or right?
Classify with regard to side length.
Hint: Is the triangle equilateral, isosceles, or scalene?
State the angle measure if any of the angles in the triangle are equal.


Triangle Classify with regard to angle measure.
Hint: Is the triangle acute, obtuse, or right?
Classify with regard to side length.
Hint: Is the triangle equilateral, isosceles, or scalene?
State the angle measure if any of the angles in the triangle are equal.
Right: The triangle contains a 90° angle.
Scalene: Each side is a different length.
None
Obtuse: The triangle contains an angle greater than 90°.
Isosceles: Two side lengths are equal.
∠X and ∠Z are equal; therefore,
∠X+∠Y+∠Z=180° becomes
∠X+∠Y+∠X=180°.
Substitute 130° for ∠Y.
∠X+130°+∠X=180°2∠X=50°∠X=25°
Acute: Every angle is less than 90°.
Equilateral: All three side lengths are equal.
180°3=60°

Each angle is 60°.
2.
Find the missing angle in each triangle

a.

 
 
 

List the information.

∠E=90° since it is a right angle.
∠F=33°

Substitute the known angles into the formula ∠D+∠E+∠F=180°.

∠D+90°+33°=180°∠D+123°=180°∠D=57°
b.

 
 
 

∠L+∠M+∠N=180°∠L+80°+45°=180°∠D+125°=180°∠D=55°

c.

 
 
 

The triangle is isosceles, so ∠G and ∠H are equal; therefore, ∠F+∠G+∠H=180° becomes ∠F+∠G+∠G=180°.

Substitute 30° for ∠F.

30°+∠G+∠G=180°2∠G+30°=180°2∠G=150°∠G=150°2∠G=75°