L3 The Power Rule and The Sum and Differences Rules of Derivatives - Part 2
Completion requirements
Unit 2A
Derivatives Part 1
Lesson 3: The Power Rule and The Sum and Differences Rules of Derivatives
Find the derivative of «math style=¨font-family:Verdana¨ xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mstyle mathsize=¨14px¨»«mrow»«mi»y«/mi»«mo»=«/mo»«mi»x«/mi»«/mrow»«/mstyle»«/math».
Using first principles, from the previous Lesson, the derivative is as follows.
Using the power rule, the derivative is as follows.
As shown, using either method, the derivative of «math style=¨font-family:Verdana¨ xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mstyle mathsize=¨14px¨»«mrow»«mi»y«/mi»«mo»=«/mo»«mi»x«/mi»«/mrow»«/mstyle»«/math» is «math style=¨font-family:Verdana¨ xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mstyle mathsize=¨14px¨»«mn»1«/mn»«/mstyle»«/math».
Using first principles, from the previous Lesson, the derivative is as follows.
«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mtable columnalign=¨right center left¨»«mtr»«mtd»«mi»f«/mi»«mo mathvariant=¨italic¨»`«/mo»«mi mathvariant=¨normal¨»(«/mi»«mi»x«/mi»«mi mathvariant=¨normal¨»)«/mi»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«munder»«mi»lim«/mi»«mrow»«mi»h«/mi»«mo»§#8594;«/mo»«mn»0«/mn»«/mrow»«/munder»«mfrac»«mrow»«mi»f«/mi»«mi mathvariant=¨normal¨»(«/mi»«mi»x«/mi»«mo»+«/mo»«mi»h«/mi»«mi mathvariant=¨normal¨»)«/mi»«mo»§#8722;«/mo»«mi»f«/mi»«mi mathvariant=¨normal¨»(«/mi»«mi»x«/mi»«mi mathvariant=¨normal¨»)«/mi»«/mrow»«mi»h«/mi»«/mfrac»«/mtd»«/mtr»«mtr»«mtd/»«mtd»«mo»=«/mo»«/mtd»«mtd»«munder»«mi»lim«/mi»«mrow»«mi»h«/mi»«mo»§#8594;«/mo»«mn»0«/mn»«/mrow»«/munder»«mfrac»«mrow»«mi mathvariant=¨normal¨»(«/mi»«mi»x«/mi»«mo»+«/mo»«mi»h«/mi»«mi mathvariant=¨normal¨»)«/mi»«mo»§#8722;«/mo»«mfenced»«mi»x«/mi»«/mfenced»«/mrow»«mi»h«/mi»«/mfrac»«/mtd»«/mtr»«mtr»«mtd/»«mtd»«mo»=«/mo»«/mtd»«mtd»«munder»«mi»lim«/mi»«mrow»«mi»h«/mi»«mo»§#8594;«/mo»«mn»0«/mn»«/mrow»«/munder»«mfrac»«mrow»«mi»x«/mi»«mo»+«/mo»«mi»h«/mi»«mo»§#8722;«/mo»«mi»x«/mi»«/mrow»«mi»h«/mi»«/mfrac»«/mtd»«/mtr»«mtr»«mtd/»«mtd»«mo»=«/mo»«/mtd»«mtd»«munder»«mi»lim«/mi»«mrow»«mi»h«/mi»«mo»§#8594;«/mo»«mn»0«/mn»«/mrow»«/munder»«mfenced»«mfrac»«mi»h«/mi»«mi»h«/mi»«/mfrac»«/mfenced»«/mtd»«/mtr»«mtr»«mtd/»«mtd»«mo»=«/mo»«/mtd»«mtd»«munder»«mi»lim«/mi»«mrow»«mi»h«/mi»«mo»§#8594;«/mo»«mn»0«/mn»«/mrow»«/munder»«mfenced»«mn»1«/mn»«/mfenced»«/mtd»«/mtr»«mtr»«mtd/»«mtd»«mo»=«/mo»«/mtd»«mtd»«mn»1«/mn»«/mtd»«/mtr»«/mtable»«/math»
Using the power rule, the derivative is as follows.
«math style=¨font-family:Verdana¨ xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mstyle mathsize=¨14px¨»«mi»y«/mi»«mo»=«/mo»«msup»«mi»x«/mi»«mn mathcolor=¨#FF0000¨»1«/mn»«/msup»«/mstyle»«/math»
Move the exponent in front of the function. Subtract «math style=¨font-family:Verdana¨ xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mstyle mathsize=¨14px¨»«mn»1«/mn»«/mstyle»«/math» from the exponent.
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«math style=¨font-family:Verdana¨ xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mstyle mathsize=¨14px¨»«mtable columnalign=¨right center left¨»«mtr»«mtd»«mfrac»«mrow»«mi»d«/mi»«mi»y«/mi»«/mrow»«mrow»«mi»d«/mi»«mi»x«/mi»«/mrow»«/mfrac»«/mtd»«mtd»«mo»=«/mo»«/mtd»«mtd»«mn
mathcolor=¨#FF0000¨»1«/mn»«msup»«mi»x«/mi»«mrow»«mn mathcolor=¨#FF0000¨»1«/mn»«mo mathcolor=¨#FF0000¨»§#8722;«/mo»«mn mathcolor=¨#FF0000¨»1«/mn»«/mrow»«/msup»«/mtd»«/mtr»«mtr»«mtd/»«mtd»«mo»=«/mo»«/mtd»«mtd»«msup»«mi»x«/mi»«mn»0«/mn»«/msup»«/mtd»«/mtr»«mtr»«mtd/»«mtd»«mo»=«/mo»«/mtd»«mtd»«mn»1«/mn»«/mtd»«/mtr»«/mtable»«/mstyle»«/math»
The zero exponent rule states «math style=¨font-family:Verdana¨ xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mstyle mathsize=¨14px¨»«mrow»«msup»«mi»x«/mi»«mn»0«/mn»«/msup»«mo»=«/mo»«mn»1«/mn»«/mrow»«/mstyle»«/math». |
As shown, using either method, the derivative of «math style=¨font-family:Verdana¨ xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mstyle mathsize=¨14px¨»«mrow»«mi»y«/mi»«mo»=«/mo»«mi»x«/mi»«/mrow»«/mstyle»«/math» is «math style=¨font-family:Verdana¨ xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mstyle mathsize=¨14px¨»«mn»1«/mn»«/mstyle»«/math».
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