Lesson 1
1. Lesson 1
1.8. Explore 4
Module 6: Exponents and Logarithms
In Try This 3 you may have determined that the function that modelled the amount of Iodine-131, A, and time, t, in 8-d intervals was . The function A = 2−t could also be used, since
.
The base is one-half because the amount of Iodine-131 is decreasing by half over each 8-d interval. The domain of the function is {t|t ≥ 0, t ∈ R}, and the range is {A|0 < A ≤ 1, A ∈ R}. You may have determined that it would take 4 eight-day intervals, or 32 d, for 0.0625 g of Iodine-131 to be left.
View Determining an Exponential Function to see an example of how to determine the equation of an exponential growth function from its graph.
Self-Check 2
- Complete “Your Turn” at the end of “Example 3” on page 341 of the textbook. Answer
- Complete question 11 on page 344 of the textbook. Answer
Try This 4
Open Multiple Transformations. Click on the boxes to deselect Quadratic and select Exponential.
- Use the sliders to increase and decrease the a, b, h, and k values. Describe how the parameters a, b, h, and k in the form f(x) = a(c)b(x–h) + k transform the graph. Complete a table like the one shown.
Parameter
Describe Effect on Graph
a
b
h
k
- How do your responses compare to your knowledge of transformations from past lessons?
Save your responses in your course folder.