Example
Example 1
Sketch the graph of the function .
Step 1: Determine the vertex.
The vertex is (h, k) so the vertex is (−1, −16).
Note that the vertex form is given as . In this example, however, the function is
, which can be rewritten in vertex form as
.
Step 2: Determine the equation of the axis of symmetry.
Use the x-coordinate of the vertex.
The equation of the axis of symmetry is x = −1.
Step 3: Determine if the function has a minimum or maximum. Since a > 0, the parabola opens up and has a minimum y-value of −16.
Step 4: Determine the y-intercept.
(0, −15)
Step 5: Graph the function.
Note that since the vertex and y-intercept are known, another point on the graph, (−2, −15), can be determined. The point (−2, −15) is a reflection of the y-intercept in the axis of symmetry (both (−2, −15) and the y-intercept are equidistant from the axis of symmetry).
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Please refer to Pages 356 and 357, Examples 1 and 2, of Principles of Mathematics 11 for more examples of graphing quadratic functions given in vertex form. |