Lesson 2
Completion requirements
Created by IMSreader
1. Lesson 2
1.6. Explore 2
Module 3: Permutations, Combinations, and the Fundamental Counting Principle
As you may have noticed in Try This 3, writing out all the factors can take a long time. Here is another way you could simplify
.
Expanding the numerator and denominator gives you the following:
![]()
As you can see, the expression in the brackets is the same as 9!; therefore, you can write
as ![]()
Dividing numerator and denominator by the common factor of 9! leaves 12 × 11 × 10 or 1320.
Self-Check 2
![]()
- Complete questions 1.a., 1.c., 1.f., 3.c., 4, 5.a., 5.c., and 5.e. on pages 81 and 82 of your textbook. Answer