Grouping by Decomposition
Grouping by Decomposition: The steps used in this method of factoring are outlined in the following two examples.
Example 4
Factor .
Step 1: If possible, identify the GCF.
There is no GCF.
Step 2: Find a pair of numbers with a sum of b (−1 in this case) and a product of ac (−15 × 2 = −30 in this case).One strategy is to list numbers that multiply to get −30 and to then look within those pairs for a sum of −1, much like in example 3.
first number | second number | product | sum | |
1
|
−30
|
1 × −30 = −30 | 1 + −30 = −29 | ![]() |
−1
|
30
|
−1 × 30 = −30 | −1 + 30 = 29 | ![]() |
2
|
−15
|
2 × −15 = −30 | 2 + −15 = −13 | ![]() |
−2
|
15
|
−2 × 15 = −30 | −2 + 15 = 13 | ![]() |
3
|
−10
|
3 × −10 = −30 | 3 + −10 = −7 | ![]() |
−3
|
10
|
−3 × 10 = −30 | −3 + 10 = 7 | ![]() |
5
|
−6
|
5 × −6 = −30 | 5 + −6 = −1 | ![]() |
−5
|
6
|
−5 × 6 = −30 | −5 + 6 = 1 | ![]() |
Step 3: The numbers 5 and −6 add to −1 and multiply to −30. Rewrite the middle term (b-term) as two terms with coefficients 5 and −6. This step 'decomposes' the middle term into two usable terms.
Step 4: Group the first two terms and the last two terms.
Step 5: Remove the greatest common factor from each of the two groups.
Step 6: The result is a common factor, , in each group. Remove the common factor and simplify.
Verify by expanding.